JEE
Get insights from 15.3k questions on JEE, answered by students, alumni, and experts. You may also ask and answer any question you like about JEE
Follow Ask QuestionQuestions
Discussions
Active Users
Followers
New answer posted
a year agoContributor-Level 10
The JoSAA counselling is free of charge for candidates. They have to pay no fee to get registered for counselling. However, after the seat confirmation, candidates have to pay a certain amount for confirmation of admission. After the admission process is completed, the given amount will be added to the semester fees of the candidate.
The amount for seat confirmation differs from category to category:
General and OBC Category: INR 35,000.
SC/ST/Gen-PwD/OBC-NCL-PwD/SC-PwD or ST-PwD Categories - INR 15,000
To know more about theexamination, candidates can refer to the official website or Shiksha.
New question posted
a year agoNew answer posted
a year agoContributor-Level 9
According to the NTA PwD category's JEE Main 2023 cutoff data, the lowest cutoff is 0.0013527. The highest cutoff, 90.7788642, is for the general category. PwD applicants who achieve an NTA scorer higher than 0.0013527 are qualified to take the JEE Advanced exam to be admitted to IITs. 2023 saw a decrease in the PwD cutoff to 0.0013527 from 0.0031029 in 2022.
New answer posted
a year agoBeginner-Level 5
Congratulation for getting excellent percentage in JEE . you can easily getting seat in NIT (National Institute of Technology). The seats are allotted on the basis of several categories that are prevalent like ST, SC, GEN, OBC, PWD. In this year admission is total 23954 seats will be offered at NIT. The NIT contains the total number of seats offered in the particular specializations for an NIT.
New answer posted
a year agoContributor-Level 10
The JEE Mains results will be made available online by NTA via the official website. On its official website, the NTA has made available the JEE Main 2024 Paper 2 result. The JEE Main 2024 session 2 paper 2 result is available to candidates at jeemain.nta.ac.in. The application number and date of birth are the login credentials needed to get the JEE Main Paper 2 result in 2024. The JEE Main 2024 paper 2 toppers have also been revealed by NTA along with the results. On April 24, the NTA released the JEE Main 2024 Session 2 Paper 1 result. The JEE Main Result Login 2024 has been made available by NTA on the official websites jeemain.nta.
New answer posted
a year agoContributor-Level 6
SASTRA University takes the cutoff for admission in B.TECH as follows-
If a student secures a JEE Main Score of 185 and normalized +2 total marks of 95%, the combined score of the student will be (0.25*185)+(0.75*95) = 117.50. They ask applicants to submit the JEE scores in the application form even if they are not qualified for the Advanced or they don't have the cut-off prescribed by MHRD. SASTRA does not use the CBSE cut-off for its admission but its own ranks calculated based on +2 marks and JEE (Main) scores.
As you have 90% in board exam you can easily get ECE branch at SASTRA University, Kumbakonam campus. But you should try
New answer posted
a year agoContributor-Level 10
With this rank, it is highly unlikely to get admission to VIT campuses. The cut-off for VIT campuses is generally high.
As per the data available, candidates selected for VIT based on JEE had under 30000 rank, so a 126344 rank will not be able to provide you admission to B.Tech CSE course at VIT.
I hope it will help.
New answer posted
a year agoBeginner-Level 4
With JEE main rank of 600000 in general and 250000 in OBC. It is difficult to secure top colleges li IITS, NITS
But you can try for state engineering college many state colleges have there own entrance exam or accept JEE Mains score but have different cut offs
You can try for private engineering college many top private colleges have relatively higher cutoff but can accessible with your rank
- Vellore institute of technology (VIT)
- Manipal Institute of Technology (MIT)
- SRM Institute of Science and Technology
- Amity University
- Amity University
- Sharda University
- KIIT (Kalinga Institute of Industrial Technology)
New answer posted
a year agoBeginner-Level 2
Hi, Yes, you can. In SASTRA, 50% of seats for B. Tech courses are prior filled based on the JEE Main score along with class 12th marks. Rest seats are filled based on the normalized aggregate score of class 12th. To be eligible for the course, you must have scored 60% in class 12th from any recognized board and physics and mathematics as compulsory subjects.
New answer posted
a year agoBeginner-Level 2
Yes, you can get into the B.Tech Aerospace Engineering programme at SASTRA University with a 62.9 percentile in JEE Mains and 80.1% (484 marks) in board exams
SASTRA University draws up a merit list for admissions based on the normalized percentage, which takes into account both JEE Mains percentile and board exam percentage
While the exact cutoff varies each year, a 62.9 percentile in JEE Mains and 80.1% in board exams should be competitive enough to secure a seat in the B.Tech Aerospace Engineering programme at SASTRA
The B.Tech Aerospace Engineering programme at SASTRA is a 4-year undergraduate programme that covers topics like aerodyn
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else
Sign Up on ShikshaOn Shiksha, get access to
- 66k Colleges
- 1.2k Exams
- 687k Reviews
- 1800k Answers