Guru Nanak Institute of Technology - GNIT
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New answer posted
a year agoContributor-Level 6
Candidates can check the GNIT IPU cutoff at the official website of the college.
Tech Cutoff 2023- GGSIPU has released the IPU B.Tech 2023 cutoff on the official website. The cutoff for IPU B.Tech admission 2023 has been released separately for JEE Main aspirants and Biotechnology. Candidates can check the cutoff of IPU 2023 from the website as well as from shiksha.
New answer posted
a year agoContributor-Level 6
Yes you can get into GNIT IPU with 75 percentile. You may not be able to get seat in higher branch.
The 2023 IPU CET cutoff for JEE Main is 90 percentile or higher for the General Category and 75 percentile or higher for the EWS Category.
The Greater Noida Institute of Technology (GNIT) IPU selects students based on their score in JEE Main exam and their 12 passed out students.
Here are some 2022 cutoffs for GNIT:
MHT CET: 534660 for general category students in Electronics and Communication Engineering.
JEE MAIN: 153047 for general category students in B TECH (Information Technology
New answer posted
a year agoContributor-Level 6
While a 60% score in Class 12th is a decent achievement, admission requirements typically also include performance in entrance exams such as JEE Main or IPU CET.
Yes, you can get admission in GNIT IPU with 60% in class 12. The criteria according to the website of GNIT IPU is listed below:
Pass in 12th Class of 10+2 of CBSE or equivalent with a minimum aggregate of 50% marks in Physics, Chemistry and Biology provided the candidate has passed in each subject separately. A candidate also must have passed in English (core or elective or functional) as a subject of study in the qualifying examination.
New answer posted
2 years agoBeginner-Level 1
| Courses | Eligibility |
|---|---|
| B.E. / B.Tech | Candidate must have passed pass Diploma in Engineering/ Technology from an AICTE approved institution with at least 45% marks (40% for SC/ ST/ OBC-A/ OBC-B/ PwD) or equivalent CGPA. or Candidate must have passed B.Sc. Degree from any recognised college/ university with at least 45% marks (40% for SC/ ST/ OBC-A/ OBC-B/ PwD) and must have passed 10+2 with Mathematics as a subject. The candidate, if admitted, will have to clear the subjects of Engineering Mechanics and Engineering Graphics / Engineering Drawing of the 1st year Degree Course in Engineering/Technology along with their second year subjects. Candidate must be citizen of India. The above mentioned upper age limit is for B.Sc. candidates as on 31.12.2018. There is no upper age limit for Diploma holders in Engineering/ Technology. |
| BCA | Candidate passed 12th/equivalent in Mandatory subjects as mentioned from any recognised institute/board are eligible to apply. |
| BBA | Candidate passed 12th/equivalent with Mandatory subject from any recognised institute/board are eligible to apply. |
| M.E./M.Tech | Candidates completed M.Sc. in Computer Science/ComputerApplications/Mathematics (with Computer Science Specialisation), MCA (with BCA or B.Sc. with Mathematics compulsory and any of the others from Statistics, Physics, Electronics or Computer Science) from any recognised institute/ university are also eligible to apply. |
| After 10th Diploma | Candidate must have passed the 10th standard (Madhyamik) Examination of the West Bengal Board of Secondary Education or its equivalent examination from any recognized Board/ Council/ Institute. Candidate appearing in the Secondary (Madhyamik) Examination of the West Bengal Board of Secondary Education or its equivalent examination are also eligible to apply. Candidate should not be born after 01.07.2008 and there is no upper age limit. |
| MCA | Candidate who qualify eligibility as given below can also apply: Module 4 Candidate must have obtained a BSc Honours degree under (10+2+3) pattern in any discipline from a UGC recognised University/Institute with a minimum of 60% marks in Aggregate (45% marks for SC/ST/OBC-A/OBC-B candidates) along with at least 55% marks in Mathematics. They must secure at least 60% marks in Secondary and Higher Secondary or equivalent level from recognised Boards with at least 60% marks in Mathematics at each level. Candidate have to secure 60% marks (45% marks for SC/ST/OBC-A/OBC-B candidates) at each level of education. |
New answer posted
2 years agoContributor-Level 7
The fee structure for B.Tech programs at Guru Gobind Singh Indraprastha University (GNIT IPU) is as follows:
1.The total course fee for B.Tech programs at GNIT IPU is INR 4.48 Lacs for the 4-year duration of the program
2. The hostel fee is calculated based on the 1st year and is included in the total fee of INR 4.48 Lakh.
The meal plan is not included in the mentioned fee.
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