Chemistry

$K{O}_2,N{O}_2,Cl{O}_2,NO$ are paramagnetic.

On decreasing pressure of NO by a factor of '2' the rate of reaction decreases by a factor of '4'

$\therefore$ Order of reaction w.r.t 'NO' = 2

Meq of K₂Cr₂O₇ = Meq of Fe²⁺

-> (Molarity * Volume * nf) of K₂Cr₂O₇ = (molarity * volume * nf) of Fe²⁺

->0.02 * 20 * 6 = M * 10 * 1

M = 0.24 M

Molarity = 24 * 10^-2 M

The central atom of nitrogen has 5 valence electrons as per the electronic configuraion. During the formation of ${\mathrm{N}\mathrm{H}}_3$ , 3 valence electrons forms three sigma bonds with hydrogen and one lone electron pair is left.

• The steric number  of the ammonia molecule: SN=3 bonds +1 lone pair $=4$ total electron domains.
• As per the steric number, there is ${\mathrm{s}\mathrm{p}}^3$ hybridisation in ammonia.
• The lone pair causes repulsion, which leads to a trigonal pyramidal geometry with bond angles of ${107}^{?}$ .

For an acid- base titration, Methly orange exist at end point as quinonoid form.

Based upon the properties and uses of chemical substances.

In sucrose, glycosidic linkage is between C₁ of α-glucose and C₂ of β-fructose.

Based upon the properties and uses of chemical substances.

Consider the below image