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New answer posted
11 months agoContributor-Level 10
11.65
The reaction given below is:
Benzene reacts with concern. H2SO4 and undergoes the following mechanism:-
Step 1: The equilibrium produces SO3 in concentrated H2SO4, as shown below:
Step 2: SO3 is the electrophile which reacts with benzene to form arenium ion, as shown below:
Step 3: A proton is removed from the arenium ion to form benzenesulfonate ion.
Step 4: The benzenesulfonate ion accepts a proton to become benzene-sulphonic acid, as shown below:
Step 5: The benzene sulphonic acid then reacts with NaOH to give phenol as the final product, as shown below:
New answer posted
11 months agoContributor-Level 10
11.64
Step 1:- Protonation of ethene to form carbocation by electrophilic attack of H3O+.
Step 2:- Nucleophilic attack of water on carbocation.
Step 3:- Deprotonation to form ethanol.
New answer posted
11 months agoContributor-Level 10
There are many ways to this conversion. Two of them are given below:-
11.63
(a) In the above conversion, the chlorobenzene is treated with a base such as NaOH, KOH etc. (strong base). The base abstracts the hydrogen from the C-2 position (it can also abstract the hydrogen from the C-6 position, as both are equally acidic) leaving the negative charge at that position.
In the next step Cl- leaves, leaving behind the positive charge at that carbon. Both the negative charge and positive charge forms a bond resulting Benzyne as the intermediate.
After the formation of the Benzyne intermediate OH- of the base attacks at the C-1 position and fur
New answer posted
11 months agoContributor-Level 10
11.62
The conversion of Phenol from Cumene requires the air oxidation of:
The air oxidation of cumene (isopropyl benzene) leads to the production of both phenol and acetone (costlier than phenol).
The air oxidation of cumene gives cumene hydro peroxide as an intermediate which on further hydrolysis (H3O+) gives phenol and acetone.
New answer posted
11 months agoContributor-Level 10
11.61
In ortho nitrophenol there is intra-molecular H bonding, whereas in para-nitrophenol there is inter-molecular H bonding, as shown below:
And because of that para-nitrophenol get tightly bounded with water and ortho nitrophenol is steam volatile and it will leave the solution.
New answer posted
11 months agoContributor-Level 10
11.60
The different forms of cresol is formed with given molecular formula:
2-methylphenol
3-methylphenol
4-methylphenol
New answer posted
11 months agoContributor-Level 10
11.58
The hydroboration-oxidation reaction is a two-step reaction that converts an alkene into a neutral alcohol by the net addition of water across the double bond. The hydrogen and hydroxyl group are added in a syn addition leading to the cis configuration. Hydroboration- oxidation is an anti-Markovnikov reaction, with the hydroxyl group attaching to the less substituted carbon. In first step Addition of Hydroborate group is done and in next step, it is oxidized by hydrogen peroxide.
For example: - When propene undergoes hydroboration-oxidation reaction, then it produces propan-1-ol as product. In this reaction diborane i.e., (BH3)2 re
New answer posted
11 months agoContributor-Level 10
11.57
Due to the presence of –OH group, alcohols form hydrogen-bonds with water but hydrocarbons cannot form hydrogen-bonds with water.
Due to inter moleculer hydrogen bonding between Alcohol and water molecular they remain tightly bounded to water molecules and have higher solubility. Whereas in case of hydrocarbon there is no chance of hydrogen bonding.
New answer posted
11 months agoContributor-Level 10
11.56
Here, propanol undergoes intermolecular H-bonding because of the presence of -OH group while butane has no such property
(intermolecular Hydrogen bonding in propanol)
Therefore, extra energy will be required to break those hydrogen bonds which in turn causes higher boiling point for propanol when compared to butane.
New answer posted
11 months agoContributor-Level 10
11.55
The structures of all isomeric alcohols of C5H12O are given below:
Naming is done by the conventional method. The -OH group is attached on the first carbon.
(b) 3-Methylbutan-1-ol
Butane is the longest chain and methyl is the substituent group.
(c) 3-Methylbutan-1-ol
the longest chain is butane and conventional naming method is used.
(d) 2,2-Dimethylpropan-1-ol
Isomer is made by transforming the principal carbon into tertiary type. The longest chain is butane and named accordingly.
(e) Pentan-2-ol
the longest chain is pentane and the numbering is chosen from the minimum position.
(f) 3-Methylbutan-2-ol
Butane is the longest chain,
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