Class 12th

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New answer posted

2 months ago

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V
Vishal Baghel

Contributor-Level 10

Kindly go through the answers 

(8.00)

New answer posted

2 months ago

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V
Vishal Baghel

Contributor-Level 10

t = t 1 / 2 l o g 2 . l o g V V V t 2 0 = 1 0 l o g 2 . l o g V V 2 5

V = 3 3 . 3 3 m l

New answer posted

2 months ago

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R
Raj Pandey

Contributor-Level 9

T (300Kto70K)

TRmeta1R ( A l ) ( Si ) semi? conductor

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2 months ago

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R
Raj Pandey

Contributor-Level 9

mg In equilibrium, Fe=T sin θ

mg=T cos θ

 tan θ=Femg=q24π0x2*mg

also  tan θs?=x/2l

Hence, x 2 l = q 2 4π0x2*mg

x 3 = 2 q 2 p 4πε0mg

x=(q2l2π0mg)1/3

Therefore xl1/3

New question posted

2 months ago

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New answer posted

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V
Vishal Baghel

Contributor-Level 10

Ammonical AgNO3   

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New answer posted

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V
Vishal Baghel

Contributor-Level 10

(Cr, Mn) -> Thermite reduction

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2 months ago

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V
Vishal Baghel

Contributor-Level 10

Sucrose D (+) glucose + D (-) Fructose

  [ α ] = + 6 6 . 5 ° [ α ] = + 5 2 . 5 ° [ α ] = 9 2 . 8 °

Thus rotation changes from positive to negative after hydrolysis. Due to this reason hydrolysis of sucrose is known as inversion and mixture after hydrolysis is known as invert sugar.

Therefore option (B) is correct.

New answer posted

2 months ago

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V
Vishal Baghel

Contributor-Level 10

[ Z n ( g l y ) 2 ] is optically active compound

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