Class 12th

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New answer posted

a year ago

0 Follower 4 Views

R
Raj Pandey

Contributor-Level 9

R − N H 2                 → 2 7 3 K H N O 2 ( a q . )               R − N 2               ⊕ → 2 9 8 K H 2 O / − N 2 ↑                         R − O H

1° aliphatic amine           Diazonium salt                Alcohol

New answer posted

a year ago

0 Follower 1 View

A
alok kumar singh

Contributor-Level 10

It is aldol condensation.

New answer posted

a year ago

0 Follower 14 Views

R
Raj Pandey

Contributor-Level 9

kindly consider the following Image 

 

New answer posted

a year ago

0 Follower 4 Views

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

New answer posted

a year ago

0 Follower 17 Views

R
Raj Pandey

Contributor-Level 9

kindly consider the following Image 

 

New answer posted

a year ago

0 Follower 17 Views

R
Raj Pandey

Contributor-Level 9

kindly consider the following Image 

 

New answer posted

a year ago

0 Follower 6 Views

A
alok kumar singh

Contributor-Level 10

CoCl3.NH3 + AgNO3 → A g C l ↓ ( 2 m o l )

[ C o ( N H 3 ) 5 C l ] C l 2 + A g N O 3 → A g C l ↓ ( 2 m o l )  

x = 5

New answer posted

a year ago

0 Follower 10 Views

R
Raj Pandey

Contributor-Level 9

kindly consider the following Image 

 

New answer posted

a year ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

M n 2 + → t 2 g 1 1 1 e g 1 1

(Number of unpaired electron = 5)

μ S = 3 5 = 5 . 9 1 ≅ 6

New answer posted

a year ago

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A
alok kumar singh

Contributor-Level 10

K = A . e − E a / R T = ( 6 . 5 * 1 0 2 ) e − 2 6 0 0 0 K / T  

E a 8 . 3 1 4 = 2 6 0 0 0

Ea = 216.164kJ/mol ≅ 216

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