Complex Numbers and Quadratic Equations

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4 months ago

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Payal Gupta

Contributor-Level 10

27. Kindly go through the solution

New answer posted

4 months ago

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P
Payal Gupta

Contributor-Level 10

26. Kindly go through the solution

New answer posted

4 months ago

0 Follower 2 Views

P
Payal Gupta

Contributor-Level 10

25. Kindly go through the solution

New answer posted

4 months ago

0 Follower 1 View

P
Payal Gupta

Contributor-Level 10

24. Kindly go through the solution

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4 months ago

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P
Payal Gupta

Contributor-Level 10

23. x2 – x + 2 = 0

Comparing the given equation with ax2 + bx + c = 0

We have, a = 1, b = –1 andc = 2

Hence, discriminant of the equation is

b2 – 4ac = (-1)2 – 4 * 1 * 2 = 1 – 8 = –7

Therefore, the solution of the quadratic equation is

New answer posted

4 months ago

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P
Payal Gupta

Contributor-Level 10

21. –x2 + x – 2 = 0

Comparing the given equation with ax2 + bx + c = 0

We have, a = –1, b = 1 and c = –2

Hence, discriminant of the equation is

b2 – 4ac = 12 – 4 * (-1)* (-2) = 1 – 8 = –7

Therefore, the solution of the quadratic equation is

New answer posted

4 months ago

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Payal Gupta

Contributor-Level 10

20x2 + 3x + 9 = 0

Comparing the given equation with ax2 + bx + c = 0

We have, a = 1, b = 3 and c = 9

Hence, discriminant of the equation is

b2 – 4ac = 32 – 4 * 1* 9 = 9 – 36 = –27

Therefore, the solution of the quadratic equation is

New answer posted

4 months ago

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Payal Gupta

Contributor-Level 10

18. x2 + 3 = 0

=>x2 = –3

=>x = ±√3

=>x= ± √3i [since, √-1 = i]

=>x = 0 ± √3i

New answer posted

4 months ago

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P
Payal Gupta

Contributor-Level 10

17. Kindly go through the solution

New answer posted

4 months ago

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P
Payal Gupta

Contributor-Level 10

16. Kindly go through the solution

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