Class 12th

The diameter of the dispersed particles is not much smaller than the wavelength of the light used. The intensity of scattered light depends on the difference between the refractive indice of the D.P and D.M., In lyophobic colloids, this difference is appreciable and therefore the tyndal effect is quite well defined but in lyophilic sols the difference is very small and the tyndal effect is very weak. So, to show Tyndall effect the refractive indices of the dispersed phase and dispersion medium differ greatly in magnitude.

Novestrol (Anti Fertility Drugs)

Novestrol has phenolic functional group, alcoholic functional group and Terminal alkyne.

Kindly consider the following Image 

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Kindly consider the following Image 

Glycerol can be separated from spent-lye in soap industry by using reduce pressure distillation technique.

Students can find the formula of integration for a particular function in this article. It is important to memorise these formulas to solve the integral problem easily. Below is the integration of a particular function formula.

The formula of a particular function:

1. Power Rule: 

$\int x^{n}dx=\frac{x^{n+1}}{n+1}+C(n\ne -1)$

2. Reciprocal Function:

$\int \frac{1}{x}dx=ln\left|x\right|+C$

3. Trigonometric Function: 

• $\int sinxdx=-cosx+C$
• $\int cosxdx=sinx+C$
• $\int {sec}^{2}xdx=tanx+C$
• $\int {csc}^{2}xdx=-cotx+C$
• $\int secxtanxdx=secx+C$
• $\int cscxcotxdx=-cscx+C$

4. Inverse Trigonometric Function

• $\int \frac{1}{1+x^2}dx={tan}^{-1}x+C$
• $\int \frac{1}{\sqrt{1-x^2}}dx={sin}^{-1}x+C$
• $\int \frac{-1}{\sqrt{1-x^2}}dx={cos}^{-1}x+C$

? 2 adj (3 A adj (2A)|
= 23.? 3 A adj (2A)|
|2
= 23 ⋅ (33)2 ⋅ | A|2 ⋅ |adj (2 A)|2
= 23 ⋅ 36 ⋅ | A|2 ⋅ (|2 A|2)2
= 23 ⋅ 36 ⋅ | A|2 [ (23)2 ⋅ | A|2]2
= 23. 36. |A|2. 212. |A|4
= 215. 36. |A|6
= 215 ⋅ 36 ⋅ 56 = 2? ⋅ 3? ⋅ 5?
? ? = 15? = 6? = 6
? +? +? = 27

Kindly go through the solution

A = [ x 1 ]
[ 1 0 ]
A² = [ x 1 ] [ x 1 ] = [ x²+1 x ]
[ 1 0 ] [ 1 0 ] [ x 1 ]
A? = [ x²+1 x ] [ x²+1 x ]
[ x 1 ] [ x 1 ]
= [ (x²+1)²+x² x (x²+1)+x ]
[ x (x²+1)+x²+1 ]
a? = (x² + 1)² + x² = 109
⇒ x = ±3
a? = x² + 1 = 10