Physics Ncert Solutions Class 12th

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New answer posted

5 months ago

0 Follower 13 Views

A
alok kumar singh

Contributor-Level 10

2SO? (g) + O? (g)? 2SO? (g)
t=0: 250 m bar 750 m bar -
0 625 m bar 2 x 250 = 500
P_total = 625 + 250m bar
= 875mbar

New answer posted

5 months ago

0 Follower 3 Views

V
Vishal Baghel

Contributor-Level 10

z² * (13.6) (1 - ¼) = 3 * (13.6)
z = 2 . (i)
h/√2mk? = (1/2.3) * h/√2mk?
=> k? = (2.3)²k? = 5.25k? (ii)
Now, k? = E? - Φ
k? = E? - Φ = z²E? - Φ
∴ k? /k? = (10.2 - Φ)/ (4 * 10.2 - Φ) = 1/5.25
=> Φ = 3eV

New answer posted

5 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

M = φ? /I? = (B? A? )/I? = [ (μ? I? /2R? )πR? ²]/I?
[Diagram of two concentric coils]
M = (μ? πR? ²)/ (2R? )
M ∝ R? ²/R?

New answer posted

5 months ago

0 Follower 1 View

R
Raj Pandey

Contributor-Level 9

Kindly consider the following Image 

 

New answer posted

5 months ago

0 Follower 5 Views

A
alok kumar singh

Contributor-Level 10

Q = ω? L/R ⇒ Δω = R/L = 50/4 = 8rad/sec
Δω
ω? = 1/√LC = 1/√ (5*80*10? ) = 50rad/sec
ω? = ω? - Δω/2 = 46rad/sec
ω? = ω? + Δω/2 = 54rad/sec

New answer posted

5 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

M? = (√3/4 a²)I * 4 = √3I² no. of turns = 4
M? = a²I * 3 = 3Ia² no. of turns = 3

New answer posted

5 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

220 * i? = 44
⇒ I? = 44/220 = 1/5 = 0.2 A

New answer posted

5 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

Y = A·B + B·C
(i) o to t? A = 0, B = 0, C = 1
(ii) Y = 0.0 + 0.1 = 0 + 1 = 1
(ii) t? to t? A = 1, B = 0, C = 1 Y = 1.0 + 0.1 = 0 + 1 = 1
(iii) t? to t? A = 0, B = 1, C = 0 Y = 0.1 + 0.1 = 0 + 1 = 1

New answer posted

5 months ago

0 Follower 3 Views

A
alok kumar singh

Contributor-Level 10

E = ½CV²
= ½ (ε? A/d)Ed²
= ½ε? E²Ad

New answer posted

5 months ago

0 Follower 2 Views

A
alok kumar singh

Contributor-Level 10

Kindly go through the solution

 

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