Complex Numbers and Quadratic Equations
Get insights from 193 questions on Complex Numbers and Quadratic Equations, answered by students, alumni, and experts. You may also ask and answer any question you like about Complex Numbers and Quadratic Equations
Follow Ask QuestionQuestions
Discussions
Active Users
Followers
New answer posted
5 months agoContributor-Level 10
circle with radius = 3
arg part of a circle (with radius ). no common points
New answer posted
5 months agoContributor-Level 10
So, z lies on perpendicular bisector of (0, 1) and (0, 5) i.e., line y = 2 as |z| = 2 z = 2i x = 0 and y = 2 so, x + 2y + 4 = 0
New question posted
6 months agoTaking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else
Sign Up on ShikshaOn Shiksha, get access to
- 66k Colleges
- 1.2k Exams
- 681k Reviews
- 1800k Answers
