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New answer posted
4 months agoContributor-Level 10
Dimension of charge: q = [AT]
Dimension of current I = [A]
Dimension of permeability μ? = [MLT? ²A? ²]
Dimension of momentum: [MLT? ¹]
Let P = q? μ? I? = [AT]? [MLT? ²A? ²]? [A]?
MLT? ¹ = M? L? T? ²? A? ²?
Comparing powers:
y = 1
x - 2y = -1 ⇒ x - 2 (1) = -1 ⇒ x = 1
x - 2y + z = 0 ⇒ 1 - 2 (1) + z = 0 ⇒ z = 1
Hence, the quantity is q¹μ? ¹I¹, or qμ? I.
New answer posted
4 months agoContributor-Level 10
This is a mnemonic method that computes the determinant of 3*3 times. It involves drawing diagonal lines for remembring how to multiply and sum elements of the matrix. Say there is a matrix:
| a b c |
| d e f |
| g h i |
We will first multiply the elements that are connected by three diagonals that run from top-left to bottom right:
a*e*i
b*f*g
c*d*h
Let us now sum these products: (aei)+ (bfg)+ (cdh)
Now, we will multiply the elements connected by three diagonals from top-right to bottom left:
c*e*g
b*d*i
a*f*h
Let us now sum these products:
(ceg)+ (bdi)+ (afh)
After this, let us subtract the sum of negative terms from the sum of positive terms:
Deter
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