Physics Nuclei Overview

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a month ago

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A
alok kumar singh

Contributor-Level 10

N N0eλt

->t = λN = N0/e

So number of nuclei decayed = N0N

N0 (1- 1/e) 

New answer posted

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A
alok kumar singh

Contributor-Level 10

Density of nuclei is order of 1017 kg m–3.

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A
alok kumar singh

Contributor-Level 10

Kindly go through the solution '

 

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V
Vishal Baghel

Contributor-Level 10

Density of nuclei is order of 1017 kg m-3.

New answer posted

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V
Vishal Baghel

Contributor-Level 10

Number of half lives of Y = 3

Number of half lives of X = 6 [As half life of X is half of that of Y].

N 1 2 6 = N 2 2 3 N 1 N 2 = 8

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a month ago

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Vishal Baghel

Contributor-Level 10

According to Nuclear activity, we can write

N 0 t 1 2 N 0 2 t 1 2 N 0 4 t 1 2 N 0 8 t 1 2 N 0 1 6 = ( 0 . 0 6 2 5 ) N 0         

Time required = 4 * t 1 2 = 2 0 y r s  

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a month ago

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New answer posted

a month ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

a month ago

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alok kumar singh

Contributor-Level 10

d = 4 3 cm (Lateral shift)

By Snell's law

μ a i r s i n 6 0 ° = μ g s i n θ

θ = 30

1*32=3sinθ  

s i n θ = 1 2  

t = 12 cm

New answer posted

a month ago

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Vishal Baghel

Contributor-Level 10

Q ( i ) = ( M B r M K r ) c 2 > 0

Q ( i i ) = ( M B r M S e 2 M e ) c 2 > 0 Q ( i i ) = ( M B r M s e ) c 2 > 0

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