Institute of Technology Eligibility

To be eligible for B.E./B.Tech course at Sur Institute of Technology and Sports Complex  you have to complete class 12 with Physics, Mathematics, Chemistry / Biotechnology /Biology /Computer Science / Computer Application as compulsory subjects.Admissions to courses is either entrance-based or merit-based. The institute accepts multiple state/ national-level entrance exams such as JEE Mains, WBJEE, JEXPO, etc. to shortlist candidates for admission. Prospective candidates have to meet the eligibility criteria defined by the institution and then fill out the application form.

To be eligible for B.E./B.Tech course at Sur Institute of Technology and Sports Complex  you have to complete class 12 with Physics, Mathematics, Chemistry / Biotechnology /Biology /Computer Science / Computer Application as compulsory subjects.Admissions to courses is either entrance-based or merit-based. The institute accepts multiple state/ national-level entrance exams such as JEE Mains, WBJEE, JEXPO, etc. to shortlist candidates for admission. Prospective candidates have to meet the eligibility criteria defined by the institution and then fill out the application form.

The minimum requirement to be eligible for B.E/ B.Tech course at World Institute of Technology (WIT) is a candidate must have passed the 10 + 2 examination from a recognised board and have obtained a minimum of 45% marks in Physics, Mathematics & Either Chemistry, Computer Science or Biology. In addition, candidates need to have passed their JEE Main examination plus have a minimum passing percentile of 50. College also provides lateral entry admissions in Diploma with least rating of 50% of distinction. Total intake capacity for B.E/B.Tech is 540 students total and 25% fees is reserved for students from Haryana.

If you meet the eligibility requirements for the B.E/B.Tech  of the institute then that is the selection criteria. The minimum requirement is 10th, and 12th should pass with a minimum 45% . This is the basic criteria. You must have decent marks in JEE exam.

The eligibility criteria for BE/B.Tech is students must have passed in the Higher Secondary Examination with Physics, Chemistry, and Mathematics ( compulsory subjects.) With minimum 45%, you can get admission through entrance exams like JEE, other than this students belonging to the State of Maharashtra are required to secure a valid score in the State Common Entrance Test.

To be eligible for admission to a B.E. or B.Tech course at Raj Kumar Goel Institute of Technology (RKGIT), Ghaziabad, you must meet the following criteria:

Pass class 12th or equivalent with Physics and Mathematics as compulsory subjects

Pass in one of the following subjects: Chemistry, Biotechnology, Biology, or Technical Vocational

Pass in the class 12th/equivalent examination in 2020, 2021, or appear in 2022

The eligibility criteria for B.E. / B.Tech at NIT - Narula Institute of Technology are as follows.Educational Qualification: Candidate should have completed 10+2 with a minimum of 45% marks in Physics and Mathematics along with any one of the following subjects: Chemistry, Biotechnology, Biology, Computer Science, or Technical Vocational subjects. For the reserved categories, the percentage required is 40%.Entrance Exam: For seeking admission to B.E. / B.Tech courses offered at the college, an applicant has to be eligible in either of JEE Main or WBJEE.

To be eligible for admission to the B.Tech programme at NIT Narula Institute of Technology, candidates must have completed their 10+2 education from a recognised board with at least 75% marks (or equivalent) in the qualifying examination. Additionally, candidates are required to clear the Joint Entrance Examination (JEE) Main, which is mandatory for admission. A valid JEE Main score is essential to be considered for the B.Tech courses offered at the institute. The total number of seats for each branch may vary, but the overall admission is competitive, based on both academic merit and JEE Main performance.