Aromatic Hydrocarbon

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A
alok kumar singh

Contributor-Level 10

It does not follow Huckel's rule hence it is not aromatic.

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V
Vishal Baghel

Contributor-Level 10

In (Ph)2C = CHCN3, no spatial variation is possible

It will not show geometrical isomerism.

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Vishal Baghel

Contributor-Level 10

Noble gases have weak dispersion forces so their melting and boiling point are very low.

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Vishal Baghel

Contributor-Level 10

Cyclohepta-1, 3, 5-triene is not aromatic as one carbon is saturated (sp³).

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Raj Pandey

Contributor-Level 9

Non-aromatic because of one sp³ hybrid carbon, also no complete delocalisation.

It is aromatic; has 6π electrons.

It is aromatic; has 6π electrons.

It has 4π electrons, so anti-aromatic

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Vishal Baghel

Contributor-Level 10

In an aromatic compound, overall delocalization is processed by the electrons according to Hückel's rule. For the compound in question, the total number of delocalized electrons is 6.

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alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

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Vishal Baghel

Contributor-Level 10

Kindly consider the following figure

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alok kumar singh

Contributor-Level 10

Please find the solution below:

 

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