Chemistry NCERT Exemplar Solutions Class 11th Chapter Twelve
Get insights from 75 questions on Chemistry NCERT Exemplar Solutions Class 11th Chapter Twelve, answered by students, alumni, and experts. You may also ask and answer any question you like about Chemistry NCERT Exemplar Solutions Class 11th Chapter Twelve
Follow Ask QuestionQuestions
Discussions
Active Users
Followers
New answer posted
6 months ago
Contributor-Level 10
29. (i) It does not show resonance due to the absence of π electrons.
(ii) It shows resonance due to the presence of lone pairs on the Nitrogen atom and π electrons on the C = O bond. Hence, amide can be represented by three resonating structures.
(iii) In this structure, the lone pair of electrons present on Nitrogen atom, is not conjugated with the π electrons of double bond. Hence, it does not show resonance.
New answer posted
6 months agoContributor-Level 10
28.
S.No. | Inductive Effect | Resonance Effect |
1 | It involves the displacement of σ electrons in saturated compounds. | It involves displacement of π electrons or Lone pair of electrons in unsaturated and conjugated compounds. |
2 | In inductive effect, there is slight displacement of σ electrons and partial positive or negative charge develops. | In this effect, there is complete transfer of π electrons and as a result, complete positive or negative charge develops. |
3 | Inductive effect can move only up to 3 to 4 carbons. | In this case, movement of electrons along the length a conjugated system takes place. |
New answer posted
6 months ago
Contributor-Level 10
(i) In this case CH3+ is the most stable species because replacement of H atom by Br atom (-Inductive effect) increases positive (ii
(ii)
is most stable because negative charge on carbon atom is dispersed due to -I effect of Cl. More Cl atoms, more dispersal of negative charge and more stabilized.
New answer posted
6 months ago
Contributor-Level 10
is most stable because negative charge on carbon atom is dispersed due to -I effect of Cl. More Cl atoms, more dispersal of negative charge and more stabilized.
New answer posted
6 months agoContributor-Level 10
27. In this case CH3+ is the most stable species because replacement of H atom by Br atom (-Inductive effect) increases positive charge on the carbon atom and destabilizes the species.
New question posted
6 months ago
New question posted
6 months agoNew answer posted
6 months agoContributor-Level 10
This is a short answer type question as classified in NCERT Exemplar
SO3 acts as an electrophile as in this, three highly electronegative oxygen atoms are attached to the sulphur atom which makes it electron deficient. It can be shown by resonance that it gets positive charge and acts as an electrophile.
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else
Sign Up on ShikshaOn Shiksha, get access to
- 65k Colleges
- 1.2k Exams
- 679k Reviews
- 1800k Answers