Area Under Simple Curves

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a month ago

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R
Raj Pandey

Contributor-Level 9

Kindly consider the following Image

 

New answer posted

a month ago

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A
alok kumar singh

Contributor-Level 10

(ap-b)²+ (bp-c)²+ (cp-d)²=0 ⇒ p=b/a=c/b=d/c. a, b, c, d are in G.P.

New answer posted

a month ago

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R
Raj Pandey

Contributor-Level 9

{ (x, y) ∈ R*R, x ≥ 0, 2x² ≤ y ≤ 4 − 2x}.
Required area = ∫? ¹ (4 - 2x - 2x²)dx
= [4x - x² - (2/3)x³]? ¹ = 4-1-2/3 = 7/3

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a month ago

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V
Vishal Baghel

Contributor-Level 10

Area = ∫? ² (2? - logx)dx = [2? /ln2 - (xlnx-x)]? ²
= (4/ln2 - (2ln2-2) - (2/ln2 - (0-1) = 2/ln2 - 2ln2 + 1.
α=2, β=-2, γ=1.
(α+β-2γ)² = (2-2-2)² = 4.

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