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Doppler Effect Class 11th

An observer moves towards a stationary source of sound with a velocity one-fourth of the velocity of sound. What is the percentage increase in the apparent frequency?

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Vishal Baghel

Contributor-Level 10

$f' = f ⌊ \frac{v + \frac{v}{4}}{v} ⌋ = \frac{5 f}{4}$

$\Rightarrow \frac{f'}{f} = \frac{5}{4}$

$\Rightarrow \frac{Δ f}{f} = \frac{1}{4}$

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New answer posted

2 months ago

Doppler Effect Class 11th

The driver of bus approaching a big wall notices that the frequency of his bus's horn changes from 420 Hz to 490 Hz when he hears it after it gets reflected from the wall. Find the speed of the bus if speed of the sound is 330 ms⁻¹ :

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Vishal Baghel

Contributor-Level 10

f? = 420 Hz
f? = (V? + V)/ (V? - V) f? = 490
(330 + V)/ (300 - V) 420 = 490
(330 + V)6 = 7 (330 – V)

13 V = 330
V = 33/13 (m/s)
= 91 (km/hr)

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2 months ago

Doppler Effect Class 11th

A driver in a car, approaching a vertical wall notices that the frequency of his car horn, has changed from 400 Hz $\frac{}{_{}} \frac{}{_{}^{}}$ to 400 Hz $\frac{}{_{}^{}}$ , when it gets reflected from the wall. If the speed of sound in air is 345 m/s , then the speed of the car is:

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Vishal Baghel

Contributor-Level 10

f? = frequency heard by wall = f_s (v_s/ (v_s - v_c)
f? = frequency heard by driver after reflection from wall

f? = (v_s + v_c)/v_s)f? = (v_s + v_c)/ (v_s - v_c)f?
f? /f? = (v_s - v_c)/ (v_s + v_c)
48/44 = (v_s - v_c)/ (v_s + v_c)
12 (v_s + v_c) = 11 (v_s - v_c)
23v_c = v_s
v_c = v_s/23 = 345/23 = 15 m/s
= (15 * 18)/5 = 54 km/hr

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New answer posted

2 months ago

Doppler Effect Class 11th

A stationary observer receives sound from two identical tuning forks, one of which approaches and the other one recedes with the same speed (much les than the speed of sound). The observers hears 2 beats/sec. The oscillation frequency of each tuning fork is $v_{0} = 1400 H z$ and the velocity of sound in air is $350 m / s$ . The speed of each tuning fork is close to:

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alok kumar singh

Contributor-Level 10

$f_{1} = f_{o} (\frac{v}{v - v_{s}}) f_{1} - f_{2} = 2$

$f_{2} = f_{o} (\frac{v}{v + v_{s}}) f_{0} v [\frac{v + v_{s} - (v - v_{s})}{v^{2} - v_{s}^{2}}] = 2; \frac{2 f_{0} v v_{s}}{v^{2} - v_{s}^{2}} = 2$

$? v_{s} ? v ∴ v_{s} = \frac{1}{4} m / s$

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2 months ago

Doppler Effect Class 11th

A stationary observer receives sound from two identical tuning forks, one of which approaches and the other one recedes with the same speed (much les than the speed of sound). The observers hears 2 beats/sec. The oscillation frequency of each tuning fork is $v_{0} = 1400 H z$ and the velocity of sound in air is $350 m / s$ . The speed of each tuning fork is close to:

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New question posted

3 months ago

Doppler Effect Physics NCERT Exemplar Solutions Class 12th Chapter Fifteen

The driver of bus approaching a big wall notices that the frequency of his bus's horn changes from $420 H z$ to $490 H z$ when he hears it after it gets reflected from the wall. Find the speed of the bus if speed of the sound is $330 {m s}^{- 1}$ :

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