Ncert Solutions Maths class 12th

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New answer posted•a year ago
S
a year ago

This is a True or False Type questions as classified in NCERT Exemplar

Sol:

F a l s e . L e t     u s     t a k e     a n     e x a m p l e :     f ( x ) = s i n x     a n d     g ( x ) = c o t x ∴ f ( x ) . g ( x ) = s i n x . c o t x = s i n x . c o s x s i n x = c o s x     w h i c h     i s     c o n t i n u o u s     a t     x = 0     b u t     c o t x     i s     n o t c o n t i n u o u s     a t     x = 0 .

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New answer posted•a year ago
S
a year ago

This is a True or False Type questions as classified in NCERT Exemplar

Sol: True.

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New answer posted•a year ago
S
a year ago

This is a True or False Type questions as classified in NCERT Exemplar

Sol: True.  We  know  that  the  sum  and  difference  of  two  or  more  functions  is  always  continuous.

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New answer posted•a year ago
S
a year ago

This is a True or False Type questions as classified in NCERT Exemplar

Sol: True.  We  know  that  the    function  is  continuous  function  on  its  domain.

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New answer posted•a year ago
S
a year ago

This is a True or False Type questions as classified in NCERT Exemplar

Sol:

False.  Given  that  f (x)=|x−1|  in   [0, 2]We  know  that  the    function  is  not  differentiable.  So.  it  is  false.

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New answer posted•a year ago
S
a year ago

This is a Fill in the Blanks Type questions as classified in NCERT Exemplar

Sol:

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New answer posted•a year ago
S
a year ago

This is a Fill in the Blanks Type questions as classified in NCERT Exemplar

Sol:

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New answer posted•a year ago
S
a year ago

This is a Fill in the Blanks Type questions as classified in NCERT Exemplar

Sol:

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New answer posted•a year ago
S
a year ago

This is a Fill in the Blanks Type questions as classified in NCERT Exemplar

Sol:

G i v e n     t h a t     y = x 2         a n d         t = x 3 D i f f e r e n t i a t i n g     b o t h     f u n c t i o n s     w . r . t .     x ⇒                                         d y d x = 2 x         a n d         d t d x = 3 x 2 ∴                                 d y d t = d y / d x d t / d x = 2 x 3 x 2 = 2 3 x S o ,     t h e     d e r i v a t i v e     o f     x 2     w . r . t .     x 3     i s     2 3 x

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New answer posted•a year ago
S
a year ago

This is a Fill in the Blanks Type questions as classified in NCERT Exemplar

Sol:

|x|=|x+1|  is  the  function  which  is  continuous  everywhere  but  fails  to  be  differentiableat  x=0  and  x=1.

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