CSIR UGC NET 2024: Result (OUT), Final Answer Key (Released), Rank List & Cutoff

Council of Scientific and Industrial Research National Eligibility Test 2024 ( CSIR NET )

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Shikha Goyal

Shikha GoyalAssistant Manager

Updated on Sep 16, 2024 15:10 IST

CSIR NET 2024: The NTA is expected to release the CSIR NET 2024 Cutoff soon on the official website at csirnet.nta.ac.in. The CSIR NET 2024 result was declared on September 12, 2024. The CSIR NET 2024 final answer key was released on September 11, 2024. Candidates can download their CSIR NET 2024 result from the official website or via direct link provided below. The CSIR NET 2024 Provisional Answer Key was released on the official website, csirnet.nta.ac.in on August 9, 2024. It was released along with question papers and marked responses. The authority conducted the CSIR NET 2024 exam from July 25 to 27, 2024, in an online mode at various exam centres across the country.  

The NTA announced the CSIR NET New Exam Date 2024 for the June session on June 29, 2024. Earlier, the CSIR NET exam scheduled for June 25 to 27, 2024, was postponed due to logistical issues. There are five papers in the CSIR NET 2024 Exam – Mathematical Science, Life Science, Chemical Science, Earth Science, and Physical Science. Check below the important details regarding the CSIR NET exam such as dates, the application process, eligibility criteria, CSIR NET Exam Pattern, CSIR NET Syllabus 2024 and result preparation criteria.

Direct Link to check CSIR NET 2024 Result

CSIR NET 2024 News & Latest Updates:

Sep 16: CSIR NET 2024 Cutoff Soon; Check Last Year's Subject-Wise Cut off Here

Sep 12: CSIR NET 2024 Result Released @csirnet.nta.ac.in; Check How to Download and More

Sep 11: CSIR NET 2024 Final Answer Key Released; Get Direct Download Link csirnet.nta.ac.in

 

 

Q:   Is CSIR NET Result 2024 released?

A:

Yes. CSIR NET Result 2024 has been announced by the National Testing Agency (NTA) on its official website. Candidates can check their results through the link provided below in this article. The CSIR NET 2024 Result is announced in online mode on the official website, in order to check the CSIR UGC NET Result 2024, candidates are required to log in to the official website with the required credentials. After the CSIR NET Result, the candidates who have qualified for the exam will be provided with the CSIR NET eligibility certificate and JRF Award Letters from NTA. Qualified candidates can further apply for the position of Assistant Professor in Indian colleges and universities.

 

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Q:   How many marks are required to qualify for the CSIR NET 2024 exam?

A:

To pass the CSIR NET 2024 exam, candidates are required to score a minimum of 33 percent in the general, EWS, and OBC categories and 25 percent in the SC, ST, and PwD categories, or both fellowship and Lectureship/Assistant Professor. 

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Q:   How many times is CSIR NET conducted in a year?

A:
CSIR NET is conducted twice a year in typically the months of June and December. Council of Scientific and Industrial Research CSIR NET (also known as CSIR UGC NET is a national-level exam conducted by the National Testing Agency to determine the eligibility of candidates for Junior Research Fellowship (JRF) and for Lectureship (LS)/ Assistant Professor in the universities and colleges of India. Candidates clearing the CSIR NET exam can become lecturers in the subject areas falling under the faculty of Science & Technology only.
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Q:   What are the benefits of qualifying CSIR NET?

A:
The benefits of qualifying for CSIR NET are mentioned below; 1- Get CSIR NET JRF fellowship/Ph.D. Fellowship: get a fellowship of INR 31,000 per month for a period of 2 years as JRF and followed by INR 35,000 per month fellowship for a period of 3 additional years. 2- Get opportunities to work in top Research Laboratories: Positions like Junior research fellowship, Senior research fellowship, Project Associate, Research Associate, Project fellow, and Senior Project fellow are available, which you can apply for. Salaries carry as per the project and the Institute Norms. It ranges from INR 15,000 to INR 45,000 per month on average, which increases with experienced and position upgrades. 3- Get Public Sector job opportunities after qualifying for the CSIR NET exam/PSU job opportunities after qualifying for the CSIR NET exam: Numerous Public sector companies like Indian Oil, Hindustan Petroleum, and ONGC, hire CSIR NET and GATE qualified every year for various post with on average salary from INR 40,000 to INR 80,000 per month. 4- Opportunities to join a top university as Assistant Professor/Lecture: In private institutes, the salary of an Assistant professor is INR 35,000 to INR 60,000 per month, and In government institutes/colleges, the salary of an Assistant professor is INR 70,000 to INR 1,20,000 per month. 5- CSIR NET qualification increases your CV Weightage/Helps in getting higher preferences in getting jobs. 6- Get an opportunity to work in any Foreign Lab, you may do a Ph.D. or post-Ph.D. 7- Increase the chance of getting a promotion. 8- Opportunity to become a book author/publisher book or chapter/become a scientific writer. 9- Get into Entrepreneurship/set up your own Research lab. 10- Get a job in Defence Research and Development organisation/DRDO lab: DRDO Lab list where Life Science candidates can get a job after clearing a CSIR NET Life Science exams are: 1- Defence Bio-Engineering and Electro Medical Laboratory (DEBEL). 2- Defence Food Research Laboratory (DFRL). 3- Defence Institute of Bio-Energy Research (DIBER) 4- Defence Institute of Psychology and Allied Science (DIPAS) 5- Defence Institute of Psychological Research (DIPR) 6- Defence Research Development Establishment (DRDE) 7- Defence Research Laboratory (DRL) 8- Institute of Nuclear Medicine and Allied Science (INMAS). For more details, you may visit the Shiksha CSIR NET exam page. (https://www.shiksha.com/exams/csir-net-exam). I hope this will help you.
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Q:   When was the CSIR NET Provisional Answer Key 2024 released?

A:

The CSIR NET Provisional Answer Key 2024 was released by the NTA on the official website on August 9, 2024. Candidates could download the CSIR NET 2024 answer key pdf from the official website. The answer key was released on the official website in a PDF format. The CSIR NET answer key contains the correct answers to all the questions asked in the exam. Candidates can use the answer key to estimate their score in the exam and get an idea of their performance. The answer key was made available for all the papers. 

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What is CSIR NET?

Council of Scientific and Industrial Research (CSIR) NET (also known as CSIR UGC NET) is a national-level exam conducted by the National Testing Agency (NTA) to determine the eligibility of candidates for Junior Research Fellowship (JRF) and for Lectureship (LS)/ Assistant Professor in the universities and colleges of India. Candidates clearing the CSIR NET exam can become lecturers in the subject areas falling under the faculty of Science & Technology only. It is also important for a candidate to check CSIR NET 2024 eligibility criteria before applying for it. Subjects for which CSIR UGC NET is conducted are mentioned below.

CSIR NET Subjects

CSIR NET Subject Codes

Chemical Sciences

701

Earth, Atmospheric, Ocean and Planetary Sciences

702

Life Sciences

703

Mathematical Sciences

704

Physical Sciences

705

 

Q:   Is it mandatory to appear for all three parts of the CSIR NET exam?

A:
No, it is not mandatory to appear for all three parts of the CSIR NET exam. The three parts of the exam are: Part A: This part consists of General Aptitude questions, which are common to all subjects. It is compulsory for all candidates to attempt this part. Part B: This part consists of subject-related multiple-choice questions (MCQs). The number of questions and the total marks for this part vary depending on the subject. Part C: This part consists of higher value questions, which are designed to test the candidates' knowledge of scientific concepts and their ability to analyze and apply them. This part also varies in terms of the number of questions and total marks for each subject. Candidates can choose to appear for only Part A and Part B, or for all three parts of the exam, depending on their preference. However, candidates who wish to be considered for the award of Junior Research Fellowship (JRF) must appear for all three parts of the exam and secure the minimum qualifying marks in each part as per the CSIR NET eligibility criteria. Candidates who qualify for Lectureship (LS) are not required to appear for Part C of the exam.
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Q:   Can I get my CSIR NET scores re-evaluated?

A:
No, the Council of Scientific and Industrial Research (CSIR) does not provide the facility for re-evaluation of CSIR NET scores. The results declared by CSIR are considered final, and no request for re-evaluation or rechecking of answer sheets is entertained. However, in case a candidate finds any discrepancy in their result or scorecard, they can apply for rechecking of their OMR sheets within a specified period of time after the declaration of results. The rechecking process involves verification of the OMR sheets for any calculation errors, omission of marks, or unchecked responses. Candidates can apply for rechecking by submitting a written request along with the requisite fee to the Examination Unit of CSIR. The fee for rechecking is non-refundable, and the decision of CSIR regarding the rechecking request is final and binding. It is important to note that the rechecking process is not a guarantee of a change in the result or score, and the scores may remain the same after rechecking. Therefore, candidates should carefully check their result and scorecard before applying for rechecking.
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Q:   If I meet the CSIR NET cut-off for my subject, what will happen next?

