NIT Rourkela - National Institute of Technology

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New question posted

3 months ago

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New answer posted

3 months ago

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R
Rashmi Sinha

Contributor-Level 10

For candidates belonging to the OBC AI category, the closing rank was  1011 for admission to the CSE course. The cutoff rank varies for different courses, specialisations, rounds, and categories. The lower the cutoff rank, the higher the chances of getting admission to your desired course and college. Candidates can refer to the table below to view the NIT Rourkela JEE Main cutoff 2025 for Round 1 for OBC AI category students:

CourseJEE Main Round 1 Cutoff 2025 
Computer Science and Engineering (4 Years, Bachelor of Technology)1011
Artificial Intelligence (4 Years, Bachelor of Technology)1258
Electronics and Communication Engineering (4 Years, Bachelor of Technology)1902
Electrical Engineering (4 Years, Bachelor of Technology)3473
Electronics and Instrumentation Engineering (4 Years, Bachelor of Technology)3641
Mechanical Engineering (4 Years, Bachelor of Technology)4819
Chemical Engineering (5 Years, Bachelor and Master of Technology (Dual Degree))6210
Chemical Engineering (4 Years, Bachelor of Technology)6340
Civil Engineering (4 Years, Bachelor of Technology)7960
Industrial Design (4 Years, Bachelor of Technology)8482
Metallurgical and Materials Engineering (4 Years, Bachelor of Technology)8827
Mathematics (5 Years, Integrated Master of Science)9201
Ceramic Engineering (4 Years, Bachelor of Technology)9483
Biomedical Engineering (4 Years, Bachelor of Technology)9577
Physics (5 Years, Integrated Master of Science)9958
Mining Engineering (4 Years, Bachelor of Technology)10124
Metallurgical and Materials Engineering (5 Years, Bachelor and Master of Technology (Dual Degree))10395
Biotechnology (4 Years, Bachelor of Technology)10504
Ceramic Engineering and M.Tech Industrial Ceramic (5 Years, Bachelor and Master of Technology (Dual Degree))10733
Chemistry (5 Years, Integrated Master of Science)10799
Food Process Engineering (4 Years, Bachelor of Technology)11208
Life Science (5 Years, Integrated Master of Science)11814

New answer posted

3 months ago

0 Follower 16 Views

R
Rashmi Sinha

Contributor-Level 10

For the General AI category, NIT Rourkela JEE Main cutoff 2025 varied from 3122 to 34766, wherein Computer Science and Engineering was the toughest specialisation. BTech admission to this institution is done through the JEE Main entrance exam score, followed by the JoSSA counselling process, which goes on for multiple rounds.

Below is a table provided detailing NIT Rourkela BTech cutoff 2025 for Round 1 for the General AI candidates. Other categories, round and quota, will have different cutoffs.

CourseJoSAA Round 1 Cutoff 2025
B.Tech. in Computer Science and Engineering3122
B.Tech. in Artificial Intelligence3650
B.Tech. in Electronics and Communication Engineering5109
B.Tech. in Electronics and Instrumentation Engineering8167
B.Tech. in Electrical Engineering9416
B.Tech. in Mechanical Engineering12248
B.Tech. in Chemical Engineering15509
Integrated B.Sc. + M.Sc. in Physics16278
B.Tech. + M.Tech. in Chemical Engineering16985
B.Tech. in Biomedical Engineering22637
B.Tech. in Industrial Design22900
Integrated B.Sc. + M.Sc. in Mathematics23032
B.Tech. in Civil Engineering23208
B.Tech. in Biotechnology23562
B.Tech. in Metallurgical and Materials Engineering26442
B.Tech. in Ceramic Engineering26762
Integrated B.Sc. + M.Sc. in Chemistry29185
B.Tech. in Mining Engineering29975
B.Tech. + M.Tech. in Metallurgical and Materials Engineering30376
Integrated B.Sc. + M.Sc. in Life Science30511
B.Tech. in Ceramic Engineering + M.Tech. in Industrial Ceramic Engineering31064
B.Tech. + M.Tech. in Mining Engineering34630
B.Tech. in Food Process Engineering34766

 

New answer posted

4 months ago

0 Follower 36 Views

C
Chandan Kumar

Beginner-Level 3

You can get CSE in GFTI as per the JoSSA counselling cutoff last year. You cannot get any branch, like CSE, ECE in NIT at this rank.

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