Class 12th

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New answer posted

3 months ago

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A
Aadit Singh Uppal

Contributor-Level 10

There are different types of electromagnetic waves and each of them have different wavelengths. Human eye can only see the light rays which have a minimum wavelength of around 400-700nm. Rays which don't meet this threshold will eventually not be visible to the humans.

New answer posted

3 months ago

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A
alok kumar singh

Contributor-Level 10

From option let it be isosceles where AB = AC then

x = r 2 ( h r ) 2            

 =   r 2 h 2 r 2 + 2 r h

x = 2 h r h 2 . . . . . . . . ( i )        

Now ar ( Δ A B C ) = Δ = 1 2 B C * A L

Δ = 1 2 * 2 2 h r a 2 * h       

then   x = 2 * 3 r 2 * r 9 r 2 4 = 3 2 r f r o m ( i )

B C = 3 r      

So . A B = h 2 + x 2 = 9 r 2 4 + 3 r 2 4 = 3 r

Hence Δ be equilateral having each side of length 3 r .  

 

New answer posted

3 months ago

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V
Vishal Baghel

Contributor-Level 10

Sphalerite is ore of zinc consists of ZnS during its concentration group 1 cyanides are used as depressants like NaCN

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3 months ago

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V
Vishal Baghel

Contributor-Level 10

Major components of gun metal are Cu, Sn and Zn

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3 months ago

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V
Vishal Baghel

Contributor-Level 10

? 1 = 3 5 E 0 ( 0 . 2 ) N m 2 C 1 , a n d ? 2 = 4 5 E 0 ( 0 . 3 ) N m 2 C 1

? 1 ? 2 = 3 * 0 . 2 * 5 5 * 0 . 3 * 4 = 1 2

New answer posted

3 months ago

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A
Aadit Singh Uppal

Contributor-Level 10

It depends on the frequency of the wave. Rays such as Gamma rays, X-Rays etc. have higher frequencies which can lead to harmful impacts if exposed to the human body. These kind of rays cannot be even produced easily unlike low frequency rays.

New answer posted

3 months ago

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A
alok kumar singh

Contributor-Level 10

A 1 + A 2 = 0 π / 2 c o s x d x           

= ( S i n x ) 0 π / 2 = 1           

A 1 = 0 π / 4 ( c o s x s i n x ) d x = ( s i n x + c o s x ) 0 π / 4           

= 2 2 1 = 2 1

S o A 2 = 1 ( 2 1 ) = 2 2 = 2 ( 2 1 )

N o w A 1 A 2 = 1 2

New answer posted

3 months ago

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P
Pallavi Pathak

Contributor-Level 10

The following are the topics covered in this chapter: Electric Field and Field Lines, Gauss's Law, Electric Dipole, Conductors and Insulators, and Electric Flux. 

New answer posted

3 months ago

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V
Vishal Baghel

Contributor-Level 10

L d i d t = V 2 d i = 3 t d t 2 0 i d i = 3 0 4 t d t i = 1 2 A

U = 1 2 L i 2 = 1 2 * 2 * 1 2 2 = 1 4 4 J

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