A:
If you meet the CSIR NET (Council of Scientific and Industrial Research National Eligibility Test) cut-off for your subject and category, you will be considered eligible for the next stage of the selection process. The selection process for CSIR NET usually comprises of a written exam, followed by an interview or document verification process. If you have qualified for JRF (Junior Research Fellowship), you will be eligible to receive a fellowship for a period of two years, which may be further extended based on your performance and other criteria. It is important to note that the award of JRF is subject to various conditions and eligibility criteria, which are specified by the CSIR. If you have qualified for lectureship, you will be eligible for the post of Assistant Professor in various colleges and universities in India. The eligibility criteria and other conditions for the post of Assistant Professor may vary depending on the institution.
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Q:   Is the CSIR NET cut-off same for all subjects?

A:
No, the CSIR NET (Council of Scientific and Industrial Research National Eligibility Test) cut-off is not the same for all subjects. The cut-off marks are determined separately for each subject based on the number of candidates appearing for the exam, the difficulty level of the exam, and other factors specific to that subject. The cut-off marks for JRF (Junior Research Fellowship) and lectureship may also differ for different subjects. Candidates who score equal to or above the cut-off marks for their respective subject and category are considered eligible for the next stage of the selection process.
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CSIR NET 2024 Exam Dates

Take a look at the table below for the complete schedule of CSIR NET 2024 exam

DatesPast Exam Dates

12 Sep '24

CSIR NET June Session Result 2024 Out

11 Sep '24

CSIR NET Final Answer Key 2024 Released

09 Aug '24 -

10 Aug '24

CSIR NET Provisional Answer Key 2024

CSIR NET 2024 Exam Highlights

Candidates can check the CSIR NET 2024 exam details in the table below:

Exam Features

Exam Particulars

Exam Name

CSIR NET (Council of Scientific and Industrial Research National Eligibility Test)

Conducting Body

National Testing Agency (NTA)

Exam Level

National

Exam Frequency

Twice a year

Mode of Exam

Online - CBT (Computer-Based Test)

Exam Fees

  • INR 1,100 for the General category
  • INR 550 for OBC
  • INR 275 for SC/ ST
  • INR 0 for PwD

Exam Duration

180 minutes

Exam Time

  • Shift 1 - 09:00 am to 12:00 noon
  • Shift 2 - 03:00 pm to 06:00 pm

No. of Papers and Total Marks

  • Paper 1: 200 marks
  • Paper 2: 200 marks

Total Questions

150 MCQs in each Paper

Marking Scheme

  • +2 for each correct answer
  • 0.25 mark deduction for each wrong answer

Language/Medium of Exam

English and Hindi

Exam Purpose

To determine the eligibility of candidates for Junior Research Fellowship (JRF) and for Lectureship (LS)/ Assistant Professor in the universities and colleges of India

No. of Test Cities

225

Official Website

csirnet.nta.ac.in

Also Read: CSIR NET Exam Analysis 2024

Q:   What is the difference between CSIR-NET, and UGC-NET?

A:
The difference between CSIR NET and UGC NET is 1- The exam Conducting body: CSIR NET Exam: Council of Scientific & Industrial Research (CSIR) UGC NET Exam: National Testing University (NTA) 2- Exam Subjects: The CSIR NET exam is conducted in 5 Science subjects, whereas the UGC NET is conducted for 84 subjects including Arts, Commerce, Computer Science and Application, Electronic Science, and Humanities including all languages. 3- Exam Pattern: UGC NET exam pattern: Paper 1: Total no of ques:50 and total marks: 100 Paper 2: Total no of ques:100 and total marks: 200 CSIR NET exam pattern: Part A: Total Marks-30; No. Of questions-20; 2 Marks for each correct question; 0.5 marks cut for every wrong answer. Part B: Total Marks-70; No. Of questions-25-50; 2-3.5 (subject-wise) Marks for each correct question; 0.5-0.875 (subject-wise) marks cut for every wrong answer. Part C: Total Marks-100; No. Of questions-35-70; 4-5 (subject-wise) Marks for each correct question; 1-1.32 (subject-wise) marks cut for every wrong answer. 4- Mode of Examination: CSIR NET is conducted offline whereas, the UGC NET exam will be conducted online (CBT). 5- Eligibility Criteria: For UGC NET Students must pass with a min of 55 percent marks (General category) and 50 percent marks (SC/ST/PwD) in Master's Degree or equivalent from universities/institutions recognised by UGC. For CSIR NET Students must pass with a min of 55 percent marks (General category) and 50 percent marks (SC/ST/PwD) in M.Sc. , BS-4 Years, Integrated BS-M, BE/B.Tech, MBBS B.Pharma. 6- Age limit: For UGC NET Upper Age Limit is 31 years for JRF whereas, CSIE NET Upper Age Limit is 28 years for JRF. There is no age limit for Assistant Professor for both the exams.
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Q:   How many sections are there in CSIR NET exam?

A:
The CSIR NET exam contains three sections- Part A, B and C. Part A contains generic questions and is common for all subjects. Part B and C contain subject-specific questions. The CSIR NET Part A consists of General Aptitude questions that assess the candidates teaching/research aptitude, reasoning ability, comprehension skills, divergent thinking and general awareness. The CSIR NET Part B and C consist of questions that are based on the subjects chosen by candidates from the following five subjects - Earth, Atmospheric, Ocean and Planetary Sciences, Chemical Sciences, Life Sciences, Mathematical Sciences and Physical Sciences.
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Q:   When will the CSIR NET 2024 exam for the June session be conducted?

A:

The National Testing Agency (NTA) will conduct the CSIR NET 2024 June session exam from July 25 to 27, 2024. The exam will be conducted for five papers, namely Mathematical Science, Life Science, Chemical Science, Earth Science and Physical Science. The CSIR NET City Intimation Slip 2024 has been re-released on July 17, 2024. The admit card is to be out soon.

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Q:   Is CSIR NET exam postponed for June 2024?

A:

The National Testing Agency released the new dates for the CSIR NET 2024 exam for the June session. Now, the CSIR NET 2024 June session exam will be conducted from July 25 to July 27, 2024. Earlier, it was held from June 25 to June 27, 2024. The exam will be Computer-Based Test. The National Testing Agency (NTA) conducts the Council of Scientific and Industrial Research National Eligibility Test (CSIR NET) twice a year on behalf of the Council of Science and Industrial Research (CSIR) under the Ministry of Science and Technology. The NTA has released the city slips for the CSIR NET 2024 June session. Candidates can download their city slips from the official website.

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CSIR NET Cut-Off 2024

The National Testing Agency (NTA) will announce the CSIR NET subject-wise Cut-off on the CSIR's official website. Candidates will be able to download the subject-wise CSIR NET Cut-Off through the official website- csirhrdg.res.in. The NTA will release the CSIR NET Subject-wise Cutoff in PDF format. The subject-wise cut-off for CSIR NET will be shared in this article. 

How to Check CSIR NET Cutoff 2024?

Candidates can follow the below-mentioned steps to check the cut-off for the CSIR UGC NET exam:

  • Visit the official website of CSIR - csirhrdg.res.in
  • Click on the 'Cut-off' link available under the News & Announcement section
  • Download and save the CSIR NET cutoff list

CSIR NET Previous Year's Cut-Off (December 2023 Session)

Candidates can check the CSIR NET December Cutoff in the table below. 

Junior Research Fellowship (NET)

Subject

UR (%)

EWS (%)

OBC (%)

SC (%)

ST (%)

PwD (%)

Chemical

Science

59.00

51.50

51.00

39.25

30.50

25.00

Earth

Science

62.63

56.97

56.61

46.31

44.61

25.10

Life

Science*

99.2136117

97.1787795

97.1787795

92.2447812

85.4189305

72.0188733

Mathematical

Science

54.875

47.625

47.125

36.00

29.625

26.125

Physical

Science

43.938

36.688

36.75

30.375

26.938

25.875

CSIR NET Lectureship/Assistant Professor (NET) Cut-off

In the table below, CSIR NET Cut-Off (December Session) has been mentioned for Lectureship/Assistant Professor (NET).

Lectureship/Assistant Professor (NET)

Subject

UR (%)

EWS (%)

OBC (%)

SC (%)

ST (%)

PwD (%)

Chemical

Science

53.10

46.35

45.90

35.325

27.45

25.00

Earth

Science

56.367

51.273

50.949

41.679

40.149

25.00

Life

Science*

98.0541384

94.9213612

94.9213612

88.5506398

80.5919359

72.0188733

Mathematical

Science

49.3875

42.8625

42.4125

32.40

26.6625

25.00

Physical

Science

39.5442

33.0192

33.075

27.3375

25.00

25.00

Q:   Where can I check the CSIR NET cut-off?

