Showing 19381 results for "MHTCET 2018 question paper"
Aircraft Maintenance Engineering Common Entrance Test A.M.E. CET) Details
The question paper consists of 90 multiple-choice questions (MCQ). A.M.E. CET question paper will be available in both Hindi and English language. This exam will be held in both online as well as offline modes. There is also a negative marking for incorrect answers. You will get 4 marks for correct answers and 1 mark for incorrect answers. We provide 40 offline centers for the entrance exam in pan India. You will get 1 hour 30 minutes to complete your exam (90 questions). Online and offline exams are held on the same day. A.M.E. CET 2022 exam will be held on the ... View more
Yes, this is enough. I had seen many student who got selected in JEE Mains after reading NCERT conceptually.
Hello Ashvini,The UGC NET was successfully held from 18th December to 22nd December and the result has been declared for the exam. The NTA conducted UGC NET exam in different cities. The UGC NET Dec Exam was held for 85 subjects and the cutoff marks for each exam is different. The NTA has released the result and cut off marks for the UGC NET December exam.
To check your result visit the official website and click on the View Result- UGC NET December Link. Insert your application number and date of birth, security pin and submit. Your result will appear on screen which you can download or take a print out for further use. As you did no... View more
Hello,
JEE Main Paper Cutoff for the last year was:
General - 81 marks
OBC - 49 Marks
SC - 32 Marls
ST- 27 Marks
This year the cutoff for JEE Main Exam is going to be slightly increased.
Hello,
Please visit this college predictor. This will help you to choose the best option for you-
<a href="https://www.shiksha.com/college-predictor" style='word-wrap:break-word;'>https://www.shiksha.com/college-predictor</a>
Thank you.
Hello R K, Solving UGC NET Question Papers will be the best strategy for you to crack this exam. Through this, you can boost up your confidence level and you can analyze your performance as well. Here I share a link from where you can get solved last years question papers of UGC NET Paper 1 - <a rel="nofollow" target="_blank" href="https://www.eduncle.com/free-downloads/ugc-net-exam" style='word-wrap:break-word;'>https://www.eduncle.com/free-downloads/ugc-net-exam</a> must check. Hope you will get the best out of it. All the Best!
Hello Goutam, National Eligibility Test (NET) is a national level exam meant for scrutinizing the expert of the knowledge required for holding the position of Lecturers/professors/ associates/ research fellows at India's reputed universities. Earlier CBSE conducted the NET exam but from December 2018 it is conducted by the National Testing Agency. UGC NET exam is conducted in approximately 81 subjects. To qualify the UGC NET exam, you have to crack NET exam which is divided into two parts I. e. Paper 1 and Paper 2. You have to score minimum marks in UGC NET which are as follow -
General Category Candidates 40 marks or 40% in Paper-I, ... View more
Carry all the drawing equipment. Go well through the last year papers. Train yourself well to solve the questions of Mathematics properly. Prepare well according to the syllabus. No need to panic, relax and give the exam because it's not very difficult.
The question paper is not difficult, but moderate. Just focus on your preparation and learn through the book which you used to study and you can also refer to Arihant book for quick revision. Simple question will be asked from every subject. Just keep your basics clear.
Please click below for question papers available on Shiksha. <a href="https://www.shiksha.com/university/soa-siksha-o-anusandhan-university/saat-exam-question-papers" style='word-wrap:break-word;'>https://www.shiksha.com/university/soa-siksha-o-anusandhan-university/saat-exam-question-papers</a>.
If you are from CBSE board, then the questions in NDA is not so tough and not so easy. But, you have too practice well
and you are from CBSE board then nothing to worry about the paper pattern and the questions.
You just concentrate on the practice and learning
So, good wishes for your exams.
