Class 12th

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2 months ago

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V
Vishal Baghel

Contributor-Level 10

In H2O (polar solvent) dibromophenol derivative and in CS2 (non-polar solvent moneobromo phenol derivate is obtained.

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Vishal Baghel

Contributor-Level 10

Therefore option (b) is correct.

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Vishal Baghel

Contributor-Level 10

i = m t h e o r m a p p = 3 0 m a p p

Δ T b = i k b . m ] H A m x m = H + x + A x

0 . 0 1 5 6 = ( m * x m ) * 0 . 5 2 * m

m + x = 0.03

x = 0 . 0 1 i = 1 . 5 = 3 0 m a p p m a p p p = 2 0

 

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Vishal Baghel

Contributor-Level 10

G l a = κ .1

Λ m = κ * 1 0 0 0 n / ( l * a ) * 1 0 3 .2

from (1) & (2) Λ m = 2 Ω 1 c m 2 m o l 1

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Vishal Baghel

Contributor-Level 10

Addition on triple bond takes place by the addition of hydrogen

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Vishal Baghel

Contributor-Level 10

N = qvB

μ q v B = m d v d t = m v d v d S

μ q B S = m v

S = 3 * 1 0 6 * 4 0 . 3 * 1 0 6 * 0 . 2 = 2 0 0 m

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Vishal Baghel

Contributor-Level 10

1 u + 1 1 0 = 1 3 5

1 u = 1 3 5 1 1 0 = 2 7 7 0 = 1 1 4 1 u = 1 3 5 1 2 9 = 6 4 3 5 * 2 9 u = 3 5 * 2 9 6 4 = 1 5 . 8 5 t o 1 5 . 8 6

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New answer posted

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V
Vishal Baghel

Contributor-Level 10

k Q e 0 . 1 2 + 1 2 m u 2 = k Q e 0 . 1 5 + 1 2 m u 2

k Q e * 0 . 0 3 0 . 1 2 * 0 . 1 5 = 1 2 m * ( v 2 u 2 )

Q = 9 . 1 * 9 9 * 1 0 1 1 1 2

= 7 5 . 0 7 5 * 1 0 1 2 4 π * ( 0 . 1 ) 2 = 5 . 9 7 n C / m 2

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