Photoelectric Effect Wave Theory Light

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2 months ago

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V
Vishal Baghel

Contributor-Level 10

Let the work function of metal is ? , so

k 1 = 3 V 0 e = h c λ ? . (i)

K 2 = V 0 e = h c 2 λ ? . (ii)

Doing (i) – 3 X (ii), we have

0 = h c λ 3 h c 2 λ + 2 ? ? = h c 4 λ    

The threshold wavelength = h c ? = 4 λ

New answer posted

2 months ago

0 Follower 1 View

V
Vishal Baghel

Contributor-Level 10

Energy of photon, E = 1240 310 = 4 e V > 2 e V   (so photoelectric effect will take place)

= 4 * 1.6 * 10 - 19 = 6.4 * 10 - 19   Joule  

Number of photons falling per second

= 6.4 * 10 - 5 * 1 6.4 * 10 - 19 = 10 14

Number of photoelectron emitted per second

= 10 14 10 3 = 10 11

11

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