Physics Electric Charge and Field

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2 months ago

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P
Payal Gupta

Contributor-Level 10

According to Lorentz's Force, we can write

F=FElectric+FMagnetic=qE+q (v*B), so

Statement I is correct but Statement II is incorrect

New answer posted

2 months ago

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A
alok kumar singh

Contributor-Level 10

First resonating length = λ = V f = 3 4 0 3 4 0 = 1 m

Second resonating length = 3 λ 4 = 7 5 c m

Third resonating length = 5 λ 4 = 1 2 5 c m

Height of water required = 125 – 75 = 50cm

New answer posted

2 months ago

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A
alok kumar singh

Contributor-Level 10

Q = C1v                                                                                                          

...more

New answer posted

2 months ago

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A
alok kumar singh

Contributor-Level 10

Please find the solution below:

 

New answer posted

2 months ago

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A
alok kumar singh

Contributor-Level 10

E1 (done to q1) = k, q1 (d/2)2= [9*109*8*106]d2*4

E2 (done to q2) = kq2 (d/2)2= [9*109*8*106]d2*4

Enet = E1 + E2

=2 [4*9*109*8*106d2]

Given Enet = 6.4 * 104

2* [4*9*109*8*106d2]=6.4*104

d2 = 9 * 10-6 + 6

d = 3m

New answer posted

2 months ago

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A
alok kumar singh

Contributor-Level 10

E1 (done to q1) = k, q1 (d/2)2= [9*109*8*10? 6]d2*4

E2 (done to q2) = k? q2 (d/2)2= [9*109*8*10? 6]d2*4

Enet = E1 + E2

=2 [4*9*109*8*10? 6d2]

Given Enet = 6.4 * 104

? 2* [4*9*109*8*10? 6d2]=6.4*104

d2 = 9 * 10-6 + 6

d = 3m

New answer posted

2 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

F1=9*109*5*106*0.3*1069*104

= 15 N

F2=9*109*5*106*0.16*1069*104

= 8N

Fnet= (15)2+ (8)2

= 17 N

New answer posted

2 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

Sol. E= (I) (t) (A)cos2? θ
(3.3)2π31.43*10-4*12

0.99*10-4

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