Class 12th
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New answer posted
5 months agoContributor-Level 10
One of the men spent 2517 – 1378 = 1139, he is Aman. This is the only possibility as we add Rs. 1378 even to the least amount Rs. 1193, we will not be able to satisfy all the conditions given simultaneously.
So, the table obtained is:
Raman | Aman | Dev | Sanjay | Kamal |
2234 | 1139 | 1139 | 1340 | 2517 |
(c)
New answer posted
5 months agoNew answer posted
5 months agoContributor-Level 10
One of the men spent 2517 – 1378 = 1139, he is Aman. This is the only possibility as we add Rs. 1378 even to the least amount Rs. 1193, we will not be able to satisfy all the conditions given simultaneously.
So, the table obtained is:
Raman | Aman | Dev | Sanjay | Kamal |
2234 | 1139 | 1139 | 1340 | 2517 |
(c)
New answer posted
5 months agoContributor-Level 10
One of the men spent 2517 – 1378 = 1139, he is Aman. This is the only possibility as we add Rs. 1378 even to the least amount Rs. 1193, we will not be able to satisfy all the conditions given simultaneously.
So, the table obtained is:
Raman | Aman | Dev | Sanjay | Kamal |
2234 | 1139 | 1139 | 1340 | 2517 |
(a)
New answer posted
5 months agoContributor-Level 10
Given are the oxide of alkali and alkaline earth metals which are ionic in nature.
Simple oxide are Li2O, CaO, MgO and K2O.
Peroxide is Na2O2 and superoxide is KO2.
All simple oxides are diamagnetic as it has no unpaired electron.
New answer posted
5 months agoContributor-Level 10
One of the men spent 2517 – 1378 = 1139, he is Aman. This is the only possibility as we add Rs. 1378 even to the least amount Rs. 1193, we will not be able to satisfy all the conditions given simultaneously.
So, the table obtained is:
Raman | Aman | Dev | Sanjay | Kamal |
2234 | 1139 | 1139 | 1340 | 2517 |
(b)
New answer posted
5 months agoContributor-Level 10
(b)
Y scored 127 in G1 and G3. V scored 130 in G1 itself.
K's mas score could be 28 + 51 + 48 = 127
R's mas score could be 49 + 55 + 22 = 126
S's mas score could be 75 + 50 + 22 = 147
Only R definitely scored less than Y.
Hence, option 2.
New answer posted
5 months agoContributor-Level 10
(c)
Form answer to the first question, the M-index of only R and S can be exactly calculated.
Hence, option (c)
New answer posted
5 months agoContributor-Level 10
(a)
If y2 < 40, then y's R-index = 87 y2 > 47; i.e. 47 < Y's R-index 87
If y2 > 40, then Y's R-index = 87 – 40 = 47
47 ≤ Y's R-index ≤ 87
Similarly,
23 ≤ K's R-index ≤ 51
33 ≤ S's R-index ≤ 55
53 ≤ S's R-index ≤ 75
82 ≤ V's R-index ≤ 130
Any one of Y, K or R could have the lowest R-index.
Hence, option (a).
New answer posted
5 months agoContributor-Level 10
(a)
Consider game against Pakistan (G1).
Runs scored by Y, V and K = 40 + 130 + 28 = 198
Total runs scored = 198/0.9 = 220
Runs scored by R (r1) and S (s1), r1, s1 < 28 and r1+ +s1? 22
Consider the game against South Africa (G2).
Runs scored by K, R and S = 51 + 49 + 75 = 175
Total runs scored = 175/0.7 = 250
Runs scored by Y (y2) and V (v2), y2, v2 < 49 and y2 + v2? 75
Consider the game against Australia (G3).
Runs scored by R, Y and S = 87 + 55 + 50 = 192
Total runs scored = 192/0.8 = 240
Runs scored by V (v3) and K (k3), v3, k3 < 50, v3+ k3? 48
R's M-index = 49
S's M-index = 50
V's M-index? 49
Y's M-index is either 40 or between 41 and 49.
S had the best M-index.
Hence, o
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