Maths NCERT Exemplar Solutions Class 11th Chapter Four

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alok kumar singh

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Kindly go through the solution

 

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alok kumar singh

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(ap-b)²+ (bp-c)²+ (cp-d)²=0 ⇒ p=b/a=c/b=d/c. a, b, c, d are in G.P.

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alok kumar singh

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Determinant = -2-sin2x. Max -1, min -3. (m, M)= (-3, -1).

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alok kumar singh

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Kindly go through the solution

(3!)³ (4!)

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alok kumar singh

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p∨ (¬p∧q) = (p∨¬p)∧ (p∨q)=T∧ (p∨q)=p∨q. Negation is ¬p∧¬q.

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alok kumar singh

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Family of planes: x+y+z+1+? (2x-y+z+3)=0. Parallel to line means dot product of normals is zero.

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alok kumar singh

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(80+1)? /8 = (¹C?80? +.+¹C? )/8. Remainder is 1/8.

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alok kumar singh

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S.D.=√ (Σ (x-a)²/n - (Σ (x-a)/n)²) = √ (a-1).

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alok kumar singh

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Kindly go through the solution

BONUS

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alok kumar singh

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Average speed = (f (t? )-f (t? )/ (t? -t? ) = a (t? +t? )+b.
Instantaneous speed = f' (t)=2at+b.
2at+b=a (t? +t? ) ⇒ t= (t? +t? )/2.

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