Limits and Continuity

Follow Ask Question
1

Questions

0

Discussions

1

Active Users

0

Followers

New answer posted

a month ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

Using L'Hopital Rule:
lim (x→2) (2xf (2) - 4f' (x)/1 = 2 (2)f (2) - 4f' (2) = 4 (4) - 4 (1) = 12.

    Get authentic answers from experts, students and alumni that you won't find anywhere else

    Sign Up on Shiksha

    On Shiksha, get access to

    • 65k Colleges
    • 1.2k Exams
    • 688k Reviews
    • 1800k Answers

    Share Your College Life Experience

    ×

    This website uses Cookies and related technologies for the site to function correctly and securely, improve & personalise your browsing experience, analyse traffic, and support our marketing efforts and serve the Core Purpose. By continuing to browse the site, you agree to Privacy Policy and Cookie Policy.