Physics Electromagnetic Waves

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New answer posted

a month ago

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R
Raj Pandey

Contributor-Level 9

E = P * t = 100 * 10 3 * 3600

= 36 * 10 7 J

New answer posted

a month ago

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R
Raj Pandey

Contributor-Level 9

n = ? r u r

n = c v v = c n

V = c ? r μ r

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a month ago

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V
Vishal Baghel

Contributor-Level 10

d_lm = Distance covered by transmitting antenna + Distance covered by receiving antenna

⇒ d_lm = √ (2Rh_transmitting) + √ (2Rh_receiving)
⇒ d_lm = √ (2 * 64 * 10? * 20) + √ (2 * 64 * 10? * 5) = 16000 + 8000 = 24000m

When h_receiving = 0 then
d_2m = √ (2 * 64 * 10? * 20) = 16000m

% increment = (8000/16000) * 100 = 50

New answer posted

a month ago

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V
Vishal Baghel

Contributor-Level 10

As we know that direction of propagation of electromagnetic wave is perpendicular to plane containing mutually perpendicular electric field and magnetic field, so option D will be correct answer.

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A
alok kumar singh

Contributor-Level 10

Electric field squared is proportional to the power P of the bulb (E² ∝ P).
(E' / E)² = (60 / 100) ⇒ E' = E * √* (3/5)*

New answer posted

a month ago

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R
Raj Pandey

Contributor-Level 9

Direction of E is perpendicular to the direction of propagation and that of B.
E = cB = 3 * 10? * 2 * 10? = 6 V/m

New answer posted

a month ago

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V
Vishal Baghel

Contributor-Level 10

The force (F) exerted by radiation is the rate of change of momentum (p).
F = Δp/Δt
For photons, p = E/c. So, F = (1/c) * (ΔE/Δt).
Since Power (P) is ΔE/Δt, F = P/c.
Intensity (I) is Power per unit Area (P/A).
The formula provided in the document is F/A = (nE)/ (Δt c A) which leads to a final calculated value of 25 W/cm².

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New question posted

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New answer posted

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A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

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