Chemistry Spl
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New answer posted
9 years ago
1 Follower
62 Views
Lalit BhandariIf I agreed with you, we'd both be wrong!
Scholar-Level 16
Hi Nishant,
Paraffins is a Latin word meaning (parum = little + affinis = reactivity). Alkanes are called paraffins because they have a little affinity towards a general reagent. In other words, alkanes are inert substances. They undergo reactions under drastic conditions.
All the best.
Paraffins is a Latin word meaning (parum = little + affinis = reactivity). Alkanes are called paraffins because they have a little affinity towards a general reagent. In other words, alkanes are inert substances. They undergo reactions under drastic conditions.
All the best.
New answer posted
9 years ago
0 Follower
549 Views
Lalit BhandariIf I agreed with you, we'd both be wrong!
Scholar-Level 16
Hi Manish,
In keeping track of how much chemistry is taking place in an electrochemical cell, we have a great advantage since we can direct and measure the exact amount of electric current that flows through the cell (thanks to the wonders of electrical measurement).
So, we need a means by which we can convert charge to numbers of electrons.
For this we use Faraday's Constant, \(F\). Faraday's Constant is given the symbol \(F\) and is defined as the charge in coulumbs (C) of 1 mole of electrons. Faraday's constant is approximately 96485 C mol-1. You can calculate \(F\) by multiplying the charge on one electron (1.602 x 10-19) by Avogadro'
In keeping track of how much chemistry is taking place in an electrochemical cell, we have a great advantage since we can direct and measure the exact amount of electric current that flows through the cell (thanks to the wonders of electrical measurement).
So, we need a means by which we can convert charge to numbers of electrons.
For this we use Faraday's Constant, \(F\). Faraday's Constant is given the symbol \(F\) and is defined as the charge in coulumbs (C) of 1 mole of electrons. Faraday's constant is approximately 96485 C mol-1. You can calculate \(F\) by multiplying the charge on one electron (1.602 x 10-19) by Avogadro'
...more
New answer posted
9 years ago
0 Follower
68 Views
arjun majheeinterest in agricultural research.
Contributor-Level 9
Hi,
Following are the best courses to pursue in M.Sc:
M.Sc in botany
M.Sc in zoology
M.Sc in biotech
M.Sc in chemistry
M.Sc in biochemistry
Universities offering these courses are Karnataka State University and MGU.
Following are the best courses to pursue in M.Sc:
M.Sc in botany
M.Sc in zoology
M.Sc in biotech
M.Sc in chemistry
M.Sc in biochemistry
Universities offering these courses are Karnataka State University and MGU.
New question posted
9 years ago
0 Follower
40 Views
New answer posted
9 years ago
3 Followers
566 Views
NITIN DESHMUKHYard by yard its hard, but inch by inch its
Scholar-Level 17
Yes, you can go for banking sector after B.Sc. Either you can go for IBPS-PO exam else you can go for MBA in BFSI from a top B-School like IIMs or MDI/SP Jain/TAPMI/IFMR/JBIMS known for finance.
New answer posted
9 years ago
1 Follower
131 Views
Vivek BansodeSCM Pro, MBA-Ops, B.Tech Engg
Guide-Level 12
All the three subjects are essential for any engineering course. However, now you can look ahead in specialization like mechanical, chemistry, IT, ECE, etc. Now, you need to analyze your strength according to these specialization not only on those three subjects.
New answer posted
9 years ago
0 Follower
144 Views
Divya JainStudent
Guide-Level 12
Hello Neha,
You can pursue:
1. B.Tech.
2. B.Sc.
3. BBA.
4. BCA.
5. B.Arch.
6. B.Pharmacy.
7. Diploma courses.
Best of luck.
You can pursue:
1. B.Tech.
2. B.Sc.
3. BBA.
4. BCA.
5. B.Arch.
6. B.Pharmacy.
7. Diploma courses.
Best of luck.
New question posted
9 years ago
0 Follower
53 Views
New answer posted
9 years ago
0 Follower
58 Views
Smriti Vats
Contributor-Level 10
Intermolecular forces (IMFs) are the forces which mediate interaction between molecules. They also include forces of attraction or repulsion which act between molecules and other types of neighboring particles (e.g., atoms or ions). They are weak compared to the intramolecular forces, the forces which keep a molecule together. For example, the covalent bond, involving the sharing of electron pairs between atoms, is much stronger than the forces present between neighboring molecules. Both sets of forces are essential parts of force fields frequently used in molecular mechanics.
New answer posted
9 years ago
7 Followers
2.5k Views
Gaurav SarodeFailure for me is just by-chance & surprising
Contributor-Level 8
If you study these subjects thoroughly, then you'll be able to crack the exam.
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