A:
The CSIR NET (Council of Scientific and Industrial Research National Eligibility Test) cut-off is usually released along with the announcement of the result. Candidates can check the cut-off marks on the official website of CSIR NET. To check the cut-off marks, candidates need to follow these steps: a) Go to the official website of CSIR NET (csirnet. nta. nic. in). b) Click on the link for the result and cut-off marks. c) Enter your registration number and password or date of birth to log in. d) The result and cut-off marks will be displayed on the screen. e) Check the cut-off marks for your category and compare them with your score to know whether you have qualified for the next stage of the selection process.
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Q:   How is CSIR NET cut-off determined?

A:
The CSIR NET (Council of Scientific and Industrial Research National Eligibility Test) cut-off is determined based on several factors, which include: A) Number of candidates appearing for the exam: The cut-off marks may be higher if a large number of candidates appear for the exam as there is a higher competition for limited seats. B) Difficulty level of the exam: The cut-off marks may be lower if the exam is relatively easier as more candidates may score higher marks. C) Number of available seats: The cut-off marks may be higher or lower depending on the number of available seats for JRF (Junior Research Fellowship) and lectureship. D) Category of the candidate: The cut-off marks are different for different categories of candidates such as General, OBC, SC, ST, and PwD. E) Previous year cut-off trends: The cut-off marks may be similar to or higher than the previous year's cut-off marks depending on the overall performance of the candidates. After considering the above factors, the Council of Scientific and Industrial Research (CSIR) determines the cut-off marks for CSIR NET. The cut-off marks are usually released along with the announcement of the result.
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Q:   Is CSIR NET cut-off released separately for JRF and lectureship?

A:
Yes, the CSIR NET (Council of Scientific and Industrial Research National Eligibility Test) cut-off is released separately for Junior Research Fellowship (JRF) and lectureship. The cut-off marks for JRF are usually higher than the cut-off marks for lectureship. Candidates who score equal to or above the JRF cut-off marks are considered eligible for the award of JRF, while candidates who score equal to or above the lectureship cut-off marks are considered eligible for the post of Assistant Professor. The cut-off marks are different for different categories of candidates such as General, OBC, SC, ST, and PwD. The cut-off marks are usually released along with the announcement of the result.
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CSIR NET Result 2024 OUT

The CSIR UGC NET Result 2024 has been published by the NTA on its official website after successfully conducting the CSIR NET June 2024 exam. Candidates can check their results through the link provided below in this article. 

How to Check CSIR NET Result 2024?

Candidates can check CSIR UGC NET Result 2024 by following the steps mentioned below:

  • Step 1: Visit the official website of CSIR NET- csirnet.nta.ac.in
  • Step 2: Click on the 'Joint CSIR UGC NET June 2024 Score Card' link
  • Step 3: Enter the following details:
    • Application number
    • Date of birth
    • Security pin as shown in the image
  • Step 4: Click on Submit
  • Step 5: View and download the CSIR NET Result and scorecard

Check CSIR NET Result 2024: https://csirnet.ntaonline.in/frontend/web/scorecard/index

CSIR NET 2024 Result PDF: Click Here 

Q:   What details are mentioned on the CSIR NET scorecard?

A:
The CSIR NET scorecard contains the following details: Name of the candidate Roll number Registration number Date of birth Category Subject Total marks obtained in both Paper I and Paper II Rank Percentile score Qualifying status for JRF and/or Lectureship Cut-off marks for JRF and Lectureship Photograph and signature of the candidate Candidates should carefully check all the details mentioned on the scorecard and ensure that they are correct. In case of any discrepancy, candidates should immediately contact the CSIR authorities for rectification. It is important to note that the CSIR NET scorecard is a crucial document that candidates must keep safely for future reference. The scorecard is required during the fellowship application process and for any further correspondence with CSIR. Candidates are advised to keep multiple copies of the scorecard in a secure place.
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Q:   What details are required to check CSIR UGC NET result?

A:
To check the CSIR UGC NET result, candidates need to have the following details: Roll number: Candidates must enter the roll number as mentioned on their admit card. Date of birth: Candidates must enter their date of birth as mentioned on their application form. Exam center code: Candidates must enter the exam center code where they appeared for the exam. Once these details are entered correctly, candidates can access their CSIR UGC NET result. The result will display the candidate's name, roll number, rank, and the marks obtained in both Paper I and Paper II. The result will also indicate whether the candidate has qualified for Junior Research Fellowship (JRF) or Lectureship (LS) or both. It is important to note that the CSIR UGC NET result is declared online on the official website of CSIR, and candidates are not sent any hard copy of the result. Therefore, candidates are advised to keep a copy of the result for future reference.
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CSIR NET Final Answer Key 2024 OUT

The NTA released the CSIR NET Final Answer Key 2024 on the offiial website. Earlier, NTA reelased the CSIR NET 2024 provisional answer key. Candidates can follow the below-mentioned steps to check the answer key for the CSIR UGC NET exam:

  • Visit the official website of CSIR UGC NET- csirnet.nta.ac.in
  • For the CSIR UGC NET June 2024 answer key, go to the link given
  • A new login window for the CSIR UGC NET Response Key 2024 will appear
  • Enter the CSIR NET June exam login details, which include your application number and date of birth/password
  • After submitting the details on the screen, the CSIR UGC NET 2024 answer key will be shown
  • Save it to your device for future use

Check CSIR NET 2024 Final Answer Key: Download PDF Here 

 

 

Q:   How to calculate the score using the CSIR NET answer key?

A:
Candidates can calculate their score using the CSIR NET (Council of Scientific and Industrial Research National Eligibility Test) answer key by following the steps given below: Step 1: Download the answer key from the official website of CSIR NET. Step 2: Match your answers with the correct answers given in the answer key. Step 3: Count the number of correct answers and the number of incorrect answers. Step 4: Use the following formula to calculate the score: Score = (Number of Correct Answers x Marks per Question) - (Number of Incorrect Answers x Negative Marks per Question) The marking scheme for CSIR NET is as follows: Each correct answer carries a weightage of 2 marks. There is negative marking of 0.5 marks for each incorrect answer. After calculating the score, candidates can compare their score with the cutoff marks to get an idea of their chances of qualifying for the next stage of the selection process. It is important to note that the score calculated using the answer key is only an estimate and not the final score. The final score will be calculated based on the official result declared by the exam conducting authority.
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Q:   How much fee do I need to pay for challenging the CSIR NET Answer Key?

A:
You need to pay INR 200 per question in online mode to challenge the CSIR NET answer key. Candidates can follow the steps mentioned below to challenge the answer key: Visit the official website of CSIR UGC NET Click on the answer key link Enter the application number, password/date of birth and security pin Click on the Sign In button Click on the link available for challenging the answer key Select the correct answer option ID for the question ID for which the challenge needs to be made Click on the Save Your Claims button. Upload the document that supports the claimed answer Click on Save Your Claims & Pay Fee button Pay INR 200 per question in online mode via credit card/debit card/internet banking.
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Q:   Why is the CSIR NET answer key important?

A:
The CSIR NET (Council of Scientific and Industrial Research National Eligibility Test) answer key is an important document for candidates who have appeared for the exam. It contains the correct answers to all the questions asked in the exam and is released by the exam conducting authority within a few days to a week after the exam is conducted. The answer key is important for the following reasons: A) Estimate Score: Candidates can use the answer key to estimate their score in the exam. By comparing their answers with the correct answers given in the answer key, candidates can get an idea of their performance in the exam and the marks they are likely to score. B) Verify Answers: Candidates can use the answer key to verify their answers and identify any mistakes they may have made while attempting the exam. This will help them to identify their weak areas and work on them to improve their performance in future exams. C) Raise Objections: Candidates can also raise objections against any incorrect answer given in the answer key. The exam conducting authority will consider the objections raised by the candidates and make the necessary corrections in the answer key, if required. D) Result Preparation: The final result of CSIR NET is based on the final answer key. Therefore, candidates can use the answer key to get an idea of their performance in the exam and their chances of qualifying for the next stage of the selection process.
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CSIR NET Exam Analysis 2024

The National Testing Agency (NTA) conducted the CSIR NET 2024 June exam on July 25, 26 and 27, 2024. The CSIR NET 2024 analysis subject-wise is provided below. Candidates should read the CSIR NET Exam Analysis carefully in order to know about the overall as well as the section-wise difficulty level of the CSIR NET Question Paper 2024. The CSIR NET Exam Analysis 2024 is based on the overall difficulty level of the question paper which may be either easy or moderate or difficult.

