DIMENSIONAL FORMULAE
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Given below are two statements : One is labeled as Assertion A and the other is labeled as Reason R.
Assertion A : Product of Pressure (P) and time (t) has the same dimension as that of coefficient of viscosity.
Reason R : Coefficient of viscosity =
Choose the correct answer from the options given below:
Given below are two statements : One is labeled as Assertion A and the other is labeled as Reason R.
Assertion A : Product of Pressure (P) and time (t) has the same dimension as that of coefficient of viscosity.
Reason R : Coefficient of viscosity =
Choose the correct answer from the options given below:
Pressure × time
Coefficient of viscosity,
If force [F], acceleration [A] and time [T] are chosen as the fundamental physical quantities. Find the dimensions of energy.
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If force [F], acceleration [A] and time [T] are chosen as the fundamental physical quantities. Find the dimensions of energy.
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E ∝ F? A? T?
[M¹L²T? ²] ∝ [M¹L¹T? ²]? [LT? ²]? [T]?
a = 1
a + b = 2 ⇒ b = 1
-2a - 2b + c = -2
⇒ c = 2
a = 1 b = 1 c = 2
E ∝ [F] [A] [T²]
Match List I with List II.
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Match List I with List II.
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[C] = Q/V = Q/ (W/Q) = Q²/W = (A²T²)/ (M¹L²T? ²) = M? ¹L? ²T? A²
[ε? ] = C/ (4πr²) * (Fr²/q²) = M? ¹L? ³T? A²
[µ? ] = 4πrF/I²l = M¹L¹T? ²A? ²
[E] = F/q = (MLT? ²)/ (AT) = MLT? ³A? ¹
Match List-I with List-II.
List-I List-II
(A) Torque (i) MLT-1
(B) Impulse (ii) MT-2
(C) Tension (iii) ML2T-2
(D) Surface Tension (iv) MLT-2
Choose the most appropriate answer from the option given below:
Match List-I with List-II.
List-I List-II
(A) Torque (i) MLT-1
(B) Impulse (ii) MT-2
(C) Tension (iii) ML2T-2
(D) Surface Tension (iv) MLT-2
Choose the most appropriate answer from the option given below:
(a) Torque ® ML2T-2 ↑ (iii)
(b) Impulse ® MlT-1 ↑ (i)
(c) Tension ↑ MLT-2 ↑ (iv)
(d) Surface Tension ↑
