Class 11th
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New answer posted
4 months agoContributor-Level 10
V_rms = √ (3RT/M)
V_N? = V_H?
√ (3RT_N? / M_N? ) = √ (3RT_H? / M_H? )
573/28 = T_H? /2
⇒ T_H? = 40.928
New answer posted
4 months agoContributor-Level 10
L_i = L_f
mvL = Iω
mvL = (ML³/3 + mL²)ω
Before collision
After collision
0.1 * 80 * 1 = (0.9 * 1²)/3 + 0.1 * 1²)ω
8 = (3/10 + 1/10)ω 8 = (4/10)ω ω = 20 rad/sec
New answer posted
4 months agoContributor-Level 10
Area of OABS is A?
Area of SCD is A?
Distance = |A? | + |A? |
A? = (1/2) [13/3 + 1]4 = 32/3
A? = (1/2) * 5/3 * 2 = 5/3
Distance = |A? | + |A? |
= 32/3 + 5/3 = 37/3
New answer posted
4 months agoContributor-Level 10
Moment of inertia in case (i) is I?
Moment of inertia in case (ii) is I?
I? = 2MR²
I? = (3/2)MR²
T? = 2π√ (I? /Mgd); T? = 2π√ (I? /Mgd)
T? /T? = √ (I? /I? ) = √ (2MR² / (3/2)MR²) = 2/√3
New answer posted
4 months agoContributor-Level 10
√2gh = (2r²g/9η) (ρ_t - ρ)
⇒ h = (2/81) (r? g (ρ_t - ρ)²/η²)
⇒ h ∝ r?
After falling through h, the velocity be equal to terminal velocity.
New answer posted
4 months agoContributor-Level 10
dm (t)/dt = bv²
F_thrust = v ( dm/dt )
Force on satellite = -v (dm (t)/dt)
M (t)a = -v (bv²)
a = - (bv³)/M (t)
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