physics ncert exemplar solutions class 12th chapter two

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New answer posted

2 months ago

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V
Vishal Baghel

Contributor-Level 10

 Δλλ=vc

v=ΔλλC

0.7*109670*109*3*108

3.13*105

New answer posted

2 months ago

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V
Vishal Baghel

Contributor-Level 10

If frequency is night wavelength is low.

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V
Vishal Baghel

Contributor-Level 10

emf induced = BHωl22

=0.2*104*5*122=50μv

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V
Vishal Baghel

Contributor-Level 10

 Leq=L1+L22M

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Vishal Baghel

Contributor-Level 10

 u=MBcosθ2 (MBcosθ1)

=MB (cosθ2cosθ1)=2*105*14*105 (cos60°cos0°)

=28 (121)

=282=14J

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P
Payal Gupta

Contributor-Level 10

Since

E.B=0 (EB)

&E0B0=C=3*108m/sec

for option D

E0B0=301.62+452.421061.52+12=301.6*106=3.01*108m/sec

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V
Vishal Baghel

Contributor-Level 10

Kindly consider the following figure

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Vishal Baghel

Contributor-Level 10

Since, volume remain constant

64*43πr3=43πR3

R3 = r3 * 64

R = 4r

σbiggerσsmalldrop=5*64*4π24πR2*5=64 (rR)2=64 (r4r)2=6416=4:1

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2 months ago

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V
Vishal Baghel

Contributor-Level 10

 Given0Ad=4μF

C1=0A*2d=2*4=8μF

C2=k0Ad/2=3*2*4=24μF

Ceq=C1C2C1+C2=8*248+24=8*2432=6μF

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2 months ago

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V
Vishal Baghel

Contributor-Level 10

 1Ceq=1C1+1C2+1C3=110+115+120

1Ceq=6+4+360=1360

Leq=6030μF

Q=Ceqv=6013*13μC

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