Physics Nuclei Overview

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New answer posted

a month ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

Energy of products = 939 + 940 = 1879
ΔE + E_reactions – E_productor = 1877 – 1879 = -2MeV.
Hence it must capture a γ - ray photon of energy 2MeV.

New answer posted

a month ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

t? , half life = (log?2)/λ = 3 s
Initially 200 nuclei were there
After 3 half-lives, 9 seconds,
No. of nuclei = (1/2³) (200) = 25
Therefore, the number of nuclei that decayed = 200 – 25 = 175

New answer posted

a month ago

0 Follower 1 View

V
Vishal Baghel

Contributor-Level 10

N = [n + n/10 + n/100 + .]
= n/ (1 - 1/10) = 10/9

New answer posted

2 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

Always possible as it is associated only with β? decay


New answer posted

2 months ago

0 Follower 10 Views

V
Vishal Baghel

Contributor-Level 10

Kindly consider the following figure

New question posted

2 months ago

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New answer posted

2 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

A = A? (1/2)?
A/A? = 1/8 = (1/2)³ ⇒ n = 3
t = n T½
30 = 3 T½
T½ = 10 years

New answer posted

3 months ago

0 Follower 2 Views

R
Raj Pandey

Contributor-Level 9

A λ A B λ B C

Amount of B,

N B = λ A N A 0 λ B λ A [ e λ A t e λ B t ]

where K = λ A λ B λ A N A 0

New answer posted

3 months ago

0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

N N 0 = ( 1 2 ) t | t 1 | 2

N = 1 0 1 0 * ( 1 2 ) 1 2 = 1 0 1 0 2 ? 7 * 1 0 9

New answer posted

3 months ago

0 Follower 1 View

P
Payal Gupta

Contributor-Level 10

Radius, R = R0A1/3

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