CSIR NET Section-Wise Analysis: Chemical Science (Shift 1) 

Candidates can check the CSIR NET Chemical Science Analysis for Shift 1 in the table below based on the students' review.

Part Name

Total MCQs

Total MCQs to be Attempted

Difficulty Level

Good Attempts

Part A

20

15

Moderate

10-12

Part B

40

35

Moderate

26-27

Part C

60

25

Moderate

18-19

Total

120

75

Moderate

58-62

Also Read: CSIR NET 2024 Chemical Science Question Paper Analysis

CSIR NET Section-Wise Analysis: Life Science (Shift 2)

Scroll down to know the CSIR NET Section-wise Analysis 2024 in the table below:

Part Name

Total MCQs

Total MCQs to be Attempted

Difficulty Level

Good Attempts

Part A

20

15

Easy to Moderate

10-12

Part B

50

35

Moderate

24-26

Part C

75

25

Moderate 

17-19

Total

145

75

Moderate

56-59

CSIR NET Section-Wise Analysis: Life Science (Shift 1)

Candidates can check CSIR NET Section-wise Analysis 2024 in the table below.

Part Name

Total MCQs

Total MCQs to be Attempted

Difficulty Level

Good Attempts

Part A

20

15

Moderate

7-8

Part B

50

35

Easy

20-25

Part C

75

25

Moderate to Difficult

13-15

Total

145

75

Moderate

45-48

CSIR NET Section-wise Exam Analysis 2024 (Earth Science)

Candidates can check CSIR NET Section-wise Analysis 2024 in the table below.

Earth Science Paper Difficulty Level Good Attempts
Part-A Easy to Moderate 10-11
Part-B Moderate 28-29
Part-C Moderate  19-20
Total Moderate 58-62

CSIR NET Section-wise Exam Analysis 2024 (Physical Science)

Candidates can check CSIR NET Section-wise Analysis 2024 in the table below.

Physical Science Paper Difficulty Level Good Attempts
Part-A Easy to Moderate 10-12
Part-B Moderate to Difficult 15-16
Part-C Easy 16-17
Total Moderate 43-45

CSIR NET Section-Wise Analysis: Mathematial Science

Candidates can check the CSIR NET Mathematical Science Analysis in the table below based on the students' review.

Part Name

Total MCQs

Total MCQs to be Attempted

Difficulty Level

Good Attempts

Part A

20

15

Easy to Moderate

10-11

Part B

40

25

Moderate to Difficult

18-19

Part C

60

20

Moderate to Difficult

12-14

Total

120

60

Moderate to Difficult

48-50

Candidates can watch the CSIR NET Student's Reaction video below.

 

Q:   Who sets CSIR NET question paper?

A:
The Council of Scientific and Industrial Research (CSIR) Sets the CSIR NET (National Eligibility Test) question paper. CSIR is a premier scientific research organisation in India, and it conducts the CSIR NET exam to determine the eligibility of candidates for the award of Junior Research Fellowship (JRF) and for appointment as Lecturers in various scientific disciplines. The CSIR NET question paper is designed by subject matter experts and scientists from different fields to assess the knowledge and understanding of the candidates in their respective disciplines.
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Q:   How many questions are there in each part of the CSIR NET exam?

A:
The number of questions in each part of the CSIR NET (Council of Scientific and Industrial Research National Eligibility Test) exam varies depending on the subject. For subjects such as Life Sciences, Chemical Sciences, Earth Sciences, and Mathematical Sciences, Part A comprises 20 questions, Part B comprises 40 questions, and Part C comprises 60 questions. For subjects such as Physical Sciences, Part A comprises 20 questions, Part B comprises 25 questions, and Part C comprises 30 questions. It's important to note that each question carries a specific weightage, which is mentioned in the question paper. Part A carries 20 marks (each question carrying 1 mark), Part B carries 40 marks (each question carrying 2 marks), and Part C carries 120 marks (each question carrying 2 or 4 marks). Therefore, it's essential to attempt all the questions carefully, as each question carries a certain weightage, and a wrong answer can lead to negative marking.
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Q:   Is there any set pattern of distribution of questions in the CSIR NET exam?

A:
Yes, there is a set pattern of distribution of questions in the CSIR NET exam. The exam pattern may vary slightly depending on the subject, but generally, the distribution of questions is as follows: 1. Part A: This section is common for all subjects and consists of multiple-choice questions (MCQs). It contains 20 questions, and candidates are required to attempt 15 questions. Each question carries two marks, and there is negative marking for incorrect answers. 2. Part B: This section consists of subject-specific multiple-choice questions. The number of questions in Part B may vary depending on the subject. Each question carries two marks, and there is negative marking for incorrect responses. 3. Part C: This section contains higher-value questions that assess the candidate's analytical and problem-solving skills. The number of questions in Part C may vary depending on the subject, but it generally has a lower number of questions compared to Parts A and B. Each question in Part C carries four or five marks. The total duration of the exam is three hours, and candidates must complete all the sections within this timeframe. It is important for candidates to be familiar with the exam pattern and distribution of questions in their chosen subject to plan their time and preparation effectively.
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Q:   What were the good attempts section-wise for the CSIR NET 2024 Life Science exam?

A:

Candidates can check below the CSIR NET 2024 good attempts as per the students review for both shifts:

CSIR NET Section-Wise Analysis: Life Science (Shift 1)

Part Name

Total MCQs

Total MCQs to be Attempted

Difficulty Level

Good Attempts

Part A

20

15

Moderate

7-8

Part B

50

35

Easy

20-25

Part C

75

25

Moderate to Difficult

13-15

Total

145

75

Moderate

45-48

 

CSIR NET Section-Wise Analysis: Life Science (Shift 2)

Part Name

Total MCQs

Total MCQs to be Attempted

Difficulty Level

Good Attempts

Part A

20

15

Easy to Moderate

10-12

Part B

50

35

Moderate

24-26

Part C

75

25

Moderate 

17-19

Total

145

75

Moderate

56-59

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CSIR NET Topper Interviews

Go through topper interviews for the CSIR NET preparation.  

CSIR UGC NET Toppers

Preparation Strategy and How They Cracked It

Bhanu Pratap Singh

Subject: Physical Science

  • Followed a proper routine
  • Focused on clearing basics for each topic
  • Attempted a series of practice/ mock tests

Bilal Ahmed

Subject: Life Science

  • Kept pace with both Paper 1 and Paper 2
  • Prepared from multiple books containing facts  
  • Revised each topic multiple times

CSIR NET Certificate 2024

The Council of Scientific and Industrial Research (CSIR) issued CSIR NET Certificate 2024 for the CSIR NET exam for December 2023 session, to the candidates who qualified for the CSIR NET exam. The applicants who passed the exam and become eligible for JRF and lectureship are given CSIR NET Certificate.

Steps to Download the CSIR NET Certificate 2024

  • Step 1: Visit the official website
  • Step 2: Click 'Joint CSIR UGC NET', enter the captcha code and submit
  • Step 3: Enter your Roll number and Date of Birth
  • Step 4: Download and Save the PDF

Read More:

CSIR NET Admit Card 2024 RELEASED

CSIR NET Admit Card 2024 was released by the National Testing Agency (NTA) on the official website. Candidates can download the CSIR NET 2024 Admit Card from the official website. The admit card contains the various details of the examination like the examination centre, exam date, time of examination, etc. Candidates can download the admit card by following the steps below.

  • Step 1: Visit the official website- csirnet.nta.ac.in
  • Step 2: Click on the CSIR-UGC NET Admit Card 2024 link on the homepage of the website
  • Step 3: A new webpage will open. Candidates should enter the required details to download the admit card
  • Step 4: If everything is done perfectly, the candidate’s admit card will be displayed on the screen
  • Step 5: Download the admit card and print it out for future use

CSIR UGC NET Admit Card 2024 Download Link- https://csirnet.ntaonline.in/frontend/web/admitcard/admit-card-july2024

 

Q:   I am unable to download my CSIR NET admit card from the official website. What should I do?

A:
If you are unable to download your CSIR NET admit card from the official website, you can follow the steps given below: 1. Check your internet connection and make sure it is stable. 2. Try using a different browser or device to download the admit card. 3. Clear your browser cache and cookies, and try again. 4. Check if the admit card download link is active on the official website. 5. Sometimes, the link may be temporarily down due to technical issues. 6. Contact the CSIR officials or the examination conducting authority for assistance. If the above steps do not work, you should contact the CSIR officials or the examination conducting authority for further assistance. You can provide your registration details such as application number, name, date of birth, etc. , and explain the issue you are facing in downloading the admit card. They may provide you with further instructions or assistance in downloading the admit card.
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Q:   I have lost my CSIR NET admit card. What should I do?

