Physics Electric Charge and Field

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New answer posted

2 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

According to question, we can write

    F C A = F C B = K q Q x 2 + ( d 2 ) 2 F = 2 F C A c o s θ = 2 K q Q x [ x 2 + ( d 2 ) 2 ] 3 2                    

For maxima of force   d F d x = 0 , s o

x = d 2 2

New answer posted

2 months ago

0 Follower 17 Views

R
Raj Pandey

Contributor-Level 9

E = k q 2 a 2

E ' = k q ( 2 a ) 2 = k q 2 a 2
E N e t = 2 E c o s 4 5 ° + E '

= k q a 2 ( 1 2 + 1 2 )

New answer posted

2 months ago

0 Follower 1 View

R
Raj Pandey

Contributor-Level 9

Kindly consider the following Image

 

New answer posted

2 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

According to question, we can write

F C A = F C B = K q Q x 2 + ( d 2 ) 2 F = 2 F C A c o s θ = 2 K q Q x [ x 2 + ( d 2 ) 2 ] 3 2                         

For maxima of force  d F d x = 0 , s o  

x = d 2 2

 

New answer posted

2 months ago

0 Follower 2 Views

R
Raj Pandey

Contributor-Level 9

mg In equilibrium, Fe=T sin θ

mg=T cos θ

 tan θ=Femg=q24π0x2*mg

also  tan θs?=x/2l

Hence, x 2 l = q 2 4π0x2*mg

x 3 = 2 q 2 p 4πε0mg

x=(q2l2π0mg)1/3

Therefore xl1/3

New answer posted

2 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

In y axis u? = v? a? = -E? q / m
s? = 0, u? t + (1/2)a? t² = 0 ⇒ t = 2u? /a? = 2v? m/E? q
x coordinate at that time = v? * t = (2v? m/0) * v? = (2v? ²m)/E? q

New answer posted

2 months ago

0 Follower 3 Views

R
Raj Pandey

Contributor-Level 9

(Independent of distance)

E 1 = E 2 = σ 2 0

New answer posted

2 months ago

0 Follower 4 Views

V
Vishal Baghel

Contributor-Level 10

W = Uf - Ui
= 0 - (-P (λ/2πε? d)
= Pλ/2πε? d

New answer posted

2 months ago

0 Follower 3 Views

R
Raj Pandey

Contributor-Level 9

? E ? d s ? = 0 ? net   = ? in   - ? out   = 0

? in   = ? out  

New answer posted

2 months ago

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A
alok kumar singh

Contributor-Level 10

Polar molecules have centres of positive and negative charges separated by some distance, so they have permanent dipole moment

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