physics ncert solutions class 11th
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New answer posted
a month agoContributor-Level 9
Layers of atmosphere are in order of (from bottom) troposphere, stratosphere, mesosphere, thermosphere.
New answer posted
a month agoContributor-Level 10
F = (i + 2j + 3k)N
r = (4 - 1)i + (3 - 2)j + (-1 - 1)k)
τ = r x F
= (3i + j - 2k) x (i + 2j + 3k)
ijk
3 1 -2 ⇒ I (3 + 4) - j (11) + (6-1)k
1 3
7i - 11j + 5k
|τ| = √121 + 25 + 49
|τ| = √195 ; x = 195
New answer posted
a month agoNew answer posted
a month agoContributor-Level 10
As Torque net = 0
Hence, L = constant
Iω = (3I + I)ω'
ω' = ω/4
Loss in K.E. = 1/2 Iω² - 1/2 (I + 3I)ω²/16 = 1/2 Iω² (1 - 1/4)
Fractional loss = (3/4 * 1/2 Iω²)/ (1/2 Iω²) = 3/4
New answer posted
a month agoContributor-Level 10
(n)λ = 5
(n, m): Integers
(2m+1)/2)λ = 3/2
⇒ (3/2)/5 = (2m+1)/ (2n)
⇒ 3n = 10m + 5
N, m are integers.
So, m = 1, n = 5, λ = 1
m = 4, n = 15, λ = 1/3
m = 7, n = 25, λ = 1/5
New answer posted
a month agoContributor-Level 10
Frequency of collisions = 1/T = Vavg/λ = 600/ (3 * 10? ) = 2 * 10? sec? ¹
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