A:
You need to log in to your registered account on the official website of the CSIR NET exam and get another printout of the admit card. Candidates can download their CSIR NET Admit Card by logging in to the official website. Candidates can follow the below-mentioned steps to download the admit card for the CSIR UGC NET exam: Step 1: Visit the official website of NTA Step 2: Click on the 'Download Admit Card' link Step 3: Enter the application number, date of birth and security code (as shown in the image) Step 4: Click on the Login button Step 5: Click on the Download Admit Card button Step 6: Download, save and print the CSIR NET admit card.
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Q:   How to correct mistakes in my CSIR NET admit card?

A:
If candidates find any mistakes in your CSIR NET admit card, candidate should promptly contact the CSIR officials or the exam conducting authority for rectification. Candidates can follow the steps given below to get the mistakes in the admit card corrected: Visit the official website of CSIR NET. Find the contact details for the examination conducting authority. Contact the authority via phone or email and explain the mistake in your admit card. Provide your correct details and any supporting documents, if required. Request them to correct the mistake and issue a corrected admit card. It is important to note that you should contact the CSIR officials as soon as possible to ensure that your corrected admit card is issued before the exam date.
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Q:   When will CSIR NET Admit Card 2024 be released?

A:

The CSIR NET Admit Card 2024 was released for June session by the National Testing Agency (NTA) on the official website. Candidates can download the CSIR NET admit card from the official website through logging in with required credentials. The admit card contains the various details of the examination like the examination centre, exam date, time of examination, etc. Candidates appearing for the exam are supposed to carry their CSIR NET Admit Card 2024 to the exam centre along with an original photo ID proof. The CSIR NET 2024 Admit Card is a mandatory document to be carried to the allotted exam centre. Candidates not having their admit card on the day of the exam might not be allowed to take the paper.

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CSIR NET City Intimation Slip 2024

CSIR NET City Intimation Slip 2024 released by the National Testing Agency (NTA) onthe official website. Candidates will be able to download their CSIR NET City Intimation Slip 2024 by logging into the official website by following the given below steps:

  • Visit the official website - csirnet.nta.ac.in
  • Click on the link stating ‘Download CSIR UGC NET Exam City Intimation Slip’
  • Enter the application number and date of birth
  • Check your exam city under the ‘City of Examination’ column
  • Take a printout

CSIR NET City Intimation Slip 2024 Download Link- https://csirnet.ntaonline.in/frontend/web/advancecityintimationslip/index

 

Q:   Has the authority re-released the CSIR NET 2024 City Intimation Slip?

A:

Yes. The NTA re-released the CSIR NET 2024 June session Advance City Intimation Slip on its official website. Candidates can download it through their login credentials. Along with the city slip, the authority also released the CSIR NET 2024 exam schedule and shift timings. Candidates can check in detail here on this page.

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CSIR NET New Exam Date 2024 OUT

The National Testing Agency (NTA) released the CSIR NET new Exam Date 2024. The exam date was rescheduled. Earlier, the CSIR NET 2024 exam was conducted from June 25 to 27, 2024. Now, the exam-conducting authority will conduct the CSIR UGC NET 2024 exam on July 25, 26, and 27, 2024. The CSIR NET 2024 exam was postponed due to some logistical challenges. It will be conducted as a Computer-Based Test. The CSIR NET Admit Card 2024 will be issued three days before the exam date on the official website.

CSIR NET Revised Exam Schedule 2024

CSIR NET Exam Date 2024 was announced for June Session by the Human Resource Development Group, a part of CSIR on the official website. CSIR NET Exam Date highlights the important events related to the CSIR NET 2024 exam such as the release of the CSIR NET Application Form, release of admit card, conduct of the exam, declaration of result, etc. Candidates should be aware of the latest CSIR NET Exam Date so that they do not miss out on any important event. 

CSIR NET Syllabus 2024

CSIR NET Syllabus 2024 for all five subjects, namely Earth, Atmospheric, Ocean and Planetary Sciences, Chemical Sciences, Life Sciences, Mathematical Sciences, and Physical Sciences, is mentioned below.

CSIR NET Syllabus: Part A

  • Numerical Ability- Number and Simplification; Average; Quadratic Equations; Sequence and Series; Surd and Indices; Logarithms; Percentage; Profit and Loss; Simple Interest & Compound Interest; Partnership; LCM and HCF; Probability; Mensuration.
  • Reasoning- Series Formation; Ranking and Arrangement; Puzzles; Coding-Decoding; Distance and Directions; Calendar and Clock, etc.
  • Data Interpretation and Graphical Analysis- Mean, Median & Mode; Measures of Dispersion; Graphical Analysis: Bar Graph, Line Graph; Pie-Chart; Tabulation.

CSIR NET Syllabus: Part B & C

A detailed CSIR NET Syllabus will help the students score better in the exam and present better clarity of the topics to be covered.

  • Chemical Sciences- Inorganic Chemistry, Physical Chemistry, Organic Chemistry, Interdisciplinary topics, etc.
  • Earth Sciences- Geology, Applied Geology, Physical Geography, Geophysics, Meteorology, Ocean Sciences, etc.
  • Life Sciences- Molecules and their Interaction, Cellular Organization, Developmental Biology, Diversity of Life Forms, Cell Communication and Cell Signaling, Ecological Principles, etc.
  • Mathematical Sciences- Analysis Linear Algebra, Complex Analysis Algebra, Topology, Ordinary Differential Equations (ODEs), Partial Differential Equations (PDEs), Numerical Analysis, Calculus of Variations, Linear Integral Equations, Classical Mechanics, Statistics, Exploratory Data Analysis, etc.
  • Physical Sciences- Mathematical Methods of Physics, Classical Mechanics, Electromagnetic Theory, Quantum Mechanics, Thermodynamic and Statistical Physics, Electronics and Experimental Methods, Atomic and Molecular Physics, Condensed Matter Physics, Nuclear and Particle Physics, etc.

CSIR NET Exam Pattern 2024

The CSIR NET Question Paper 2024 is divided into three sections- Part A, B and C.

Part 'A' shall be common to all subjects. This part shall be a test containing a maximum of 20 questions of General Aptitude. The candidates shall be required to answer any 15 questions for two marks each. The total marks allocated to this section shall be 30 out of 200.

The CSIR NET Part A consists of General Aptitude questions that assess the candidates’ teaching/research aptitude, reasoning ability, comprehension skills, divergent thinking and general awareness.

The CSIR NET Part B and C consist of questions that are based on the subjects chosen by candidates from the following five subjects - Earth, Atmospheric, Ocean and Planetary Sciences, Chemical Sciences, Life Sciences, Mathematical Sciences and Physical Sciences.

CSIR NET 2024: Exam Pattern for Life Sciences

Take a look at the detailed CSIR NET Exam Pattern 2024 below.

Particulars

Part A

Part B

Part C

Total

Total Questions

20

50

75

145

Max no of questions to attempt

15

35

25

75

Marks for each correct answer

2

2

4

200

Negative marking of 25 per cent in Part A, B & C

0.5

0.5

1

-

CSIR NET 2024: Exam Pattern for Chemical Sciences

Take a look at the detailed structure below.

Particulars

Part A

Part B

Part C

Total

Total Questions

20

40

60

120

Max no of questions to attempt

15

35

25

75

Marks for each correct answer

2

2

4

200

Negative marking of 25 per cent

0.5

0.5

1

-

CSIR NET 2024: Exam Pattern for Earth, Atmospheric, Ocean and Planetary Sciences

Take a look at the detailed structure below.

Particulars

Part A

Part B

Part C

Total

Total Questions

20

50

80

150

Max no of questions to attempt

15

35

25

75

Marks for each correct answer

2

2

4

200

Negative marking- 25 per cent in Part A & B and 33 per cent in Part C

0.5

0.5

1.32

-

CSIR NET 2024: Exam Pattern for Mathematical Sciences

Take a look at the detailed structure below.

Particulars

Part A

Part B

Part C

Total

Total Questions

20

40

60

120

Max no of questions to attempt

15

25

20

60

Marks for each correct answer

2

3

4.75

200

Negative marking in Part A & B of 25 per cent and no negative marking in Part C

0.5

0.75

0

-

CSIR NET 2024: Exam Pattern for Physical Sciences

Take a look at the detailed structure below.

Particulars

Part A

Part B

Part C

Total

Total Questions

20

25

30

75

Max no of questions to attempt

15

20

20

55

Marks for each correct answer

2

3.5

5

200

Negative marking of 25%

0.5

0.875

1.25

-

Note: There is a negative marking in the CSIR NET Exam. One-fourth mark of the question will be deducted for incorrect answers.

Q:   How many attempts are allowed in CSIR NET exam?

