Class 11th

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V
Vishal Baghel

Contributor-Level 10

Kindly consider the following figure

                  

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V
Vishal Baghel

Contributor-Level 10

Probability density of plots


From the given graph answer is (1)

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Vishal Baghel

Contributor-Level 10

Hess's law
ΔH_solution = ΔH_lattice + ΔH_hydration
4 = 788 + ΔH_hydration
ΔH_hydration = -784 kJ mol? ¹

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Vishal Baghel

Contributor-Level 10

In isoelectronic species nuclear charge can be approximated as
Nuclear charge ≈ z / no. of electrons
Al³? Mg²? Na? F? O²? N³?
Nuclear Charge: 13/10 12/10 11/10 9/10 8/10 7/10
Minimum nuclear charge is in N³? and maximum is in Al³?
So order should be
Al³? < Mg? < Na? < F? < O? < N?

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Vishal Baghel

Contributor-Level 10

Using VSEPR, L.P - B.P repulsion we can safely say that CH? should have the highest bond angle among the given

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Vishal Baghel

Contributor-Level 10

P = constant


m (dv/dt) = P
∫? vdv = P/m ∫? dt
v²/2 = Pt/m ⇒ v = (2Pt/m)¹/²
dx/dt = √ (2P/m) t¹/²
∫? dx = √ (2P/m) ∫? t¹/² dt
x = √ (2P/m) (t³/² / (3/2) = √ (2P/m) * (2/3) * t³/²
= (2/3) * 27 = 18

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Vishal Baghel

Contributor-Level 10

V_rms = √ (3RT/M)
V_N? = V_H?
√ (3RT_N? / M_N? ) = √ (3RT_H? / M_H? )
573/28 = T_H? /2
⇒ T_H? = 40.928

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Vishal Baghel

Contributor-Level 10

L_i = L_f
mvL = Iω
mvL = (ML³/3 + mL²)ω


Before collision
After collision
0.1 * 80 * 1 = (0.9 * 1²)/3 + 0.1 * 1²)ω
8 = (3/10 + 1/10)ω 8 = (4/10)ω ω = 20 rad/sec

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