Matrix

Get insights from 57 questions on Matrix, answered by students, alumni, and experts. You may also ask and answer any question you like about Matrix

Follow Ask Question
57

Questions

0

Discussions

8

Active Users

0

Followers

New answer posted

8 months ago

0 Follower 29 Views

A
alok kumar singh

Contributor-Level 10

A = [ x y z y z x z x y ] , | A | = 3 x y z ( x 3 + y 3 + z 3 ) = ( x + y + z ) [ ( x + y + z ) 2 3 ( x y + y z + z x ) ]

A2 = l

A. A' = l    (as A = A')

x 2 + y 2 + z 2 = 1 a n d x y + y z + z x = 0         

x 3 + y 3 + z 3 = 3 * 2 + 1 * ( 1 0 ) = 7             

New answer posted

8 months ago

0 Follower 11 Views

A
alok kumar singh

Contributor-Level 10

[ 0 t a n θ 2 t a n θ 2 0 ] , I 2 + A = [ 1 t a n θ 2 t a n θ 2 1 ] , I 2 A = [ 1 t a n θ 2 t a n θ 2 1 ]           

  ( I 2 + A ) ( I 2 A ) 1 = [ a b b a ]          

  a 2 + b 2 = | ( I 2 + A ) ( I 2 A ) 1 | = s e c 2 θ 2 * c o s 2 θ 2 = 1          

1 3 ( a 2 + b 2 ) = 1 3 * 1 = 1 3

New answer posted

8 months ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

  A = [ a i j ] 3 * 3 = [ a 1 1 a 1 2 a 1 3 a 2 1 a 2 2 a 2 3 a 3 1 a 3 2 a 3 3 ]             

a i 1 + a i 2 + a i 3 = 1 ; i = 1 , 2 , 3            

L e t X = [ 1 1 1 ] t h e m  

given [ a 1 1 a 1 2 a 1 3 a 2 1 a 2 2 a 2 3 a 3 1 a 3 2 a 3 3 ] [ 1 1 1 ] = [ 1 1 1 ]  

->AX = X .(i)

replace x by A x we have

A (AX) = AX

->A2X = AX = X .(ii)

Again replace X by AX

A3X = AX = X.

As  X = [ 1 1 1 ] , Sum of all entries in A3 = sum of entries in X = 1 +1 + 1 = 3

New answer posted

8 months ago

0 Follower 1 View

A
Aashi Madavi

Contributor-Level 8

The seat matrix includes reservation quotas for categories such as SC, ST, OBC-NVL, EWS, PwD and many more. Apart from this, the seats are allocated on the basis of NCC, sports, minority, and various other categories. Every category is allocated some percentage of the total seats to be eligible based on the quota or reservation.

New answer posted

8 months ago

0 Follower 1 View

A
Aashi Rastogi

Contributor-Level 10

The seat matrix guides seat allocation across various counselling rounds by indicating towards the vacant seats. This process ensures transparency and a fair admission, giving equal opportunity to everyone. In several cases, the vacant seat left by the end of the admission process is occupied on the basis of remaining quotas such as management.

New answer posted

8 months ago

0 Follower 1 View

M
Manisha Shukla

Contributor-Level 8

Seat matrix varies as per the type of institution, location, course, and applicable reservation policies. Every institute or university adheres to a different set of policies to conduct seat matrix. These policies vary in facilitating on the basis of quotas, and reservations. Furthermore, the institutes tend to offer Management quota to students based on the provided eligibility criteria.

New answer posted

8 months ago

0 Follower 2 Views

A
Aishwarya Sharma

Contributor-Level 8

The seat matrix is updated annually before every admission cycle to reflect necessary changes in seat availability, new courses, and reservation policies. The national level examination bodies such as MCC and JoSAA determine the seat matrix for the eligible students. Similarly, various state level counselling authorities designs the seat allocation matrix based on the state quotas and institute-specific admissions.

New answer posted

8 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

x + y + z = 4

3x + 2y + 5z = 3

9 x + 4 y + ( 2 8 + [ λ ] ) z = [ λ ]           

Δ = | 1 1 1 3 2 5 9 4 2 8 + [ λ ] | = 5 6 + 2 [ λ ] 2 0 ( 8 4 + 3 [ λ ] 4 5 ) + ( 6 )

= [ λ ] 9              

I f [ λ ] + 9 0 then unique solution

& if  [ λ ] + 9 = 0 t h e n Δ 1 = Δ 2 = Δ 3 = 0 so infinite solution will exist

Hence λ R  

New answer posted

8 months ago

0 Follower 6 Views

A
alok kumar singh

Contributor-Level 10

| A | = | [ x + 1 ] [ x + 2 ] [ x + 3 ] [ x ] [ x + 3 ] [ x + 3 ] [ x ] [ x + 2 ] [ x + 4 ] | = | [ x ] + 1 [ x ] + 2 [ x ] + 3 [ x ] [ x ] + 3 [ x ] + 3 [ x ] [ x ] + 2 [ x ] + 4 |

R 1 R 1 R 3 & R 2 R 2 R 3

| 1 0 1 0 1 1 [ x ] [ x ] + 2 [ x ] + 4 | = 1 9 2

[ x ] = 6 2

x [ 6 2 , 6 3 )              

 

New answer posted

8 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

A 2 = ( 1 0 0 0 1 1 1 0 0 ) ( 1 0 0 0 1 1 1 0 0 ) = ( 1 0 0 1 1 1 1 0 0 )

A 3 = ( 1 0 0 1 1 1 1 0 0 ) ( 1 0 0 0 1 1 1 0 0 ) = ( 1 0 0 2 1 1 1 0 0 )

A 2 0 2 5 A 2 0 2 0

= ( 1 0 0 2 0 2 4 1 1 1 0 0 ) ( 1 0 0 2 0 1 9 1 1 1 0 0 ) = ( 1 0 0 5 0 0 1 0 0 ) = A 6 A

Get authentic answers from experts, students and alumni that you won't find anywhere else

Sign Up on Shiksha

On Shiksha, get access to

  • 66k Colleges
  • 1.2k Exams
  • 688k Reviews
  • 1850k Answers

Share Your College Life Experience

×

This website uses Cookies and related technologies for the site to function correctly and securely, improve & personalise your browsing experience, analyse traffic, and support our marketing efforts and serve the Core Purpose. By continuing to browse the site, you agree to Privacy Policy and Cookie Policy.