Physics Nuclei Overview
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Determine the number of nuclei that will be decayed upto one average life of radioactive material? (N0 : Initial number of nuclei)
Determine the number of nuclei that will be decayed upto one average life of radioactive material? (N0 : Initial number of nuclei)
N = N0e–λt
->t = λN = N0/e
So number of nuclei decayed = N0 – N
= N0 (1- 1/e)
Density of nuclei is order of 1017 kg m–3.
Power factor of series LCR circuit at resonance is
Power factor of series LCR circuit at resonance is
Density of nuclei is order of 1017 kg m-3.
Two radioactive substances X and Y originally have N1 and N2 nuclei respectively. Half life of X is half of the life of Y. After three half lives of Y, number of nuclei of both are equal.
The ratio will be equal to:
Two radioactive substances X and Y originally have N1 and N2 nuclei respectively. Half life of X is half of the life of Y. After three half lives of Y, number of nuclei of both are equal.
The ratio will be equal to:
Number of half lives of Y = 3
Number of half lives of X = 6 [As half life of X is half of that of Y].
The half life of a radioactive substance is 5 years. After x years a given sample of the radioactive substance gets reduced to 6/25% of its initial value. The value of x is___________.
The half life of a radioactive substance is 5 years. After x years a given sample of the radioactive substance gets reduced to 6/25% of its initial value. The value of x is___________.
According to Nuclear activity, we can write
Time required = 4 ×
A ray of light is incident at an angle of incidence on the glass slab of refractive index After refraction, the light ray emerges out from other parallel faces and lateral shift between incident ray and emergent ray is cm. The thickness of the glass slab is _______cm.
A ray of light is incident at an angle of incidence on the glass slab of refractive index After refraction, the light ray emerges out from other parallel faces and lateral shift between incident ray and emergent ray is cm. The thickness of the glass slab is _______cm.
cm (Lateral shift)
By Snell’s law
θ = 30
t = 12 cm

Mass of Bromine, Selenium and Krypton are given as:-
Mass of Bromine, Selenium and Krypton are given as:-
The rest mass of the deuteron, proton and neutron is equivalent to energy of 1877MeV, 939MeV, 940MeV respectively. A deuteron may disintegrate to a proton and neutron if it.
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The rest mass of the deuteron, proton and neutron is equivalent to energy of 1877MeV, 939MeV, 940MeV respectively. A deuteron may disintegrate to a proton and neutron if it.
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Energy of products = 939 + 940 = 1879
ΔE + E_reactions – E_productor = 1877 – 1879 = -2MeV.
Hence it must capture a γ - ray photon of energy 2MeV.


