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New answer posted
3 months agoContributor-Level 10
From the given information we can conclude that (P3) and (P4) are at seat numbers 7 and 6, respectively. And (P11) is the only person between (P3) and (P10) while (P1) is opposite to (P11). Hence, (P1), (P11) and (P10) must be at seat numbers 5, 8 and 9 respectively.
Then we have following two cases:
New question posted
3 months agoNew answer posted
3 months agoContributor-Level 10
According to the information provided following arrangement of the schedule will be formed.
Wed | Thu | Fri | Sat | Sun | Mon | Tue |
Z6, Z2 | Z8, Z5 | Z9, Z4 | Z3 | * | Z1, Z7 | Z10 |
New answer posted
3 months agoContributor-Level 10
Since, Kathak has one more dancer than Bhangra, there are 4 dancer in Kathak S4, S5, S6 and S9. Remaining dancers are in Bharatnatyam. So, option (a) is correct
New answer posted
3 months agoContributor-Level 10
If the Bharatnatyam team has just one member S10, then the Kathak team will surely have S4, S5 and S6 as dancers.
New answer posted
3 months agoContributor-Level 10
Going through options we find that the only possibility is S10 and S8.
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