physics ncert solutions class 11th

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New answer posted

a month ago

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R
Raj Pandey

Contributor-Level 9

Layers of atmosphere are in order of (from bottom) troposphere, stratosphere, mesosphere, thermosphere.

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a month ago

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A
alok kumar singh

Contributor-Level 10

F = (i + 2j + 3k)N
r = (4 - 1)i + (3 - 2)j + (-1 - 1)k)
τ = r x F
= (3i + j - 2k) x (i + 2j + 3k)
ijk
3 1 -2 ⇒ I (3 + 4) - j (11) + (6-1)k
1 3
7i - 11j + 5k
|τ| = √121 + 25 + 49
|τ| = √195 ; x = 195

New answer posted

a month ago

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A
alok kumar singh

Contributor-Level 10

Use the equation to find ' N ':
P = 2/3 (v) (N/V) (1/2 mu²)

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a month ago

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A
alok kumar singh

Contributor-Level 10

As Torque net = 0
Hence, L = constant
Iω = (3I + I)ω'
ω' = ω/4
Loss in K.E. = 1/2 Iω² - 1/2 (I + 3I)ω²/16 = 1/2 Iω² (1 - 1/4)
Fractional loss = (3/4 * 1/2 Iω²)/ (1/2 Iω²) = 3/4

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a month ago

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A
alok kumar singh

Contributor-Level 10

Mean relaxation time T = λ/V? = λ / √ (8RT/πm)
∴ T ∝ 1/√T

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a month ago

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A
alok kumar singh

Contributor-Level 10

(n)λ = 5
(n, m): Integers
(2m+1)/2)λ = 3/2
⇒ (3/2)/5 = (2m+1)/ (2n)
⇒ 3n = 10m + 5
N, m are integers.
So, m = 1, n = 5, λ = 1
m = 4, n = 15, λ = 1/3
m = 7, n = 25, λ = 1/5

New answer posted

a month ago

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V
Vishal Baghel

Contributor-Level 10

K = Q r Δ x Δ A T

M L 2 T - 2 ( L ) L 2 ( θ ) ( T ) M 1 L 1 - T - 3 θ - 1

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a month ago

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A
alok kumar singh

Contributor-Level 10

Frequency of collisions = 1/T = Vavg/λ = 600/ (3 * 10? ) = 2 * 10? sec? ¹

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