physics ncert solutions class 11th
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New answer posted
a month agoContributor-Level 10
Average speed
(d) Initial velocity
Final velocity
Change in velocity
Momentum gain is along
Force experienced is along
Force experienced is in North-East direction.
New answer posted
a month agoContributor-Level 10
|Δp| = 2mu sinθ = 2 * 5 * 10? ³ * 5√2 * (1/√2) = 5 * 10? ² kg m s? ¹
⇒ x = 5
New answer posted
a month agoContributor-Level 10
v_rms = √ (3RT/M) and v_av = √ (8RT/πM)
⇒ v_rms / v_av = √ [ (3RT/M) / (8RT/πM)] = √ (3π/8)
New answer posted
a month agoContributor-Level 10
μ_min = (I tanθ)/ (I + mR²)
= [ (mR²/2)tanθ] / [mR²/2 + mR²] = (tanθ)/3 = (tan 60°)/3 = √3/3 = 1.732/3 = 0.5773
Since given coefficient of static friction is less than μ_min, so body will perform rolling with slipping and kinetic friction will act
F? = μN = μmg cosθ = (0.4) * mg cos 60° = mg/5
New answer posted
a month agoContributor-Level 10
4t = 100 * (4/3)π * (40π * 10? * 0.01)³
t = 2.5 * 10? ¹¹ cm = 2.5 * 10? ¹³ m
New answer posted
a month agoContributor-Level 9
According to principle of equi-partition of Energy, the average energy per molecules associated with each degree of freedom is (1/2)kT.
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