<p>Hi, applicants who wish to enroll in a BTech programme must meet the prerequisites set forth by the universities. Applicants for the course may do so if they fulfill the eligibility requirements. The following are the standard requirements for admission to BTech institutes in Maharashtra:</p><ul><li>Candidates must have completed Physics, Chemistry, and Mathematics as core courses in Class 12 with at least a 60% aggregate from an accredited board (the pass rate may vary in various colleges)</li><li>Applicants must pass common entrance tests, such as the MHT CET, in order to be admitted.</li><... View more
<p>Check the common eligibility criteria for admission to BTech in colleges in Pune below:</p><ul><li>Candidates <strong>must have passed Class 12 with a minimum of 60% aggregate</strong> from a recognised board with PCM.</li></ul><p><strong>Also read:</strong> <a href="https://www.shiksha.com/engineering/articles/mht-cet-important-topics-chapter-wise-weightage-blogId-37847">MHT CET important Topics & Chapter Wise Weightage</a></p><p>Hope this helps~</p>
Hi,
Just go through this link and fill out the required details
College predictor in Shiksha
<a href="https://www.shiksha.com/college-predictor" style='word-wrap:break-word;'>https://www.shiksha.com/college-predictor</a>
Hello Saksham,
You scored a very good rank in JEE Mains paper 2. So, I think you can get good colleges in last rounds counselling. So, please visit to this link below to predict colleges based on your category and rank:-
<a href="https://www.shiksha.com/b-tech/resources/jee-mains-college-predictor" style='word-wrap:break-word;'>https://www.shiksha.com/b-tech/resources/jee-mains-college-predictor</a>
I hope I'm able to help you.
Hello,
Hope you are doing well. It's quite tough to get NIT with 1853 OBC rank but there is a possibility you will get it because the ranks of NITs limits to 2000.
Hope for the best.
Do apply for B.Arch admission at NIT-Calicut.
All the best.
For a general candidate from another state, only spot round may get you to JMI.
Though the scenario may get easy for home state, Muslim, OBC and women students.
Still, you have got good marks, do not lose hope.
As per my knowledge, Manipal only accepts NATA score but you may enquire before making your mind.
You can use this link to find out which colleges you can get from these marks. This is Shiksha's official college predictor tool based on previous year’s data.
<a href="https://www.shiksha.com/architecture-planning/colleges/b-arch-colleges-india" style='word-wrap:break-word;'>https://www.shiksha.com/architecture-planning/colleges/b-arch-colleges-india</a>
Syllabus for CEE-2021 is given below-
Separate Questions will be administered for the following groups:
Group-A. B.Sc. B.Ed. Or B.A. B.Ed. Or M.Sc. B.Ed. Group-B
a. B.Ed. Group-C
a. M.Ed. Level of question paper will be as given below:
Group-A. The level of questions will be such as expected of the candidate completing higher secondary or senior secondary education
Group-B. The level of questions will be such as expected of the candidate completing graduation
Group-C. The level of questions will be such as expected of the candidate completing graduation and professional education level
For all the groups, ar... View more
Hi Sudhanshu, Please refer to syllabus for ICAR AIEEE from the link below:
<a href="https://www.shiksha.com/science/exams/icar-aieea/syllabus?q=ICAR+AIEEA&rf=searchwidget&landing=ep" style='word-wrap:break-word;'>https://www.shiksha.com/science/exams/icar-aieea/syllabus?q=ICAR+AIEEA&rf=searchwidget&landing=ep</a>.
You can get every entrance paper for Jamia Millia Islamia at this site: <a rel="nofollow" target="_blank" href="https://www.google.co.in/url?sa=t&source=web&rct=j&url=https://www.jmientrance.com/&ved=2ahUKEwiEyJDE8KLiAhX07nMBHfSuCZIQFjANegQIBxAB&usg=AOvVaw2oPLDbVnrpZdNnSsTZyU5o" style='word-wrap:break-word;'>https://www.google.co.in/url?sa=t&source=web&rct=j&url=https://www.jmientrance.com/&ved=2ahUKEwiEyJDE8KLiAhX07nMBHfSuCZIQFjANegQIBxAB&usg=AOvVaw2oPLDbVnrpZdNnSsTZyU5o</a>
You can also request more paper from them.