A:
There is no limit on the number of attempts for the CSIR NET (Council of Scientific and Industrial Research National Eligibility Test) exam. A candidate can appear for the exam as many times as they wish, provided they fulfill the eligibility criteria. However, it's important to note that the validity of the CSIR NET scorecard is only for two years from the date of the result declaration. Therefore, if a candidate wants to use their CSIR NET score for the purpose of Junior Research Fellowship (JRF) or lectureship, they must apply for these positions within the validity period of the scorecard. It's also important to note that the CSIR NET exam is conducted twice a year, usually in June and December. Therefore, the candidates have two opportunities each year to appear for the exam and improve their score.
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Q:   How many marks are allotted for a correct answer in the CSIR NET exam?

A:
The marks allotted for a correct answer in the CSIR NET (Council of Scientific and Industrial Research National Eligibility Test) exam vary depending on the part and type of question. Part A comprises 20 questions, and each question carries 1 mark. Therefore, the total marks allotted for Part A is 20. Part B and Part C comprise subject-specific questions, and each question carries 2 or 4 marks. Part B comprises 40 questions, and the total marks allotted for this section is 80. Part C comprises 60 questions, and the total marks allotted for this section is 120. It's important to note that there is negative marking of 25 per cent marks (33 per cent in Part C of Earth Sciences paper) for each incorrect answer in Part B and Part C. Therefore, it's essential to attempt only those questions for which the candidate is confident about the correct answer. Overall, the CSIR NET exam is designed to test the candidate's knowledge, understanding, analytical ability, and problem-solving skills in their respective subject, and the marks allotted for each question reflect the difficulty level of the question.
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CSIR NET Preparation Tips 2024

Some beneficial CSIR NET 2024 preparation tips for the exam are as mentioned below:

  • Candidates are advised to go through the syllabus and exam pattern before commencing their preparation for the Exam
  • Candidates should try to solve a mock test for CSIR NET before starting preparation to check their level of preparation
  • Candidates should prepare a routing involving more focus on the Candidate’s weak topics and lesser on the strong topics
  • It is advisable to start with the basics and then move on to the advanced topics
  • Note-taking is also suggested for such topics which need constant revision
  • Revise each topic before starting a new one. It would enhance the retention capacity
  • Check out the CSIR NET previous year papers and the questions that have been asked
  • Look for the study material that suits you the most from a list of Books. No need to read all the books for the preparation

Q:   How do I prepare for the CSIR NET exam without coaching?

A:
CSIR NET exams are conducted twice a year, in June and December, allowing aspirants to gain eligibility for lectureships in Indian universities and colleges. Every year, many aspirants give this exam, so you must start your preparation as early as possible and manage your time well. Preparation tips: Go through the syllabus. Well, it is highly recommended that you follow the syllabus, as it assists you in planning your preparation efficiently. It will give you an understanding of the time needed to prepare the complete syllabus. Manage your time well. Follow the study plan strictly. Make proper notes for revision. Collect and solve the previous year's papers. Analyze the papers and sort them according to the subject. Set a time for revision. Exam Pattern of CSIR-NET: CSIR-NET is an online exam containing 200 objective-type questions worth 200 marks. The question paper is divided into 3 parts, which are A, B, and C. Each part includes a different number of questions. The total number of questions in the CSIR NET exam also varies depending on the subject for which the student is appearing. The whole time required to complete the exam is three hours. Candidates can visit the official websites for the Testbook to find study materials, daily, weekly, and monthly quizzes, previous year's question papers, mock tests, and more. I hope this will help you.
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Q:   How many papers are there in the CSIR NET Exam?

A:
There is only one paper in the CSIR NET exam. However, the question paper is divided into three parts- Part A, Part B and Part C. The CSIR NET Question Paper 2023 will be divided into three sections- Part A, B and C. Part 'A' shall be common to all subjects. This part shall be a test containing a maximum of 20 questions of General Aptitude. The candidates shall be required to answer any 15 questions for two marks each. The total marks allocated to this section shall be 30 out of 200. The CSIR NET Part B and C consist of questions that are based on the subjects chosen by candidates from the following five subjects - Earth, Atmospheric, Ocean and Planetary Sciences, Chemical Sciences, Life Sciences, Mathematical Sciences and Physical Sciences.
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Q:   Can I crack the CSIR NET exam in first attempt?

A:
Yes, it is possible to crack the CSIR NET (Council of Scientific and Industrial Research National Eligibility Test) exam in the first attempt with proper preparation and dedication. Many candidates have successfully cleared the exam in their first attempt. To increase your chances of success in the first attempt, you should start preparing early, create a comprehensive study plan, and focus on the important topics and concepts. Solve previous year question papers, take mock tests, and revise regularly to reinforce your understanding of the topics. It is also important to maintain a positive attitude, stay motivated, and avoid undue stress during the preparation period. Seek guidance from mentors, teachers, or other experts in your field to clarify your doubts and get advice on exam preparation.
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CSIR NET Best Books 2024

Candidates can check the subject-wise CSIR NET Best Books 2024 in the table below which can help candidates prepare for the exam. 

Subject Book Name Author/Publisher
Chemical Sciences UGC-CSIR JRF/ NET Chemical Sciences (Chemistry) Trueman’s
Earth Sciences Joint CSIR-UGC NET Earth, Atmospheric, Ocean, and Planetary Sciences R. Gupta’s
Life Sciences UGC CSIR NET/ SET (JRF & LS) Life Sciences Arihant
Mathematical Sciences CSIR-UGC NET/ SET (JRF & LS) Mathematical Sciences Khanna Publishers
Physical Science CSIR-UGC NET/ JRF/ SET Physical Sciences Upkar’s

CSIR NET Application Form 2024

CSIR NET Application Form 2024 was accepted by the NTA till May 27, 2024. Candidates can follow the given below steps to accurately fill out the CSIR NET June Application Form 2024.

  • At first, the candidates are required to register themselves online
  • Login with the credentials used during the registration process
  • Fill out the application form available with the application number & password shared on your email ID and phone number
  • Upload the scanned documents as per requirements. The instructions for the same will be available there
  • After submitting the form, pay the application fee through the online payment gateways available

CSIR NET Application Form 2024: How to Fill CSIR NET Apply Online Form?

Candidates can watch the video below where we have explained the step-by-step process of how to fill out CSIR NET Application Form 2024.

CSIR NET Apply Online 2024: Application Fees

Candidates need to pay CSIR NET Application Fee 2024 in online mode only in order to submit the CSIR UGC NET Form 2024. The category-wise CSIR NET application fee for CSIR NET 2024 is mentioned below.

Category

CSIR NET Application Fee 2024 (in INR)

General

1,150

OBC – Non-creamy layer

600

SC/ST/PwD

325

Also Read:

CSIR NET Exam Centre List 2024

CSIR NET Application Form Correction 2024

Q:   What is the application fee for CSIR NET exam?

A:

CSIR UGC NET application fee is INR 1,150 for the General category, INR 600 for the OBC-NCL category and INR 325 for SC/ST and PwD category candidates. Candidates can pay their requisite fees on online mode through netbanking/credit card/debit card/UPI. After submitting the application fee, your application form will be provisionally accepted by the NTA. If NTA founds any discrepancy in the application form, the candidature of the candidate will be rejected at any time-point of exam. Candidates whose application form has been submitted successfully can download their CSIR NET confirmation page. Candidates are advised to keep the confirmation page in a printed format for future purposes.

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Q:   How many candidates register for the CSIR NET exam every year?

A:

Over two Lacs candidates register for the CSIR UGC NET exam every year. In June 2023, a total of 2,74,027 candidates had registered while 1,99,890 aspirants appeared for the exam. Council of Scientific and Industrial Research CSIR NET (also known as CSIR UGC NET is a national-level exam conducted by the National Testing Agency NTA to determine the eligibility of candidates for Junior Research Fellowship (JRF) and for Lectureship (LS)/ Assistant Professor in the universities and colleges of India.

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Q:   What documents should I keep handy while filling the CSIR NET Application Form?

A:

While filling the CSIR NET application form, it's recommended to keep the following documents and information handy:

1. Scanned copy of your photography and signature in the specified format and size
2. Academic records such as mark sheets, certificates, and degree certificates
3. Category certificate (if applicable) for OBC/SC/ST/PwD candidates
4. Valid photos ID proof such as Aadhar Card, PAN Card, Voter ID, Passport, Driver's License, etc.
5. Details of your educational qualifications such as name of the board/university, year of passing, marks obtained, etc.
6. Email ID and mobile number for registration and future communication
7. Net banking/debit card/credit card details for payment of application fee

It's important to ensure that all the documents and information provided are accurate and up-to-date to avoid any issues during the application process.

