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New answer posted
11 months agoContributor-Level 9
………(i)
………(ii)
………(iii)
Centre of the circle given by solving (i) & (ii)
Again is tangent to the circle.
New question posted
11 months agoNew question posted
11 months agoNew answer posted
11 months agoContributor-Level 9
gen term = 
For constant term
36 – 3r – rk = 0
for r = 1, 2, 4

Possible values of k = 3, 1
New question posted
11 months agoNew answer posted
11 months agoContributor-Level 9
A = {1, 2, 3, ….50}
R1 = (2, 1), (2, 2), (2, 4)…. (2, 32)
(3, 1) (3, 3) (3, 9) (3, 27)
(13, 1) (13, 13) etc.
R2 = { (2, 1), (2, 2), (3, 1), (3, 3), (5, 1), (5, 5), (7, 1), (7, 7), (1, 1), (11, 11)…}
contains only 9 elements.
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