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Payal Gupta

Contributor-Level 10

This is a multiple choice answer as classified in NCERT Exemplar

(a), (d) Initially key K1 is closed and key K2 is open, the capacitor C1 is charged by battery and capacitor C2 is still uncharged. Now K1 is opened and K2 is closed, the capacitors C1 and C2 both are connected in parallel. The charge stored by capacitor C1, gets redistributed between C1 and C2 till their potentials become same, i.e., V2 = V1.
By law of conservation of charge, the charge stored in capacitor Cx is equal to sum of charges on capacitors C1 and C2 when K1 is opened and K2 is closed, i.e.,  Q

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New question posted

10 months ago

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New answer posted

10 months ago

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P
Payal Gupta

Contributor-Level 10

This is a multiple choice answer as classified in NCERT Exemplar

(b), (c) We know, the electric field intensity E and electric potential V are dV related as E =- dV/dr or we can write |E|=ΔV/Δr

The electric field intensity E and electric potential V are related as E = 0 and for V = constant, dV/dr=0 this imply that electric field intensity E = 0.

If some charge is present inside the region then electric field cannot be zero at that region, for this V = constant is not valid.

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10 months ago

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Payal Gupta

Contributor-Level 10

This is a multiple choice answer as classified in NCERT Exemplar

(b), (c) If potential of two point is same then work done is also zero according to relation As W=qdv=q (final potential-initial potential).

Also W=-qdv= -q 1 2 E . d l

For equipotential surface V2-V2=0 and W=0

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Payal Gupta

Contributor-Level 10

This is a multiple choice answer as classified in NCERT Exemplar

(a), (b), (c) Properties of equipotential surfaces

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Payal Gupta

Contributor-Level 10

This is a multiple choice answer as classified in NCERT Exemplar

(c) Field lines are always perpendicular to the direction of equipotential surface. The electric field in the in z- direction suggest that equipotential surface are in x-y plane. The shape of equipotential surface depends upon nature and type of distribution of charges.

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10 months ago

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Payal Gupta

Contributor-Level 10

This is a multiple choice answer as classified in NCERT Exemplar

C1 = k 1 ? A d 1  , C2 = k 2 ? A d 2

1 C = 1 C 1 + 1 C 2 = C 1 * C 2 C 1 + C 2 = k 1 k 2 ? A k 1 d 2 + k 2 d 1

K = k 1 k 2 ( d 1 + d 2 ) k 1 d 2 + k 2 d 1

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Payal Gupta

Contributor-Level 10

This is a multiple choice answer as classified in NCERT Exemplar

(a) The electric potential due to point charge q is given by V=q/4? 0r

It means electric potential due to point charge is same for all equidistant points. The locus of these equidistant points, which are at same potential, form spherical surface.

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10 months ago

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Payal Gupta

Contributor-Level 10

This is a multiple choice answer as classified in NCERT Exemplar

(c) As we know that E= - d v d r and potential is always same through out the surface, so according to relation electric field is zero because potential remains same at each point.

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Payal Gupta

Contributor-Level 10

This is a multiple choice answer as classified in NCERT Exemplar

(c) As W=qdv=q (final potential-initial potential), but the potential at a and b is same in all cases . so work done is equal in all cases.

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