Class 12th

Oxidation of toluene to benzaldehyde can be easily carried out with which of the following

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The reaction of H₂O₂ with potassium permanganate in acidic medium leads to the formation of mainly.

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$2 M n O_{4}^{-} + 6 H^{+} + 5 H_{2} O_{2} \to 2 M n^{2 +} + 8 H_{2} O + 5 O_{2}$

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The compound(s) that is (are) removed as slag during the extraction of copper is:

(A) CaO

(B) FeO

(C) Al₂O₃

(D) ZnO

(E) NiO

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Contributor-Level 10

Kindly go through the solution

$F e O + \underset{(A c i d i c f l u x)}{S i O_{2}} \to \underset{(S l a g)}{F e S i O_{3}}$

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The correct order of nucleophilicity is

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Nucleophilicity is directly proportional to the electron density of atom and inversely proportional to its electronegativity.

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The IUPAC nomenclature of an element with electronic configuration [Rn] 5f¹⁴6d¹7s² is:

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IUPAC nomenclature of element with atomic no. 103 is uniltrium.

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The major product in the following reaction

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Match the List-I with List-II

List-I	List-II
(A) N₂(g) + 3H₂(g) -> 2NH₃(g)	(I) Cu
(B) CO(g) + 3H₂(g) -> CH₄(g) + H₂O(g)	(II) Cu/ZnO – Cr₂O₃
(C) CO(g) + H₂(g) -> HCOH(g)	(III) Fe_xO_y + K₂O + Al₂O₃
(D) CO(g) + 2H₂(g) -> CH₃OH(g)	(IV) Ni

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Class 12th Chemistry Solutions

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Uses of catalyst is very specific for a particular reaction.

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The depression in freezing point observed for a formic acid solution of concentration 0.5 mL L^-1 is $0.0405 ° C .$ Density of formic acid is 1.05 g mL^-1. The Van't Hoff factor of the formic acid solution is nearly: (Given for water $K_{f} = 1.86 k k g m o l^{- 1}$ )

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Let we take $1 l$ of solution

Mass of solute = Volume * Density

= 0.5 $m l * 1.05 g m / m l$

= 0.525 gram

Mass of solution = 1 kg. [considering very dilute solution]

Mass of solvent = 1000 – 0.525 = 999.475 gram

$\Rightarrow i = 1.9$

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The most common oxidation state of Lanthanoid elements is +3. Which of the following is likely to deviate easily from +3 oxidation state?

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$C e^{3 +} \to [X e] 4 f^{1} 5 d^{0}$

$C e^{4 +} \to [X e] 4 f^{0} 5 d^{0}$ (Noble gas configuration)

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10 months ago

SO₂Cl₂ on reaction with excess of water results into acidic mixture

SO₂Cl₂ + H₂O -> H₂SO₄ + 2HCl

16 moles of NaOH is required for the complete neutralization of the resultant acidic mixture. The number of moles of SO₂Cl₂ used is:

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