Physics NCERT Exemplar Solutions Class 11th Chapter Eight

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New answer posted

a month ago

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alok kumar singh

Contributor-Level 10

Let height of bridge = h

Displacement of ball, S = - h

S = u t + 1 2 a t 2 - h = 4 * 4 + 1 2 ( - 10 ) ( 4 ) 2 h = 64 m

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a month ago

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New answer posted

a month ago

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A
alok kumar singh

Contributor-Level 10

Factual (theory based)

Capacitor in parallel removes the AC ripple from the rectified output.

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a month ago

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alok kumar singh

Contributor-Level 10

N N 0 = 1 16 = 1 2 t T 1 / 2

t = 4 T 1 / 2 = 20 * 4 = 80   minutes  

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a month ago

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alok kumar singh

Contributor-Level 10

? 1 λ = R 1 n 2 2 - 1 n 1 2

1 λ = R 1 2 2

λ = 4 R

1 λ ' = R 1 4 2

λ ' = 16 R

λ ' = 4 λ

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alok kumar singh

Contributor-Level 10

Speed of light in air is

C = x t 1

Speed of light in another denser medium.

C 2 = 10 x t 2

μ = C C 2 = x t 1 * t 2 10 x

μ = t 2 10 t 1

(d) Δ θ = λ d

Δ θ is proportional to λ but independent of D .

(c) e V = Energy of electron

for minimum wavelength, maximum loss of energy

e V = h c λ

λ 1 V

  1. (b) Incident energy = 2.20 e V

If ? < 2.20 e V  electron will emit.

? > 2.20 e V No electron emission

Only caesium will emit electron

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alok kumar singh

Contributor-Level 10

B = E C = 48 3 * 10 8 = 16 * 10 - 8

= 1.6 * 10 - 7 T

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2 months ago

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alok kumar singh

Contributor-Level 10

l g = n k

l g G = ( l l g ) s

n k G = ( l n k ) s l = n k G s + n k = n k ( G + s ) s

l = n k s ( G + s )

 

New answer posted

2 months ago

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A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

Based on theory

New answer posted

2 months ago

0 Follower 1 View

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alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

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