Redox Reactions
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New answer posted
4 months agoContributor-Level 10
This is a Multiple Choice Questions as classified in NCERT Exemplar
Option (iv) is the correct answer.
Disproportionate reactions are defined as the reactions in which the same substance is oxidized as well as reduced. Here, the below reaction is given as-
2NO2 + 2OH- →NO2 -+ NO3- +H2O
In this reaction, N is both oxidized as well as reduced since O.N. of N increases from +4 in NO3−? to +5 in NO2 ? and decreases from +4 in NO to +3 in NO2−.
New answer posted
4 months agoContributor-Level 10
This is a Multiple Choice Questions as classified in NCERT Exemplar
Option (iv) is the correct answer
For 3d1 4s2 can exhibit the highest oxidation state as 2+1 = +3,
For 3d34s2can exhibit the highest oxidation state as 2+3 = +5
For 3d54s1can exhibit the highest oxidation state as 1+5 = +6
For 3d54s2can exhibit the highest oxidation state as 2+5 = +7
New answer posted
4 months agoContributor-Level 10
This is a Multiple Choice Questions as classified in NCERT Exemplar
Option (i) is the correct answer
Let the oxidation number of central atom be 'y'.
Oxidation number of O = −2
CrO2−: y + 2 * (−2) = −1
y − 4 = −1 or y = +3
CrO42−? : y + 4 * (−2) = −2
y − 8 = −2 or y = +6
ClO3−: y + 3 * (−2) = −1
y − 6 = −1 or y = +5
MnO4−: y + 4 * (−2) = −1
y − 8 = −1 or y = +7
increasing order of oxidation number of the central atom is:
CrO2 – , ClO3 –, CrO4 2–, MnO4
New answer posted
4 months agoContributor-Level 10
This is a Multiple Choice Questions as classified in NCERT Exemplar
Option (ii) is the correct answer.
The oxidation states are given below-
In NH2OH oxidation of N is -1.
NH4NO3 exists as NH4+.NO3-,
Thus, the oxidation state of N in NH4+ is -3 while in NO3? is +5.
In N2H4 oxidation of N is -2
In N3H oxidation of N is
New answer posted
4 months agoContributor-Level 10
This is a Multiple Choice Questions as classified in NCERT Exemplar
Option (i) is the correct answer
In ionic hydrides hydrogen exists in -1 oxidation state because the hydrogen acquires negative charge in the presence of its companion.
New answer posted
4 months agoContributor-Level 10
This is a Multiple Choice Questions as classified in NCERT Exemplar
Option (i) is the correct answer.
Standard reduction potential of bromine is higher than Iodine, hence Bromine is a stronger oxidant than iodine.
New answer posted
4 months agoContributor-Level 10
This is a Multiple Choice Questions as classified in NCERT Exemplar
Option (iv) is the correct answer.
E? will be negative for the pair Ag and Fe3+. Hence the reaction is not feasible.
New answer posted
4 months agoContributor-Level 10
This is a Multiple Choice Questions as classified in NCERT Exemplar
Option (iv) is the correct answer
Reduction potential is defined as the tendency of the specie to get reduced. More positive the value of E® , greater is the tendency of the species to get reduced and stronger is the oxidising agent.
On the basis of the given E® values, the order of getting reduced is:
Br2Ag + I2Cu2+
Hence, Cu has the least tendency to get reduced and will itself gets oxidise and reduce other species as: Br2? , Ag+ and I2.
New answer posted
4 months agoContributor-Level 10
This is a Multiple Choice Questions as classified in NCERT Exemplar
Option (iv) is the correct answer
The strongest oxidising agent means it has greater tendency to oxidise other species and itself gets easily reduced. So higher the E? values, stronger is the oxidising agent it is. Thus, Ag+ having the highest positive E? value among the given systems, is the strongest oxidising agent.
New answer posted
4 months agoContributor-Level 10
This is a Multiple Choice Questions as classified in NCERT Exemplar
option (iv) is the correct answer.
Redox reaction is defined as the simultaneous oxidation and reduction of reacting species. Thus, change in oxidation state will decide whether a reaction is redox or not. Thus, assigning the oxidation states as:
(i) CuO + H2→ Cu + H2O
Here, oxidation of H and reduction of Cu is taking place.
(ii) Fe2O3 + 3CO→ 2Fe + 3CO2
Here, oxidation of C and reduction of Fe is taking place.
(iii) 2K + F2→2KF
Here, the oxidation of K and reduction of F is taking place.
(iv) BaCl2 + H
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