Physics Electromagnetic Waves
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New answer posted
a month agoContributor-Level 10
d_lm = Distance covered by transmitting antenna + Distance covered by receiving antenna
⇒ d_lm = √ (2Rh_transmitting) + √ (2Rh_receiving)
⇒ d_lm = √ (2 * 64 * 10? * 20) + √ (2 * 64 * 10? * 5) = 16000 + 8000 = 24000m
When h_receiving = 0 then
d_2m = √ (2 * 64 * 10? * 20) = 16000m
% increment = (8000/16000) * 100 = 50
New answer posted
a month agoContributor-Level 10
As we know that direction of propagation of electromagnetic wave is perpendicular to plane containing mutually perpendicular electric field and magnetic field, so option D will be correct answer.
New answer posted
a month agoContributor-Level 10
Electric field squared is proportional to the power P of the bulb (E² ∝ P).
(E' / E)² = (60 / 100) ⇒ E' = E * √* (3/5)*
New answer posted
a month agoContributor-Level 9
Direction of E is perpendicular to the direction of propagation and that of B.
E = cB = 3 * 10? * 2 * 10? = 6 V/m
New answer posted
a month agoContributor-Level 10
The force (F) exerted by radiation is the rate of change of momentum (p).
F = Δp/Δt
For photons, p = E/c. So, F = (1/c) * (ΔE/Δt).
Since Power (P) is ΔE/Δt, F = P/c.
Intensity (I) is Power per unit Area (P/A).
The formula provided in the document is F/A = (nE)/ (Δt c A) which leads to a final calculated value of 25 W/cm².
New question posted
a month agoNew question posted
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