Search Colleges, Courses, Exams, Questions and Articles

Ask a query on 8879100846 Ask Login | Sign Up

 

 
› Tags › Doppler Effect Derivation

Doppler Effect Derivation

Follow Ask Question
1

Questions

0

Discussions

1

Active Users

0

Followers

New answer posted

a month ago

Doppler Effect Derivation Class 11th

As a train moving with constant speed crosses the platform, the apparent frequency heard by a person standing on the platform during approach and recession differ by 2% of the actual frequency of the horn. If the speed of sound is 330 m/s, find the approximate speed of the train.
0 Follower 2 Views

V
Vishal Baghel

Contributor-Level 10

f? = f? (330/ (330-V) f? = f? (330/ (330+V)
(f? - f? )/f? * 100 = 2% ⇒ (330/ (330-V) - (330/ (330+V) = 0.02
⇒ 330 [ (2V)/ (330)²-V²)] = 0.02 ⇒ 330V = 0.01 * (330)² ⇒ V = 3.3 m/s (approx.)

    Get authentic answers from experts, students and alumni that you won't find anywhere else

    Sign Up on Shiksha

    On Shiksha, get access to

    • 65k Colleges
    • 1.2k Exams
    • 682k Reviews
    • 1800k Answers

    Share Your College Life Experience

    Write a Review
    Community GuidelinesUser Points System
    QuestionsDiscussionsTags

    ×
    ×

    This website uses Cookies and related technologies for the site to function correctly and securely, improve & personalise your browsing experience, analyse traffic, and support our marketing efforts and serve the Core Purpose. By continuing to browse the site, you agree to Privacy Policy and Cookie Policy.