Complex Numbers and Quadratic Equations
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23. x2 – x + 2 = 0
Comparing the given equation with ax2 + bx + c = 0
We have, a = 1, b = –1 andc = 2
Hence, discriminant of the equation is
b2 – 4ac = (-1)2 – 4 * 1 * 2 = 1 – 8 = –7
Therefore, the solution of the quadratic equation is
Upvote 
21. –x2 + x – 2 = 0
Comparing the given equation with ax2 + bx + c = 0
We have, a = –1, b = 1 and c = –2
Hence, discriminant of the equation is
b2 – 4ac = 12 – 4 * (-1)* (-2) = 1 – 8 = –7
Therefore, the solution of the quadratic equation is
Upvote 20. x2 + 3x + 9 = 0
Comparing the given equation with ax2 + bx + c = 0
We have, a = 1, b = 3 and c = 9
Hence, discriminant of the equation is
b2 – 4ac = 32 – 4 * 1* 9 = 9 – 36 = –27
Therefore, the solution of the quadratic equation is
Upvote Class 11 Complex Numbers Ex 5.3 Solutions
18. x2+ 3 = 0
Class 11 Complex Numbers Ex 5.3 Solutions
18. x2+ 3 = 0
18. x2 + 3 = 0
=>x2 = –3
=>x =
=>x= ± √3 [since, √-1 = i]
=>x = 0 ± √3
Upvote Convert the complex number given in Exercise 3 in the polar form:
17. –3
Convert the complex number given in Exercise 3 in the polar form:
17. –3
