COER University Roorkee Answered Questions

COER cut off for B.Tech is decided based on scores obtained in JEE Mains. The candidate must have passed in 10+2 and have scored of minimum of 50 % in there core subject such as physics chemistry mathematics. candidates cannot get direct admissions.

 You should have cleared 12th board or equivalent with 50% aggregrate also you should have passed in Physics, Mathematics and Chemistry as well. (For UG Admission)You should have passed your graduation from a recognised university with a 50% of aggregrate. (For PG admission)Accepting exams are JEE Mains, CUET, CAT, UKSEE, GATE, CUET-PG, JIPMER-PG

Candidates have to appear for the JEE-Mains for B.Tech and GATE/entrance examination conducted by the COER Roorkee for M.Tech, UKSEE for MCA and on the basis of marks obtained in the previous qualification for the other courses. Candidates must have cleared the JEE Main entrance exam with a valid score equivalent to the cutoff eligibility framed by COER.

Yes the minimum requirement is 50% in the core subjects or COER University and If you are willing to secure admission to the B.Tech course at COERU, you must have cleared the JEE Main entrance exam with a valid score equivalent to the cutoff eligibility framed by COER. This is the eligibility criteria to get through admissions in COER University.

No, if you are willing to secure admission to the BTech course at COERU, you must clear the JEE Main entrance exam with a valid score equivalent to the cutoff eligibility prescribed by COER. Students must have scored between 45% -50% in Class 12 core subjects. This is the basic eligibility criteria to get admission in COER University.