Physics Nuclei Overview

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New answer posted

5 months ago

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V
Vishal Baghel

Contributor-Level 10

t? , half life = (log?2)/λ = 3 s
Initially 200 nuclei were there
After 3 half-lives, 9 seconds,
No. of nuclei = (1/2³) (200) = 25
Therefore, the number of nuclei that decayed = 200 – 25 = 175

New answer posted

5 months ago

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V
Vishal Baghel

Contributor-Level 10

N = [n + n/10 + n/100 + .]
= n/ (1 - 1/10) = 10/9

New answer posted

5 months ago

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V
Vishal Baghel

Contributor-Level 10

Always possible as it is associated only with β? decay


New answer posted

5 months ago

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V
Vishal Baghel

Contributor-Level 10

Kindly consider the following figure

New answer posted

5 months ago

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A
alok kumar singh

Contributor-Level 10

A = A? (1/2)?
A/A? = 1/8 = (1/2)³ ⇒ n = 3
t = n T½
30 = 3 T½
T½ = 10 years

New answer posted

6 months ago

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R
Raj Pandey

Contributor-Level 9

A λ A B λ B C

Amount of B,

N B = λ A N A 0 λ B λ A [ e λ A t e λ B t ]

where K = λ A λ B λ A N A 0

New answer posted

6 months ago

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V
Vishal Baghel

Contributor-Level 10

N N 0 = ( 1 2 ) t | t 1 | 2

N = 1 0 1 0 * ( 1 2 ) 1 2 = 1 0 1 0 2 ? 7 * 1 0 9

New answer posted

6 months ago

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P
Payal Gupta

Contributor-Level 10

Radius, R = R0A1/3

New answer posted

6 months ago

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V
Vishal Baghel

Contributor-Level 10

t 1 2 = 6 0 d a y s

at t = 0 m m 0  0

a t t m m 0 ( 1 7 8 )

= m 8 m 0 7 8 ( m m 0 )

1 2 3 = 1 2 ( t 6 0 ) t 6 0 = 3

t = 180 days

New answer posted

6 months ago

0 Follower 4 Views

P
Payal Gupta

Contributor-Level 10

forA, t12=4sec

=mA0e0.6934*16

mA=mA0e4*0.693 - (1)

for B,

for B,  t12=8sec

mB=mB0e2*0.693 - (2)

mAmB=mAOmBOe4*0.693e2*0.693

mAmB=25100=x100x=25

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