Data Interpretation
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New answer posted
5 months agoContributor-Level 10
Total votes in 2009 = (2.24/44.8)*100=5 crore
Total Votes in 1999 = (1.228/30.7)*100= 4 crore
4 cr. is 20% less than 5 cr.
New answer posted
5 months agoContributor-Level 10
Total admission for each course:
Course 2 = 40 + 80 + 95 + 100 + 110 + 130 = 555,
Course 5 = 100 + 140 + 180 + 200 + 250 + 300 = 234,
Course 4 = 14 + 18 + 10 + 6 + 12 + 16 = 1170,
Course 3 = 80 + 120 + 120 + 110 + 150 + 130 = 710.
New answer posted
5 months agoContributor-Level 10
The greatest decline happened for Course 4 which is =.18-6/18*100 = 66%
New answer posted
5 months agoContributor-Level 10
In the two years, 2018 & 2019, the required percentage is more than 25 % but it happened in 2011 for the first time.
New answer posted
5 months agoContributor-Level 10
Profitable can be either A or D. Then aggressive and honest has to be B and C. Hence, truthful is A or D. And for both A and D the lowest revenue is from S1
New answer posted
5 months agoContributor-Level 10
B is honest according to Statement (I) Atmost only one statement can be true as both give Aggressive and Honest as firm B.Firm B cannot have two names.
New answer posted
5 months agoContributor-Level 10
According to statement (I) aggressive is (B). Then F1. has to be C (as given in neutral statement).
Then statement (II) is also true, F1's the lowest revenue is from Bihar.
New answer posted
5 months agoContributor-Level 10
As F3. has the highest market share hence Truthful Ltd. can be A or C. From neutral statement either B and C are aggressive and honest or A and D are aggressive and honest. According to statement (I), B is profitable, then A and D are aggressive and honest. Then honest total revenue cannot be more than that of profitable, hence statement (II) is false.
New answer posted
5 months agoContributor-Level 10
| Day 1 | Day 2 | Day 3 | Day 4 | Day 5 |
Start Price | 100 | 90 | 80 | 90 | 100 |
End Price | 90 | 80 | 90 | 100 | 110 |
Assume initial number of share with T1 and T2 is X. In the above table T1 by 10 share each on day 1, day 2 and sold 10 shares and day 3, day 4 and day 5.
Total share with T1 is X – 10.
In the above T2 buy share only on day 2.
Total shares with T2 is X + 10.
T2 had 20 shares more than T1.
Therefore at the end of day 3 the price of share is Rs. 90
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