Electrostatics
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New answer posted
a month agoContributor-Level 10
Enet = Eo/k
Enet = E_free - E_bound = qf/Aε? - qb/Aε?
Eo = qf/Aε?
So, (qf-qb)/Aε? = qf/ (kAε? )
qf - qb = qf/k
qb = qf (1 - 1/k)
New answer posted
a month agoContributor-Level 10
If charge (-Q) at origin is replaced by (+Q), then electric field at the centre of the cube is zero. Thus, electric field at the centre of the cube is as if only (-2Q) charge is present at the origin.
New answer posted
a month agoContributor-Level 10
When connected in series, equivalent capacitance,
When connected in parallel, equivalent capacitance
C2 = C + C = 2C
New answer posted
a month agoContributor-Level 10
(A) If is the velocity of light
so, (Energy of photon)
(B) Velocity of photon is equal to velocity of light i.e. c.
(C)
(D) In photon-electron collision both total energy and total momentum are conserved.
New answer posted
a month agoContributor-Level 10
The potential
at any point, at distance
from centre of dipole
At axial point where
At axial point where
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