Class 12th

Kindly consider the following figure

Because E points along the tangent to the lines of force. If initial velocity is zero then due to the force, it always moves in the direction of E. Hence will always move on some lines of force

In Case I when both are positively charged, due to induction positive charge moves outwards on spheres, increasing effective distance between centres of charge causing magnitude of the force to decrease.

Hybridisation = sp³d²

Shape – square planar

Order of limiting molar conductivity

$O{H}^{-}>S{O}_4^{2-}>C{l}^{-}>C{H}_{3}CO{O}^{-}$

Higher the acidic strength, lower will be the value of pK_a.

Correct order of pK_a is

$C{H}_{3}COOH>C_6{H}_{5}COOH>HCOOH>O_{2}NC{H}_{2}COOH$  

$Xe{F}_2+P{F}_5\to {\left[XeF\right]}^{+}{\left[P{F}_6\right]}^{-}$

  ${\left[Co{\left(N{H}_3\right)}_6\right]}^{3+},N{H}_3$ becomes strong ligand due to +3 oxidation state of cobalt ion. Hence electronic configuration of CO³⁺ is $t_{2g}^6{e}_g^0$  

Haemoglobin is a positive colloid. Hence greater is the charge of anion, more effective will be the coagulation of haemoglobin.

$$ Correct order of coagulating power is $P{O}_4^{3-}>S{O}_4^{2-}>C{l}^{-}$

Electrophoresis : The migration of colloidal particles under the influence of an electric field is known as electrophoresis.