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CSIR UGC NET Notification 2024

CSIR NET Notification 2024 for June session was released by the NTA on the official website on May 1, 2024. The notification contains the important details of the exam including the detailed application process, eligibility criteria, admit card, exam dates, exam pattern, syllabus, etc. The CSIR NET 2024 notification for June contains the following details:

  • Application process
  • Exam dates and schedule
  • CSIR NET 2024 eligibility criteria
  • CSIR NET exam pattern and syllabus
  • CSIR NET qualifying marks and cut-off criteria
  • Exam centres list
  • Admit card
  • Verification of eligibility

CSIR UGC NET Notification 2024 PDF (June Session)- Download_Here 

CSIR NET Notification 2024: Details Mentioned

The CSIR NET 2024 Notification contains important information related to the exam. The notification generally includes the following details:

  • Eligibility Criteria: The notification specifies the eligibility criteria that candidates must meet to be able to apply for the exam. This includes information related to age limit, educational qualifications, and other criteria.
  • Application Process: The notification provides details about the application process, including the mode of application, the application fee, and the documents required to be submitted.
  • Exam Pattern: The notification specifies the exam pattern, i.e., the structure and format of the exam, including the number of papers, the types of questions, the marking scheme, and the duration of the exam.
  • Syllabus: The notification provides the syllabus for the exam, which includes the topics and sub-topics that candidates need to study to prepare for the exam.
  • Important Dates: The notification provides important dates related to the exam, including the start and end dates of the application process, the CSIR NET Exam Date, the release of the admit card, and the announcement of results.
  • Admit Card: The notification provides information related to the availability of the admit card, which is a mandatory document required to appear for the exam.
  • Result: The notification provides information related to the announcement of the result, including the date of result declaration and the process to check the result.

Q:   Who releases the CSIR NET notification?

A:
The CSIR NET (Council of Scientific and Industrial Research National Eligibility Test) notification is released by the Council of Scientific and Industrial Research (CSIR) in India. CSIR is a premier national research and development organisation in India and it conducts the CSIR NET exam twice a year to determine the eligibility of candidates for Junior Research Fellowship (JRF) and/or appointment as Lecturer in Indian universities and colleges. The CSIR NET notification contains important information related to the exam such as eligibility criteria, application process, exam pattern, syllabus, and important dates. The notification is usually released on the official website of CSIR and interested candidates can apply online through the website.
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Q:   What information does CSIR NET notification contain?

A:
The CSIR NET (Council of Scientific and Industrial Research National Eligibility Test) notification contains important information related to the exam. The notification generally includes the following details: Eligibility Criteria: The notification specifies the eligibility criteria that candidates must meet to be able to apply for the exam. This includes information related to age limit, educational qualifications, and other criteria. Application Process: The notification provides details about the application process, including the mode of application, the application fee, and the documents required to be submitted. Exam Pattern: The notification specifies the exam pattern, I. e. , the structure and format of the exam, including the number of papers, the types of questions, the marking scheme, and the duration of the exam. Syllabus: The notification provides the syllabus for the exam, which includes the topics and sub-topics that candidates need to study to prepare for the exam. Important Dates: The notification provides important dates related to the exam, including the start and end dates of the application process, the date of the exam, the release of the admit card, and the announcement of results. Admit Card: The notification provides information related to the availability of the admit card, which is a mandatory document required to appear for the exam. Result: The notification provides information related to the announcement of the result, including the date of result declaration and the process to check the result.
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Q:   Does CSIR NET notification contain information about the job openings?

A:
No, the CSIR NET (Council of Scientific and Industrial Research National Eligibility Test) notification does not contain information about job openings. The purpose of the CSIR NET exam is to determine the eligibility of candidates for Junior Research Fellowship (JRF) and/or appointment as Lecturer in Indian universities and colleges. The exam is conducted to select eligible candidates for research positions in various fields of Science and technology. The CSIR NET notification contains information related to the exam, including eligibility criteria, application process, exam pattern, syllabus, and important dates. It is important for candidates to carefully read and understand the notification to be able to apply for the exam and prepare for it effectively.
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CSIR NET Eligibility Criteria 2024

The basic CSIR UGC NET Eligibility Criteria 2024 that candidates must fulfil are mentioned below:

CSIR NET Educational Qualification 2024

  • Candidates should have obtained a degree in BTech/BE/BPharma/MBBS/BS (four years)/Integrated BS-MS/MSc with a minimum of 55 per cent marks for General (UR)/General-EWS and OBC (50 per cent for SC/ST, Third gender and PwD) 

CSIR NET Age Limit 2024

  • To apply for CSIR NET JRF, candidates should be a maximum of 28 years of age. The upper age limit is relaxable for up to 5 years for SC/ST/Third gender/PwD/Females and up to 3 years for OBC (Non-Creamy Layer) 
  • There is no upper age limit to apply for the post of Lectureship (LS)/ Assistant Professor

Q:   What is the age limit for CSIR NET 2024 exam?

A:

The age limit for the CSIR NET (Council of Scientific and Industrial Research National Eligibility Test) exam is an important eligibility criterion that candidates must fulfill to be eligible to apply for the exam. The age limit for the JRF (Junior Research Fellowship) category is specified as 28 years as on the 1st of January of the exam year, i.e. , for the CSIR NET 2024 exam, the candidate must not have been born earlier than January 1, 1995. However, this age limit is subject to certain relaxations for candidates belonging to reserved categories such as SC/ST/OBC/PwD/Women. The relaxation in the age limit varies for different categories and is specified in the official notification.

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Q:   For which subjects is CSIR NET conducted?

A:
CSIR NET is conducted for five Science subjects including Chemical Sciences, Earth, Atmospheric, Ocean and Planetary Sciences, Life Sciences, Mathematical Sciences, and Physical Sciences. Council of Scientific and Industrial Research CSIR NET (also known as CSIR UGC NET is a national-level exam conducted by the National Testing Agency NTA to determine the eligibility of candidates for Junior Research Fellowship (JRF) and for Lectureship (LS)/ Assistant Professor in the universities and colleges of India.
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Q:   I am studying M.Sc. Applied mathematics. Am I eligible for computer Science in CSIR NET?

A:
According to the eligibility criteria for the CSIR NET exam, candidates must have a master's degree or its equivalent in the relevant subject with a minimum of 55% marks (50% for SC/ST/OBC-NCL/PwD candidates). Since you are pursuing an M.Sc. In Applied Mathematics, you may be eligible to appear for the CSIR NET exam in the Mathematical Sciences stream. However, if you want to appear for the CSIR NET exam in the Computer Science stream, you will need to have a master's degree or its equivalent in Computer Science or a related discipline such as Electronics & Communication Engineering, Information Science, or Information Technology with a minimum of 55% marks (50% for SC/ST/OBC-NCL/PwD candidates). Therefore, if you have completed your M.Sc. In Applied Mathematics and wish to appear for the CSIR NET exam in the Computer Science stream, you may need to pursue an additional qualification such as a Master's in Computer Science or a related field to meet the eligibility criteria.
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Q:   What is the eligibility criteria to apply for the CSIR-NET?

A:

The CSIR NET exam is conducted for the Junior Research Fellowship and for the Lectureship in Science and Technology subjects. The eligibility criteria for the CSIR NET are as follows:

(a) Academic criteria:

  1. The applicant must have a degree in any of the following: B.Tech, BE, B.Pharma MBBS B.Sc. (Hons. ), or M.Sc.
  2. Candidates with Bachelor's-level degrees, such as B.Tech, can only apply for JRFs and not lectureships.
  3. The applicant must have a minimum of 55 percent in their degree course. 

(b) Age criteria:

  1. The upper age limit for CSIR NET is 28 years for JRF, which is relaxed to 5 years for certain categories.
  2. If you want to apply for the position of assistant professor, there is no age limit.
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CSIR NET Recruitment Process 2024

The complete process for the CSIR NET Exam 2024 is explained below:

Stage One: Filling up the CSIR NET Application Form

In the first step, candidates need to fill out the CSIR NET Application Form and submit their application form online along with the payment of application fees.

Stage Two: CSIR NET Exam 2024

In the next step, CSIR NET 2024 Exam will be conducted in online mode for all the candidates who successfully submit their completely filled application forms before the last date.

Stage Three: Announcement of CSIR NET 2024 Result

The CSIR NET Result 2024 is declared in two categories-

  1. One merit list who qualifies for the award of Junior Research Fellowship (JRF-NET)
  2. The second merit list is for the candidates who qualify for the eligibility test for lectureship (LS-NET)

Stage Four: Interview

The next phase of the selection process is an interview. Qualified candidates, who will be shortlisted on the basis of the merit list will have to face personal interviews in different institutions, laboratories and University departments.

Stage Five: Award of Fellowship

Fellowship will be provided only to those candidates who are able to enrol for PhD in research institutes/ laboratories and Universities within two years of the declaration of the result of the CSIR UGC NET Exam.

