Tags Angular Momentum of Rotation About a Fixed Axis

Angular Momentum of Rotation About a Fixed Axis

Get insights from 9 questions on Angular Momentum of Rotation About a Fixed Axis, answered by students, alumni, and experts. You may also ask and answer any question you like about Angular Momentum of Rotation About a Fixed Axis

Follow Ask Question

Questions

Discussions

Active Users

Followers

New answer posted

a month ago

Angular Momentum of Rotation About a Fixed Axis Class 11th

The position vector of 1kg object is $\vec{r} = (3 \hat{i} - \hat{j}) m$ and its velocity $\vec{v} = (3 \hat{j} + \hat{k}) m s^{- 1} .$ The magnitude of is angular momentum is $\sqrt[]{x} N m$ where x is________.

0 Follower 2 Views

Vishal Baghel

Contributor-Level 10

$\vec{L} = \vec{r} * m \vec{v}$

= $(3 \hat{i} - \hat{j}) * (3 \hat{j} + \hat{k})$

$= 9 \hat{k} + 3 (- \hat{j}) - \hat{i}$

$= - \hat{i} - 3 \hat{j} + 9 \hat{k}$

$| \vec{L} | = \sqrt[]{1 + 9 + 81} = \sqrt[]{91}$

0 0

New answer posted

a month ago

Angular Momentum of Rotation About a Fixed Axis Class 11th

Three rods of equal mass having length L, L and √2L are joined to form a triangular frame as shown in the figure. The system is rotating about an axis passing through the vertex of the triangle and perpendicular to the plane of the triangle with an angular velocity ω. Find the angular momentum of the system.

0 Follower 2 Views

Vishal Baghel

Contributor-Level 10

L = Iω
I = (mL²/3) + (mL²/3) + [m (√2L)²/12] + m (L/√2)² = mL² [2/3 + 1/6 + 1/2] = (4mL²/3); L = (4/3)mL²ω

0 0

New answer posted

a month ago

Angular Momentum of Rotation About a Fixed Axis Class 11th

Can angular momentum also be defined for a straight line motion?

0 Follower 1 View

Aadit Singh Uppal

Contributor-Level 10

Yes, an object moving in a straight path can also possess angular momentum with respect to a referenc epoint which doesn't lie on it's path. In such cases. the referenc epoint may lie perpendicular distance from the axis. If an object is moving in a straight line (not through the reference point) the perpendicular distance $r_\perp$ (l = rp) will be non-zero.

0 0

New answer posted

a month ago

Angular Momentum of Rotation About a Fixed Axis Class 11th

Do the planets in outer space also possess angular momentum?

0 Follower 1 View

Aadit Singh Uppal

Contributor-Level 10

Yes, how much time these planets take in completing an orbit around the sun hugely depends on their distance from the sun as well as their mass. Since these planets move in a circular orbit, the term angular momentum is used in such cases for computing relevant information.

0 0

New answer posted

a month ago

Angular Momentum of Rotation About a Fixed Axis Class 11th

Why is angular momentum not a scalar quantity?

0 Follower 1 View

Aadit Singh Uppal

Contributor-Level 10

Angular momentum also depends on how the mass is spread over the body and not just mass only. If you closely look at the formula of angular momentum:

L=r*p

You will observe that it is a cross product of two vector quantities. Hence, the formula won't be practical without direction being involved.

0 0

New answer posted

a month ago

Angular Momentum of Rotation About a Fixed Axis Class 11th

A thin circular ring of mass M and radius r is rotating about its axis with an angular speed ω. Two particles having mass m each are now attached at diametrically opposite points. The angular speed of the ring will become:

0 Follower 2 Views

Raj Pandey

Contributor-Level 9

Using conservation of Angular momentum along axis of rotation, we can write
Mr²ω = (Mr² + 2mr²)ω? ⇒ ω? = Mω / (M + 2m)

0 0

New answer posted

a month ago

Angular Momentum of Rotation About a Fixed Axis Class 11th

A mass M hangs on a massless rod of length l which rotates at a constant angular frequency. The mass M moves with steady speed in a circular path of constant radius. Assume that the system is in steady circular motion with constant angular velocity ω. The angular momentum of M about point A is LA which lies in the positive z direction and the angular momentum of M about point B is LB. The correct statement for this system is:

0 Follower 3 Views

Vishal Baghel

Contributor-Level 10

Kindly consider the following figure

0 0

New answer posted

a month ago

Angular Momentum of Rotation About a Fixed Axis Class 11th

Four point masses, each of mass m, are fixed at the corners of a square of side l. The square is rotating with angular frequency ω, about an axis passing through one of the corners of the square and parallel to its diagonal, as shown in the figure. The angular momentum of the square about this axis is:

0 Follower 3 Views

Vishal Baghel

Contributor-Level 10

I = m (l/√2)²*2 + m (√2l)² = 3ml²
L=Iω = 3ml²ω

0 0

New answer posted

2 months ago

Angular Momentum of Rotation About a Fixed Axis Class 11th

Consider a uniform rod of mass $M = 4 m$ and length $l$ pivoted about its centre. A mass $m$ moving with velocity $v$ making angle $θ = \frac{π}{4}$ $\frac{}{}$ to the rod's long axis collides with one end the rod and sticks to it. The angular sped of the rod-mass system just after the collision is

0 Follower 7 Views

Raj Pandey

Contributor-Level 9

$L_{o i} = L_{o f}$

$\begin{array}{r} \frac{m v}{\sqrt[]{2}} * \frac{l}{2} = [\frac{4 m l^{2}}{12} + \frac{m l^{2}}{4}] * ω \\ ω = \frac{6 v}{7 \sqrt[]{2} l} = \frac{3 \sqrt[]{2} v}{7 l} \end{array}$

0 0

Get authentic answers from experts, students and alumni that you won't find anywhere else

On Shiksha, get access to

65k Colleges
1.2k Exams
687k Reviews
1800k Answers

Community GuidelinesUser Points System

QuestionsDiscussionsTags

Need guidance on career and education? Ask our experts

Your Question

Angular Momentum of Rotation About a Fixed Axis

Questions

Discussions

Active Users

Followers

All

Discussions

Unanswered Questions

Share Your College Life Experience