Refer to the infographic below for the CSIR NET recruitment process:

CSIR NET Recruitment Process 2023

Q:   Is there a negative marking in the CSIR NET exam?

A:

Yes, there is a negative marking of 25 per cent in the CSIR NET exam for each wrong answer (33 per cent in Part C of Earth Sciences paper). Marking Scheme in CSIR NET 2024 exam varies with different stages of exam. Part A comprises 20 questions, and each question carries 1 mark. Therefore, the total marks allotted for Part A is 20. Part B and Part C comprise subject-specific questions, and each question carries 2 or 4 marks. Part B comprises 40 questions, and the total marks allotted for this section is 80. Part C comprises 60 questions, and the total marks allotted for this section is 120. It's important to note that the negative marking can significantly affect the final score, and the candidates should attempt the questions carefully and only answer those questions for which they are confident about the correct answer. Guesswork should be avoided as it may lead to negative marking and a reduction in the overall score.

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Q:   Can I get a government job after passing the CSIR NET JRF in life Science?

A:
There are many public sector organizations that offer a wide range of opportunities for talented people with good CSIR NET scores. Qualifying the CSIR NET with a good score is an advantage, as PSUs now have direct access to NET scores and can select qualified candidates based on their academic profiles. Government Job posts after clearing the CSIR NET JRF in life Science Are: Assistant Professor, Scientist, Sr. Associate Scientist, Biomedical Scientist, Clinical Research Associate, Microbiologist, Geneticist, Biology Content Developer, Biology Researcher, Biological Technician, Botanist, Conservationist, Ecologist, Environment Consultant, Farming Consultant, Forester, Horticulturist, Laboratory Technician, Molecular Biologist, Museum Educator, Mycologist, Natural Resources Manager, Nursery Manager, Plant Biochemist, Plant Explorer, Plant Researcher, Science Adviser, Taxonomist, Weed Scientist, Research Biochemist, Sr. Regulatory Affairs Associate, Biotechnology Researcher, Quality Controller, Regional Manager, Research Assistant, Food, Industrial or Environmental Microbiologists, Quality Assurance Technologists, Sales or Technical Representative, Clinical and Veterinary Microbiologists, Medical Technologists, Pharmacologist, Food Technologist, Scientific Laboratory Technician, Physician Associate, Research Scientist (life sciences), Educational Institutes, Plant Breeding Centers, Genetic Engineering Firms, Agriculture Departments, Biotechnology Companies, Crop Plantation Facilities, Agriculture Ministries, Research Laboratories, Agricultural Scientist, etc. Salary: The minimum average salary in PSUs varies from INR 40,000 per month to INR 70,000 per month, and it increases with your promotion.
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Q:   Is the CSIR NET exam lengthy?

A:
The length of the CSIR NET exam can vary depending on the subject and the paper you are appearing for. The CSIR NET exam consists of multiple-choice questions (MCQs) and is conducted in two sessions: Part A and Part B/C. Part A is common for all subjects and contains questions related to general Science, aptitude, and reasoning. Part A consists of 20 questions, and the candidates have to attempt 15 questions. Each question carries two marks, and there is negative marking for incorrect answers. Part B contains subject-specific multiple-choice questions, and the number of questions may vary from subject to subject. Part B carries two marks for each correct answer, and there is negative marking for incorrect responses. Part C consists of higher-value questions that test the candidate's knowledge in a particular subject. The questions in Part C are designed to assess the analytical skills and problem-solving ability of the candidates. The total duration of the exam is three hours, and the length of the exam can be considered moderate to lengthy, especially for subjects with a large syllabus. It requires a good amount of preparation and time management to answer all the questions within the given time frame.
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CSIR NET 2024 FAQs

Candidates can read CSIR NET 2024 FAQs below.

Q:   When will CSIR NET Admit Card 2024 be released?

A:

The CSIR NET Admit Card 2024 was released for June session by the National Testing Agency (NTA) on the official website. Candidates can download the CSIR NET admit card from the official website through logging in with required credentials. The admit card contains the various details of the examination like the examination centre, exam date, time of examination, etc. Candidates appearing for the exam are supposed to carry their CSIR NET Admit Card 2024 to the exam centre along with an original photo ID proof. The CSIR NET 2024 Admit Card is a mandatory document to be carried to the allotted exam centre. Candidates not having their admit card on the day of the exam might not be allowed to take the paper.

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Q:   When will the CSIR NET Application Form 2024 be released?

A:

CSIR NET Application Form 2024 will be released by the National Testing Agency (NTA) along with the notification tentatively in November 2024 for December session. Interested candidates will be able to fill out the CSIR NET 2024 Application Form by registering on the official website.

CSIR NET Application Form for June 2024 session was released by the NTA from May 1 to 27, 2024. The conduction of the CSIR NET 2024 exam is entrusted to the National Testing Agency (NTA) by the Council of Scientific and Industrial Research (CSIR) to determine the eligibility for Junior Research Fellowship (JRF) and Lectureship (LS) in Indian universities and colleges.

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CSIR NET Exam

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Answered Yesterday

To pass the CSIR NET 2024 Exam, candidates must score at least 33 percent in the general, EWS, and OBC categories and 25 percent in the SC, ST, and PwD categories. The CSIR NET 2024 result was released on September 12, 2024. The CSIR NET 2024 scorecard is available on the official website at csirne

...more

S

Shikha Goyal

Contributor-Level 10

Answered a month ago

Yes. The CSIR NET 2024 Final Answer Key has released on the official website at csirnet.nta.ac.in. The authority released the CSIR NET 2024 Provisional Answer Key on the official website. The CSIR NET Final Answer Key has been released after analysing the representations of the candidates.

S

Shikha Goyal

Contributor-Level 10

Answered a month ago

The NTA released the CSIR NET 2024 Provisional Answer Key on August 9, 2024. The duration of challenge the CSIR NET 2024 Answer Key is from August 9 to August 11, 2024. The last date for payment is August 11, 2024. 

S

Shikha Goyal

Contributor-Level 10

Answered a month ago

The authority released the CSIR NET 2024 Answer Key on the official website at csirnet.nta.ac.in. Candidates can access the CSIR NET 2024 Answer Key PDF from the official website or a direct link provided here. 

S

Shikha Goyal

Contributor-Level 10

Answered a month ago

The NTA conducted the CSIR NET 2024 Mathematical Science Exam 2024 on July 25 in shift 2 from 3 p.m. to 6 p.m. As per the student reactions, the overall difficulty level of the CSIR NET 2024 Mathematical Science exam was moderate to difficult. Topics asked in the exam with high-weightage are: 

  • Sequen

...more

S

Shikha Goyal

Contributor-Level 10

Answered a month ago

Candidates can check below the CSIR NET 2024 good attempts as per the students review for both shifts:

CSIR NET Section-Wise Analysis: Life Science (Shift 1)

Part Name

Total MCQs

Total MCQs to be Attempted

Difficulty Level

Good Attempts

Part A

20

15

Moderate

7-8

Part B

50

35

Easy

20-25

Part C

75

25

Moderate to Difficult

13-15

Total

145

75

Moderate

45-48

 

CSIR NET Section-Wise Analysis: Life Science (Shift 2)

Part Name

Total MCQs

Total MCQs to be Attempted

Difficulty Level

Good Attempts

Part A

20

15

Easy to Moderate

10-12

Part B

50

35

Moderate

24-26

Part C

75

25

Moderate 

17-19

Total

145

75

Moderate

56-59

S

Shikha Goyal

Contributor-Level 10

Answered a month ago

To pass the CSIR NET 2024 exam, candidates are required to score a minimum of 33 percent in the general, EWS, and OBC categories and 25 percent in the SC, ST, and PwD categories, or both fellowship and Lectureship/Assistant Professor. 

S

Shikha Goyal

Contributor-Level 10

Answered 2 months ago

The NTA released the CSIR NET 2024 Admit Card for June Session on the official website. Candidates can download the CSIR NET admit card from the official website by logging in with the required credentials. The CSIR NET 2024 Admit Card is a mandatory document to be carried by the candidate to the al

...more

S

Shikha Goyal

Contributor-Level 10

Answered 2 months ago

Yes. The NTA re-released the CSIR NET 2024 June session Advance City Intimation Slip on its official website. Candidates can download it through their login credentials. Along with the city slip, the authority also released the CSIR NET 2024 exam schedule and shift timings. Candidates can check in d

...more

S

Shikha Goyal

Contributor-Level 10

Answered 2 months ago

The National Testing Agency released the new dates for the CSIR NET 2024 exam for the June session. Now, the CSIR NET 2024 June session exam will be conducted from July 25 to July 27, 2024. Earlier, it was held from June 25 to June 27, 2024. The exam will be Computer-Based Test. The National Testi

...more

S

Shikha Goyal

Contributor-Level 10

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